/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Find the second-order partial de... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the second-order partial derivatives of the function. In each case, show that the mixed partial derivatives \(f_{x y}\) and \(f_{y x}\) are equal. \(f(x, y)=\sqrt{x^{2}+y^{2}}\)

Short Answer

Expert verified
The second-order partial derivatives of the function \(f(x, y) = \sqrt{x^2 + y^2}\) are as follows: \(f_{xx} = \frac{y^2}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{yy} = \frac{x^2}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{xy} = f_{yx} = -\frac{xy}{(x^2+y^2)^{\frac{3}{2}}}\) The mixed partial derivatives \(f_{xy}\) and \(f_{yx}\) are equal, confirming that the function satisfies Clairaut's theorem.

Step by step solution

01

Calculate first-order partial derivatives

First, find the first-order partial derivatives of the function \(f(x, y)=\sqrt{x^{2}+y^{2}}\) with respect to x and y: \(f_x = \frac{\partial f}{\partial x} = \frac{x}{\sqrt{x^2+y^2}}\) \(f_y = \frac{\partial f}{\partial y} = \frac{y}{\sqrt{x^2+y^2}}\)
02

Calculate second-order partial derivatives

Now, compute the second-order partial derivatives, using the previously calculated first-order partial derivatives: \(f_{xx} = \frac{\partial f_x}{\partial x} = \frac{y^2}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{yy} = \frac{\partial f_y}{\partial y} = \frac{x^2}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{xy} = \frac{\partial f_x}{\partial y} = -\frac{xy}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{yx} = \frac{\partial f_y}{\partial x} = -\frac{xy}{(x^2+y^2)^{\frac{3}{2}}}\)
03

Compare mixed partial derivatives

We can now compare the mixed partial derivatives \(f_{xy}\) and \(f_{yx}\): \(f_{xy} = -\frac{xy}{(x^2+y^2)^{\frac{3}{2}}}\) \(f_{yx} = -\frac{xy}{(x^2+y^2)^{\frac{3}{2}}}\) Since \(f_{xy}\) and \(f_{yx}\) are equal, we conclude that the mixed partial derivatives of the function \(f(x, y)=\sqrt{x^{2}+y^{2}}\) are equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial derivatives
When studying functions of two variables, also known as a multi-variable function, it's essential to understand how each variable influences the function independently. This is where partial derivatives come into play.
A partial derivative of a function with respect to one variable, say x, while keeping the other variable, y, constant, shows how the function changes as x changes. The same applies when differentiating with respect to y.
Consider the function given in the problem, \(f(x, y) = \sqrt{x^{2} + y^{2}}\). To find the partial derivative with respect to x, denoted as \(f_x\), we treat y as a constant and differentiate with respect to x. The result, \(f_x = \frac{x}{\sqrt{x^{2} + y^{2}}}\), tells us how \(f(x, y)\) changes as x varies.
Similarly, the partial derivative with respect to y, \(f_y = \frac{y}{\sqrt{x^{2} + y^{2}}}\), indicates how the function changes as y changes. By understanding these first-order derivatives, we lay the groundwork for analyzing more complex behaviors in the function.
Mixed partial derivatives
Once the first-order partial derivatives are determined, the next step is to explore second-order partial derivatives. These include mixed partial derivatives, which are derivatives taken with respect to different variables.
In our case, the mixed partial derivatives are denoted as \(f_{xy}\) and \(f_{yx}\), representing differentiation first with respect to x and then y, and first with respect to y and then x, respectively.
When calculating these mixed derivatives for the function \(f(x,y) = \sqrt{x^{2} + y^{2}}\), we have \(f_{xy} = -\frac{xy}{(x^{2} + y^{2})^{\frac{3}{2}}}\) and \(f_{yx} = -\frac{xy}{(x^{2} + y^{2})^{\frac{3}{2}}}\).
It turns out that these two derivatives are equal. This equality indicates that the order of differentiation does not affect the result, a property that typically holds true for smooth functions and is important in ensuring the behavior of functions is consistent across variable changes.
Function of two variables
A function of two variables is a mathematical construct where each output value is determined by two input variables, say x and y. In the context of our problem, the function \(f(x, y) = \sqrt{x^{2} + y^{2}}\) is such a function.
These functions can be visualized as surfaces in three-dimensional space with the x and y axes marking the input variables and the z-axis representing the function's value or output. This visualization is useful for conceptualizing the properties and changes captured by partial derivatives.
Understanding how the function behaves is essential for many areas in mathematics, physics, and engineering. It allows us to predict changes and reactions with respect to each input variable, especially when modeling real-world phenomena.
By analyzing the partial and mixed partial derivatives, we delve deeper into understanding not just isolated changes in one direction, but how interactions between variables can affect the overall behavior and shape of the function in space.

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