/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A book designer has decided that... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A book designer has decided that the pages of a book should have 1 -in. margins at the top and bottom and \(\frac{1}{2}\) -in. margins on the sides. She further stipulated that each page should have an area of 50 in. \(^{2}\). Find a function in the variable \(x\), giving the area of the printed page. What is the domain of the function?

Short Answer

Expert verified
The area function for the printed page is \(A(x) = x\left(\frac{50}{x + 1} - 2\right)\), with the domain of \(x > 0\).

Step by step solution

01

Defining the Variables and relationships between them

Assume that the width of the printed page is \(x\) inches. The width of the whole book page, including margins on both sides, would then be \(x + 2\cdot\frac{1}{2} = x + 1\) inches. Let the length of the printed page be \(y\) inches. The total length of the book page would then be \(y + 2\cdot1 = y + 2\) inches. Given the total area of the book page, we have the equation: \[(x + 1)(y + 2) = 50\]
02

Find the function A(x)

We need to express the area of the printed page in terms of \(x\). We define \(A(x) = x \cdot y\). To find \(y\) in terms of \(x\), we need to solve the equation \((x + 1)(y + 2) = 50\) for \(y\): \[\begin{aligned} y + 2 &= \frac{50}{x + 1} \end{aligned}\] Subtracting 2 from both sides of the equation gives: \[\begin{aligned} y &= \frac{50}{x + 1} - 2 \end{aligned}\] Now we can express the area of the printed page A(x) as: \[\begin{aligned} A(x) &= x \cdot y \\ A(x) &= x\left(\frac{50}{x + 1} - 2\right) \end{aligned}\]
03

Find the domain of the function A(x)

For the function A(x) to be valid, its domain would include all real numbers that give a valid book page length and width (positive dimensions). The printed page width \(x\) must be positive, so \(x > 0\). Also, the total page width \(x+1\) cannot be equal to zero, which means that \(x\) cannot be equal to \(-1\). However, since we already constrained \(x > 0\), the latter condition is automatically met. As for the printed page length \(y\), as stated in step 1, \(y = \frac{50}{x + 1} - 2\), and we must ensure that the denominator is always positive so that the length remains positive. Since \(x > 0\), the denominator \(x + 1 > 0\), making the length \(y\) also positive. Therefore, the domain of the function A(x) is given by: \[x > 0\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function and Variable Relationships

Understanding the relationships between functions and variables is central to solving many applied mathematics problems. Functions allow us to represent complex relationships in simple terms by relating an input, usually a variable, to an output, which can be a numerical value, another variable, or an expression containing variables.


In our exercise, a function has been created to relate the width of the printed page (\(x\)) to the area of that page (\(A(x)\)). The relationship established here is direct: as the width changes, the area is dynamically recalculated according to the function. Such functions serve as models that simulate various scenarios, helping one predict outcomes and make decisions accordingly - such as adjusting the page size while ensuring the area stays the same.


  • A function can represent direct or inverse relationships between variables.
  • Functions are tools for modeling real-world scenarios mathematically.
  • The proper choice of variables simplifies the establishment of these relationships.

In our case, as the width of the printed page varies, the equation \(A(x) = x \times \text{length}\) changes dynamically, showing a direct relationship between page width and area.

Domain of a Function

The domain of a function represents all the possible input values (or 'x' values in a two-dimensional space) that the function can accept to produce a real, defined outcome. When considering the domain, we focus on the limitations that certain operations within the function impose on the values we can plug into it.


In finding the domain for our book design problem, we need to consider the physical interpretation of the variable values. Here the width (\(x\text{ inches}\text{ width}\)) of the printed page must be a positive number since a negative or zero width does not make sense for a physical object. We also have to ensure that when substituting these values into our function, we do not encounter mathematical impossibilities like division by zero. Consequently, we exclude values that make the denominator in any fraction within the function zero.


  • The function's domain includes all the real numbers that result in a physically meaningful and mathematically valid output.
  • Real-world constraints often influence the domain of a function.
  • Excluding values that do not make physical or mathematical sense is critical in defining the domain.

In summary, these considerations ensure the function accurately reflects the possible sizes of printed pages without running into mathematical errors or nonsensical physical dimensions.

Area Calculation

Calculating the area is a fundamental part of many mathematical applications, particularly in geometry. Area signifies the size of a two-dimensional surface within a set of boundaries. It's measured in square units, such as square inches (\( \text{in}^2 \text{ area is calculated}\)) in our exercise example.


For our book designer's problem, the calculation starts with the recognition that the total area of the book page is constrained to 50 square inches. However, this is not solely the printable area since we must subtract the portions taken up by the margins. Thus, we employ algebra to express the printable area as a function of the width variable (\(x\)) after considering the margins.


  • Area is an essential concept for understanding spatial relationships.
  • Real-world context and constraints influence how we calculate area.
  • Algebra can help express area in terms of a variable, aiding in optimization and planning.

In conclusion, by establishing a function for area regarding the printed page's width, we can determine suitable dimensions that satisfy the design requirements and maintain functionality.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

DECISION ANALYSIS A product may be made using machine I or machine II. The manufacturer estimates that the monthly fixed costs of using machine I are \(\$ 18,000\), whereas the monthly fixed costs of using machine II are \(\$ 15,000\). The variable costs of manufacturing 1 unit of the product using machine I and machine II are \(\$ 15\) and \(\$ 20\), respectively. The product sells for \(\$ 50\) each. a. Find the cost functions associated with using each machine. b. Sketch the graphs of the cost functions of part (a) and the revenue functions on the same set of axes. c. Which machine should management choose in order to maximize their profit if the projected sales are 450 units? 550 units? 650 units? d. What is the profit for each case in part (c)?

A workcenter system purchased at a cost of \(\$ 60,000\) in 2007 has a scrap value of \(\$ 12,000\) at the end of 4 yr. If the straight-line method of depreciation is used, a. Find the rate of depreciation. b. Find the linear equation expressing the system's book value at the end of \(t\) yr. c. Sketch the graph of the function of part (b). d. Find the system's book value at the end of the third year.

Find the vertex, the \(x\) -intercepts (if any), and sketch the parabola. \(f(x)=\frac{3}{8} x^{2}-2 x+2\)

Find the vertex, the \(x\) -intercepts (if any), and sketch the parabola. \(f(x)=-4 x^{2}+4 x+3\)

For the supply equations in Exercises 27 and 28, where \(x\) is the quantity supplied in units of a thousand and \(p\) is the unit price in dollars, (a) sketch the supply curve and (b) determine the price at which the supplier will make 2000 units of the commodity available in the market. \(p=2 x^{2}+18\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.