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Determine where the function is concave upward and where it is concave downward. $$ f(x)=\frac{x+1}{x-1} $$

Short Answer

Expert verified
The function is concave upward on the interval \((1,+\infty)\) and concave downward on the interval \((-∞,1)\).

Step by step solution

01

Find the first derivative

To find the first derivative, we'll use the quotient rule (since our function is a rational function), which states that for a function \(\frac{u}{v}\), the derivative is given by \(\frac{u'v-uv'}{v^2}\): Given function: \(f(x)=\frac{x+1}{x-1}\) Let \(u=x+1\) and \(v=x-1\), then: \(u'=1\) and \(v'=1\) Now we apply the quotient rule: \(f'(x)=\frac{1(x-1)-(x+1)1}{(x-1)^2}\) Simplify: \(f'(x)=\frac{x-1-x-1}{(x-1)^2} = -\frac{2}{(x-1)^2}\)
02

Find the second derivative

To find the second derivative, we'll differentiate the first derivative with respect to x. To do that, we can use the power rule: Given first derivative: \(f'(x)=-\frac{2}{(x-1)^2}\) Let \(u=(x-1)^{-2}\), then \(u'=-2(x-1)^{-3}\). Now we apply the power rule: \(f''(x) = -2(-2(x-1)^{-3}) = 4(x-1)^{-3}\)
03

Determine concave intervals

Now that we have the second derivative, we can use it to analyze concavity. The concave up and concave down intervals are determined by the signs of \(f''(x)\): \(f''(x) = 4(x-1)^{-3}\) Since the exponent is -3, and 4 is always positive, the concavity is determined solely by the sign of (x-1). \(f''(x) > 0\) (concave upward) if \(x > 1\) \(f''(x) < 0\) (concave downward) if \(x < 1\) We cannot evaluate the second derivative at \(x=1\) because it would cause division by zero. Therefore, we don't include this point in our analysis.
04

Write the answer

The function is concave upward on the interval \((1,+\infty)\) and concave downward on the interval \((-∞,1)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concave Upward
Understanding the concept of concavity in functions helps in visualizing the shape of the graph. When we describe a function as being concave upward, imagine it as being shaped like a cup that can hold water. This part of the graph shows where the function's rate of change is increasing. The formal way to determine if a function is concave upward is to look at the second derivative of the function.

If the second derivative is positive over a certain interval, then the function is concave upward on that interval. In the context of our function, \(f(x)=\frac{x+1}{x-1}\), the second derivative, \(f''(x)\), came out to be positive when \(x > 1\). Thus, the curve is concave upward on the interval \( (1,+\text{∞})\).
Concave Downward
In contrast, a function is described as concave downward when it resembles the shape of an upside-down cup or a frown. During intervals where the function is concave downward, its rate of change is decreasing. To determine this concavity, we again refer to the second derivative of the function.

If the second derivative is negative, the function is concave downward over that interval. Referring back to our function \(f(x)=\frac{x+1}{x-1}\), \(f''(x)\) is negative when \(x < 1\). Hence, the curve is concave downward on the interval \( (-\text{∞}, 1)\). It’s crucial to note that the point where \(x=1\) is not included because it's a vertical asymptote for the function.
Second Derivative Test
The second derivative test is a handy tool used for determining the concavity of a function as well as identifying possible points of inflection—where the function changes concavity. This test involves taking the second derivative of a function, as we did with \(f''(x)\), and analyzing its sign.

A positive second derivative indicates the graph is concave upward, while a negative second derivative indicates concave downward. The second derivative also helps us conclude that for our function, there's a point of inflection at \(x=1\), where the function changes from being concave downward to concave upward. However, since the function is undefined at \(x=1\), it's a point we approach but do not include in our intervals.
Quotient Rule in Calculus
The quotient rule is a technique used to differentiate functions that are fractions of one another. For a function \(f(x) = \frac{u(x)}{v(x)}\), the quotient rule states that the derivative, \(f'(x)\), is \(\frac{u'(x)v(x) - u(x)v'(x)}{v(x)^2}\). It’s important that \(v(x)\) is not zero since division by zero is undefined.

In practice, like we've seen with our example function \(f(x)=\frac{x+1}{x-1}\), we differentiate the numerator and the denominator separately, then apply the quotient rule to get the first derivative \(f'(x)\). Understanding and applying the quotient rule is crucial for finding derivatives of rational functions and analyzing their properties, such as concavity.

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