Chapter 10: Problem 32
Determine where the function is concave upward and where it is concave downward. $$ f(x)=\sqrt[3]{x} $$
Short Answer
Expert verified
The function \(f(x) = \sqrt[3]{x}\) is concave upward when \(x < 0\) and concave downward when \(x > 0\).
Step by step solution
01
Find the first derivative of the function
The given function is \(f(x) = \sqrt[3]{x}\). We can rewrite it as \(f(x) = x^{\frac{1}{3}}\). To find the first derivative, we'll differentiate the function.
Using the power rule:
\(f'(x) = \frac{1}{3}x^{\frac{1}{3}-1}\)
Which simplifies to:
\(f'(x) = \frac{1}{3}x^{-\frac{2}{3}}\)
02
Find the second derivative of the function
Now, to find the concavity of the function, we need to find the second derivative. Differentiate the first derivative \(f'(x)\):
\(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\)
03
Determine the concavity of the function
The second derivative \(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\) helps us determine the concavity.
1. If \(f''(x) > 0\), the function is concave upward.
2. If \(f''(x) < 0\), the function is concave downward.
Since the second derivative has a negative coefficient \(-\frac{2}{9}\), and any \(x\) value in the exponent is also negative, this means:
1. When \(x > 0\), the exponent is negative, making the second derivative negative, so the function is concave downward.
2. When \(x < 0\), the exponent is negative, making the second derivative positive, so the function is concave upward.
Thus, the function is concave upward when \(x < 0\) and concave downward when \(x > 0\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First Derivative
The first derivative of a function gives us valuable information about the behavior of the function in terms of its rate of change. In our exercise, we're working with the function \(f(x) = \sqrt[3]{x}\), which can be rewritten as \(f(x) = x^{\frac{1}{3}}\). To determine how this function increases or decreases, we compute the first derivative using differentiation.
Applying the power rule, \(f'(x) = \frac{1}{3}x^{\frac{1}{3}-1}\), simplifies to \(f'(x) = \frac{1}{3}x^{-\frac{2}{3}}\). This derivative essentially tells us how steep the function is at any given point on the \(x\)-axis. Notice the negative exponent, which will affect the shape and direction of the graph as you move along the \(x\)-axis.
Applying the power rule, \(f'(x) = \frac{1}{3}x^{\frac{1}{3}-1}\), simplifies to \(f'(x) = \frac{1}{3}x^{-\frac{2}{3}}\). This derivative essentially tells us how steep the function is at any given point on the \(x\)-axis. Notice the negative exponent, which will affect the shape and direction of the graph as you move along the \(x\)-axis.
- Positive first derivative implies the function is increasing.
- Negative first derivative implies the function is decreasing.
Second Derivative
The second derivative provides insight into the concavity of a function, which essentially tells us how the function curves. After finding the first derivative \(f'(x) = \frac{1}{3}x^{-\frac{2}{3}}\), we proceed to find the second derivative.
Applying differentiation again, the second derivative becomes \(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\). This expression encompasses more information about the rate at which the slope \(f'(x)\) is changing.
Applying differentiation again, the second derivative becomes \(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\). This expression encompasses more information about the rate at which the slope \(f'(x)\) is changing.
- Positive second derivative: The function is concave upward.
- Negative second derivative: The function is concave downward.
Power Rule
The power rule is an essential tool in calculus for differentiating functions of the form \(x^n\). It states that the derivative of \(x^n\) is \(nx^{n-1}\), a simple yet powerful method used frequently.
For our function \(f(x) = x^{\frac{1}{3}}\), applying the power rule gives us \( \left(\frac{1}{3} \right)x^{\frac{1}{3} - 1} = \frac{1}{3}x^{-\frac{2}{3}}\). The rule helps simplify the differentiation process, allowing us to tackle more complex functions efficiently. Remember:
For our function \(f(x) = x^{\frac{1}{3}}\), applying the power rule gives us \( \left(\frac{1}{3} \right)x^{\frac{1}{3} - 1} = \frac{1}{3}x^{-\frac{2}{3}}\). The rule helps simplify the differentiation process, allowing us to tackle more complex functions efficiently. Remember:
- Identify the exponent \(n\).
- Multiply by \(n\) and reduce the exponent by one.
Concave Upward and Downward
Concavity describes how a function curves along the \(x\)-axis. In simpler terms, it tells us whether the graph of the function is shaped like a cup or an upside-down cup in specific intervals.
Using the second derivative \(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\), we determine:
Using the second derivative \(f''(x) = -\frac{2}{9}x^{-\frac{5}{3}}\), we determine:
- If \(f''(x) > 0\), the function is concave upward - similar to an upright cup.
- If \(f''(x) < 0\), the function is concave downward - more like an upside-down cup.