Chapter 11: Problem 22
Find the indefinite integral. $$\int e^{2 t+3} d t$$
Short Answer
Expert verified
The short answer for the indefinite integral of the given function is: \(\int e^{2 t+3} d t = \frac{1}{2} e^{2t+3} + C\).
Step by step solution
01
Identify substitution
To find the indefinite integral of the given function, we will use the substitution method. Let \(u = 2t + 3\). Then, we will differentiate both sides with respect to \(t\) to find \(du\).
02
Differentiate the substitution
We differentiate both sides of \(u = 2t + 3\):
\[\frac{d u}{d t} = \frac{d(2t + 3)}{d t}\]
Now, solve for \(du\):
\[\frac{d u}{d t} = 2\]
\[du = 2 dt\]
03
Replace variables and simplify
Now we substitute \(u\) and \(du\) into our integral:
\[\int e^{2t+3} dt = \int e^u \cdot \frac{du}{2}\]
Now, multiply by 1/2 to separate the constant:
\[\frac{1}{2} \int e^u du\]
04
Find the integral
Now the integral is in an easily solvable form:
\[\frac{1}{2} \int e^u du = \frac{1}{2} (e^u + C)\]
05
Substitute back the original variable
Now we just need to replace \(u\) with our original expression, \(2t + 3\):
\[\frac{1}{2} (e^{2t+3} + C)\]
06
Write the final answer
Writing the final answer in terms of \(t\):
\[\int e^{2 t+3} d t = \frac{1}{2} e^{2t+3} + C\]
Our final answer for the indefinite integral of the given function is:
\[\frac{1}{2} e^{2t+3} + C\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful tool used for integrating functions. It simplifies complex integrals into more manageable forms, which are easier to solve. In our example, we're working with the integral \( \int e^{2t+3} dt \). Here, the expression \( 2t + 3 \) looks a bit tricky to integrate directly with respect to \( t \). That's where substitution comes into play.
We start by letting \( u = 2t + 3 \), which means we are substituting the complicated part with a single variable, \( u \). This effectively transforms our integral into something simpler, \( \int e^u du \).
We start by letting \( u = 2t + 3 \), which means we are substituting the complicated part with a single variable, \( u \). This effectively transforms our integral into something simpler, \( \int e^u du \).
- Transform the variable: Identify a part of the expression (usually inside another function, like an exponent) that can be substituted.
- Differentiation: Use differentiation to express \( dt \) in terms of \( du \).
- Simplify the integral: Replace the original variable with the substitution to simplify the integral.
Differentiation
Differentiation is the process of finding the derivative of a function. We use it in the substitution method to relate the differentials of variables. In our example, after setting \( u = 2t + 3 \), the next step is to find \( du \).
This involves differentiating \( u = 2t + 3 \) with respect to \( t \). The derivative \( \frac{du}{dt} = 2 \) is found by applying basic differentiation rules. This results in \( du = 2 \, dt \), providing the differential terms we need to integrate.
This involves differentiating \( u = 2t + 3 \) with respect to \( t \). The derivative \( \frac{du}{dt} = 2 \) is found by applying basic differentiation rules. This results in \( du = 2 \, dt \), providing the differential terms we need to integrate.
- The derivative of \( 2t + 3 \) shows how \( u \) changes as \( t \) changes.
- Helps in converting \( dt \) to \( du \) or vice versa.
- Makes the substitution process smooth and correct.
Exponential Function
The exponential function, particularly \( e^x \), frequently appears in calculus due to its unique properties. It's essential to understand why \( \int e^x \, dx = e^x + C \). This forms the foundation for solving integrals involving exponential functions.
The function \( e^{2t+3} \) in the integral \( \int e^{2t+3} dt \) can initially seem complex. However, once you apply the substitution method, the task simplifies to integrating \( e^u \). The simplicity of the exponential function allows this operation to be straightforward:
The function \( e^{2t+3} \) in the integral \( \int e^{2t+3} dt \) can initially seem complex. However, once you apply the substitution method, the task simplifies to integrating \( e^u \). The simplicity of the exponential function allows this operation to be straightforward:
- The property \( \frac{d}{dx} e^x = e^x \) impacts how we integrate it.
- Exponential functions maintain their form after integration, with only a constant factor changing.
- Perfect for substitution as transforming doesn't change the overall form of the expression.