/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Find an equation of the line tha... [FREE SOLUTION] | 91Ó°ÊÓ

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Find an equation of the line that passes through the given points. $$ (1,2) \text { and }(-3,-2) $$

Short Answer

Expert verified
The equation of the line that passes through the points (1,2) and (-3,-2) is \(y = x + 1\).

Step by step solution

01

Find the slope of the line.

To find the slope of the line that passes through the given points \((1, 2)\) and \((-3, -2)\), we will use the formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\) where \(m\) is the slope, and \(x_1, y_1\) and \(x_2, y_2\) are the coordinates of the two given points. In our case, we have \(x_1 = 1\), \(y_1 = 2\), \(x_2 = -3\), and \(y_2 = -2\). Plugging in these values, we get: \(m = \frac{-2 - 2}{-3 - 1} = \frac{-4}{-4} = 1\)
02

Use the point-slope form.

Now that we have the slope \(m = 1\), we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is given by: \(y - y_1 = m(x - x_1)\) We can use either of the given points for our calculation, so let's use the point \((1, 2)\). Plugging the values into the equation, we get: \(y - 2 = 1(x - 1)\)
03

Simplify the equation.

Now let's simplify the equation we obtained in step 2 by distributing the slope on the right side and solving for \(y\): \(y - 2 = 1(x - 1)\) \(y - 2 = x - 1\) \[y = x + 1\] So, the equation of the line passing through the given points is \(y = x + 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Formula

Understanding the slope of a line is fundamental in algebra and coordinate geometry. The slope is a measure of how steep a line is and is represented by the letter m. Mathematically, the slope is calculated using the following formula:

\(m = \frac{y_2 - y_1}{x_2 - x_1}\)

This is known as the slope formula. Here, \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of any two points on a line. By subtracting the y-coordinates and dividing by the difference in the x-coordinates, we determine the rate at which the line rises (or falls) as it moves from left to right. Positive slopes indicate lines that incline upwards, whereas negative slopes point to lines that decline. If the slope is zero, the line is horizontal, and undefined slopes belong to vertical lines.

To make this concept easier to grasp, think of the slope as a fraction. The numerator tells you the change in vertical distance (rise), while the denominator tells you the change in horizontal distance (run). A higher slope value indicates a steeper line.

For the exercise above, the calculation yielded a slope (m) of 1, which means for every unit the line moves horizontally to the right, it also moves one unit up.

Point-Slope Form

The point-slope form is an equation of a line that uses its slope and any point on the line. The general equation is as follows:


\(y - y_1 = m(x - x_1)\)

In this equation, m denotes the slope of the line, and \((x_1, y_1)\) represents the coordinates of a known point on the line. This form is particularly useful when you're given a point and a slope, and you need to write the equation of the line.

For instance, in the provided exercise, after determining the slope to be 1 using the slope formula, we applied the point-slope form with the point (1, 2). After substituting the values into the formula, we achieved the equation \(y - 2 = 1(x - 1)\), which can be simplified further. This method is a reliable way to quickly generate the linear equation without needing to plot points or visualize the graph.

To improve the exercise, let's emphasize that the point selected (1, 2) could have been either of the given points. Choosing different points on the same line to apply the point-slope form will result in equivalent equations, which, when simplified, will show the same relationship between x and y.

Linear Equations

Linear equations form the backbone of algebra and are the focus of much study in mathematics due to their direct relationship between variables. These equations represent lines on a coordinate plane and can be identified by their straight-line graphs. A linear equation in two variables like x and y generally looks like:


\(y = mx + b\)

Here, m represents the slope of the line, and b is the y-intercept, which is the point where the line crosses the y-axis. The equation provided in the exercise solution, \(y = x + 1\), is in the slope-intercept form, which is one of the simplest forms of a linear equation. The slope here is 1, which means the line goes up one unit for every unit it moves to the right. The y-intercept is 1, indicating the line crosses the y-axis at the point (0,1).

Linear equations are essential in various real-world applications such as physics for describing motion, in economics to calculate cost functions, or in any discipline that requires a relationship between two variables to be determined or used for predictions. Breaking down linear equations and understanding their components helps students to solve various problems not only graphically but also algebraically.

To ensure students fully grasp this concept, it's important to highlight that any form of a linear equation, whether it's point-slope, slope-intercept, or standard form (Ax + By = C), essentially describes the same same line on a graph, just expressed in different ways. This understanding allows for versatility and adaptability in solving and interpreting linear equations.

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Most popular questions from this chapter

In 2005, National Textile installed a new machine in one of its factories at a cost of \(\$ 250,000\). The machine is depreciated linearly over 10 yr with a scrap value of \(\$ 10,000\). a. Find an expression for the machine's book value in the \(t\) th year of use \((0 \leq t \leq 10)\). b. Sketch the graph of the function of part (a). c. Find the machine's book value in 2009 . d. Find the rate at which the machine is being depreciated.

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