/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Find the indefinite integral. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the indefinite integral. \$$\int\left(\sqrt{x}+\frac{3}{x}-2 e^{x}\right) d x$$

Short Answer

Expert verified
\[\int\left(\sqrt{x}+\frac{3}{x}-2 e^{x}\right) \, dx = \frac{2}{3}x^{\frac{3}{2}} + 3\ln |x| - 2e^{x} + C\]

Step by step solution

01

Integrate the square root term

To integrate the square root term, recall that \(\sqrt{x} = x^{\frac{1}{2}}\). So, we have: \[\int \sqrt{x} \, dx = \int x^{\frac{1}{2}} \, dx\] Now, use the power rule for integration, which states that \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\), where n is a constant and C is the integration constant: \[\int x^{\frac{1}{2}} \, dx = \frac{x^{\frac{1}{2} + 1}}{\frac{1}{2} + 1} + C = \frac{2}{3}x^{\frac{3}{2}} + C_1\]
02

Integrate the reciprocal term

To integrate the reciprocal term, consider: \[\int \frac{3}{x} \, dx = 3\int \frac{1}{x} \, dx\] Recall that the integral of \(\frac{1}{x}\) with respect to x is the natural logarithm, \(\ln |x|\): \[3\int \frac{1}{x} \, dx = 3\ln |x| + C_2\]
03

Integrate the exponential term

To integrate the exponential term, notice that the derivative of \(e^x\) with respect to x is \(e^x\). So, the integral of the given exponential term is: \[\int -2e^{x} \, dx = -2\int e^{x} \, dx = -2e^{x} + C_3\]
04

Combine the individual integrals

Now that we have integrated each term, we will combine them into a single integral. The indefinite integral of the given function is the sum of the three integrals we calculated above: \[\int\left(\sqrt{x}+\frac{3}{x}-2 e^{x}\right) \, dx = \frac{2}{3}x^{\frac{3}{2}} + 3\ln |x| - 2e^{x} + C\] Where \(C = C_1 + C_2 + C_3\) is the constant of integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Integration
When you encounter a function like \(x^{n}\) in an integral, the Power Rule for Integration is your go-to tool. This rule is particularly helpful when you're dealing with polynomials or any function where the variable is raised to a constant power. It states that if you want to integrate \(x^n\), you increase the power by 1 and then divide by the new power. A key element to remember is the constant of integration, \(C\), which accounts for any constant term that could be present in the original function.
For example, if you are given \(\int x^{\frac{1}{2}} \, dx\), you would add 1 to \(\frac{1}{2}\), making it \(\frac{3}{2}\). Then, divide by \(\frac{3}{2}\), leaving you with \(\frac{2}{3}x^{\frac{3}{2}} + C\). It's crucial to apply this rule carefully, ensuring you only use it when \(n eq -1\), as this is the point where the integration technique changes, often leading to logarithmic integration instead.
  • As simple as it is, the Power Rule is foundational for integration.
  • Always add the constant of integration (\(C\)) to your final answer.
  • The Power Rule is not applicable when \(n\) equals \(-1\); this is where the logarithm comes in.
Natural Logarithm Integration
The Natural Logarithm Integration technique is essential whenever you encounter an integral of the form \(\int \frac{1}{x} \, dx\). The result of this integral is \(\ln |x| + C\), where \(\ln\) represents the natural logarithm, which is the logarithm to the base \(e\).
Why does this happen? It's deeply connected to the derivative of the natural logarithm. The derivative of \(\ln |x|\) is \(\frac{1}{x}\), which means integration reverses this process.
Consider any function that simplifies to \(\frac{1}{x}\). Multiplying constants outside the integral directly changes the magnitude of the natural logarithm term, yet not its natural form.
This can come into play when simplifying rational functions, particularly when handling terms where the numerator is merely a constant.
  • It's particular to functions of the form \(\int \frac{1}{x} \, dx\).
  • Think of integration as reverse differentiation.
  • Natural Logarithm Integration handles cases where Power Rule can't, specifically \(n = -1\).
Exponential Function Integration
Exponential functions have a unique place in calculus due to their consistent derivative and integral - both are \(e^x\) for the base of natural logarithms, "e". This distinct property simplifies the process of integration and differentiation involving exponential functions. If you see a term like \(e^{x}\), you're in luck; its integral is directly \(e^{x} + C\).
When handling integrals involving exponential functions multiplied by constants, simply integrate as usual and then multiply the result by that constant. For instance, \(\int -2e^{x} \, dx\) integrates to \(-2e^{x} + C\), reflecting the constant’s effect on the integral's magnitude without altering its form.
Exponential Function Integration is powerful. It finds real-world applications in modeling growth or decay processes due to how naturally exponential functions describe such phenomena.
  • Exponential functions integrate to themselves with a constant, \(C\).
  • They can model natural growth or decay.
  • Integration and differentiation of exponential functions are simpler than for other functions.

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Most popular questions from this chapter

Based on a preliminary report by a geological survey team, it is estimated that a newly discovered oil field can be expected to produce oil at the rate of $$ R(t)=\frac{600 t^{2}}{t^{3}+32}+5 \quad(0 \leq t \leq 20) $$ thousand barrels/year, \(t\) yr after production begins. Find the amount of oil that the field can be expected to yield during the first 5 yr of production, assuming that the projection holds true.

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