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Find the absolute maximum value and the absolute minimum value, if any, of each function. $$ g(x)=x^{3}+3 x^{2}-1 \text { on }[-3,1] $$

Short Answer

Expert verified
The absolute maximum value of the function \(g(x) = x^3 + 3x^2 - 1\) on the interval [-3, 1] is 3, occurring at \(x = -2\) and \(x = 1\). The absolute minimum value is -1, occurring at \(x = -3\) and \(x = 0\).

Step by step solution

01

Calculate the first derivative

We have the function \(g(x) = x^3 + 3x^2 - 1\). First, we need to find its derivative: $$ g'(x) = \frac{d}{dx}(x^3 + 3x^2 - 1) = 3x^2 + 6x $$
02

Set the first derivative equal to zero and solve

Now, we need to find the critical points by setting the first derivative equal to zero and solving for x: $$ 3x^2 + 6x = 0 $$ Factor out 3x: $$ 3x(x + 2) = 0 $$ So, we have two critical points at x = 0 and x = -2. Step 2: Evaluate the function at the critical points and endpoints
03

Evaluate the function at the critical points and endpoints

We have the critical points x = -2 and x = 0, and the interval is [-3, 1]. Let's evaluate the function at these points: $$ g(-3) = (-3)^3 + 3(-3)^2 - 1 = -27 + 27 - 1 = -1 $$ $$ g(-2) = (-2)^3 + 3(-2)^2 - 1 = -8 + 12 - 1 = 3 $$ $$ g(0) = (0)^3 + 3(0)^2 - 1 = -1 $$ $$ g(1) = (1)^3 + 3(1)^2 - 1 = 1 + 3 - 1 = 3 $$ Step 3: Compare the function values to determine the absolute maximum and minimum values
04

Compare the function values

We have the following function values: - g(-3) = -1 - g(-2) = 3 - g(0) = -1 - g(1) = 3 From these values, we can see that the absolute maximum value is 3, occurring at x = -2 and x = 1. And the absolute minimum value is -1, occurring at x = -3 and x = 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a fundamental branch of mathematics that focuses on change. It explores how things change and how quickly they do so. Calculus is divided into two main branches: differential calculus and integral calculus. Differential calculus deals primarily with the concept of the derivative which measures how a function changes as its input changes. On the other hand, integral calculus involves summing a function's values over a range, providing the total accumulation of quantities. In practical terms, calculus helps us understand the underlying patterns that drive changes in various contexts, ranging from physics to economics. Its tools enable us to analyze functions, find maxima and minima (such as in optimization problems), and understand limits and continuity.
Critical Points
Critical points are specific values of the variable in a function where the first derivative is zero or undefined. These points often indicate where the function could have a maximum, minimum, or saddle point. Finding critical points is crucial because they help identify potential extrema in a function. - When the derivative at a point is zero, the function might have a horizontal tangent, suggesting a peak (maximum) or a trough (minimum) at that point. - Critical points are typically calculated by setting the first derivative equal to zero and solving for the variable. - Understanding critical points is vital for solving problems where we need to determine the highest or lowest values a function can take on within a certain interval.
Derivatives
Derivatives are a key concept in calculus, representing the rate of change of a function with respect to its variable. For the function given in this exercise, the derivative \( g'(x) = 3x^2 + 6x \) was calculated. This expression tells us how quickly \( g(x) \) is changing at any point \( x \).- Derivatives help us find critical points by indicating where the slope of the tangent line to the function is zero.- The process of differentiation involves applying rules like the power rule, product rule, or chain rule to simplify complex functions into more manageable parts.- Understanding derivatives enables you to describe the behavior and trends within a function, making it easier to analyze and predict the function’s behavior across different domains.
Polynomial Functions
Polynomial functions like \( g(x) = x^3 + 3x^2 - 1 \) are algebraic expressions that consist of variables raised to whole number exponents. These functions can be simple or complex, depending on their degree, which is the highest exponent present in the expression.- The smooth curves of polynomial functions can exhibit various characteristics depending on their degree, such as how many turns they have and where they intersect the x-axis.- For this specific function, it is a cubic polynomial due to the \( x^3 \) term, indicating it may have up to three real roots.- Analyzing polynomial functions involves finding critical points, determining intervals of increase or decrease, and understanding their overall shape through key characteristics such as intercepts and degree. Polynomial functions are versatile and pop up in various mathematical and real-world applications.

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