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Find the relative extrema, if any, of each function. Use the second derivative test, if applicable. $$ f(x)=2 x^{3}+1 $$

Short Answer

Expert verified
The function \(f(x) = 2x^3 + 1\) has one critical point at x = 0. However, the second derivative test is inconclusive at this point, as \(f''(0) = 0\). Therefore, we cannot determine the relative extrema of the function.

Step by step solution

01

Compute the first derivative and find critical points

First, we need to find the derivative of the given function with respect to x: \[f'(x) = \frac{d}{dx}(2x^3 + 1)\] Using the power rule for differentiation, we obtain: \[f'(x) = 6x^2\] To find the critical points, we set the first derivative equal to zero and solve for x: \[6x^2 = 0\] \[x^2 = 0\] \[x = 0\] So, there is only one critical point, which is x = 0.
02

Compute the second derivative and evaluate at the critical point

Now, we need to find the second derivative of the given function with respect to x: \[f''(x) = \frac{d^2}{dx^2}(2x^3 + 1)\] Further differentiating the first derivative, we obtain: \[f''(x) = 12x\] Now, we'll evaluate the second derivative at the critical point x = 0: \[f''(0) = 12(0) = 0\]
03

Use the second derivative test to determine the relative extrema

According to the second derivative test: - If \(f''(x) > 0\) for a critical point x, the function has a relative minimum at that point. - If \(f''(x) < 0\) for a critical point x, the function has a relative maximum at that point. - If \(f''(x) = 0\) for a critical point x, the test is inconclusive, and we cannot determine whether the function has a relative extrema at that point or not. Since the second derivative at the critical point x = 0 is equal to 0, the second derivative test is inconclusive, and we cannot determine the relative extrema of the function \(f(x) = 2x^3 + 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second Derivative Test
The Second Derivative Test is a handy tool in calculus that helps us determine whether a function's critical point is a relative maximum, minimum, or neither. Let's get a bit more familiar with this test. When the first derivative of a function equals zero at a point, that point is referred to as a critical point. To classify this critical point, we use the second derivative. Here's how it works:

If the second derivative at a critical point is positive (( f''(x) > 0 )), it indicates that the function is concave up at that point, resembling a 'U' shape, which indicates a relative minimum. Conversely, if the second derivative is negative (( f''(x) < 0 )), it suggests the function is concave down, resembling an upside-down 'U', signifying a relative maximum. However, if the second derivative equals zero (( f''(x) = 0 )), the test is inconclusive. This is precisely what happened with the function ( f(x) = 2x^3 + 1 ). Since ( f''(0) = 0 ), we cannot say for certain if there's a relative max or min at ( x = 0 ). Additional analysis or tests would be needed to draw further conclusions.
Critical Points
Critical points play a pivotal role in understanding the behavior of functions. These are the points on the graph where the function's first derivative is either zero or undefined, potentially indicating a relative maximum, minimum, or point of inflection. Finding them is an essential step towards sketching the function's graph and analyzing its behavior. When solving for critical points, as in our exercise, you set the first derivative equal to zero and solve for ( x ). Here, in the function ( f(x) = 2x^3 + 1 ), the critical point was found at ( x = 0 ) after setting the first derivative ( f'(x) = 6x^2 ) to zero. Remember, not all critical points will lead to relative extrema, but they are great indicators of where to search for them.
Power Rule for Differentiation
The Power Rule is one of the fundamental rules of differentiation used in calculus. It simplifies the process of finding the derivative for terms raised to a power. According to the Power Rule, if you have a function ( f(x) = ax^n ), where ( a ) is a constant and ( n ) is a real number, the derivative of that function with respect to ( x ) is ( f'(x) = n * ax^{n-1} ). This rule was applied when finding the first derivative of the given function ( f(x) = 2x^3 + 1 ), which resulted in ( f'(x) = 6x^2 ), and indeed later to find the second derivative. As simple as it is powerful, the Power Rule is a tool that streamlines finding derivatives – a fundamental skill for solving more complex problems in calculus.

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Most popular questions from this chapter

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