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Show that the cubic function $$ f(x)=a x^{3}+b x^{2}+c x+d \quad(a \neq 0) $$ has no relative extremum if and only if \(b^{2}-3 a c \leq 0\).

Short Answer

Expert verified
A cubic function \(f(x) = ax^3 + bx^2 + cx + d\) with \(a \neq 0\) has no relative extremum if and only if \(b^2 - 3ac \leq 0\). We established this condition by analyzing the discriminant of the first derivative, \(f'(x) = 3ax^2 + 2bx + c\). If \(b^2 - 3ac \leq 0\), the derivative will not have real solutions, indicating no relative extrema in the cubic function.

Step by step solution

01

Finding First Derivative

To find the critical points of the function, we need to find its first derivative. Calculate the first derivative, \(f'(x)\), of the cubic function: $$ f(x) = ax^3 + bx^2 + cx + d $$ Applying the power rule, we get: $$ f'(x) = 3ax^2 + 2bx + c $$
02

Finding Critical Points of the Function

To find the critical points of the function, set \(f'(x)\) equal to zero: $$ 3ax^2 + 2bx + c = 0 $$ We are looking for x-values that satisfy the above equation. This is a quadratic equation in the form of \(Ax^2 + Bx + C = 0\), where \(A = 3a, B = 2b\), and \(C = c\). To determine if the equation has real solutions, we will use the discriminant formula: $$ \Delta = B^2 - 4AC $$ Here, we want to analyze if this quadratic equation has real zeros, which will serve as the critical points for the function's extremum.
03

Evaluating the Discriminant

Substitute the values of \(A, B\), and \(C\) into the discriminant formula: $$ \Delta = (2b)^2 - 4(3a)(c) $$ Simplify the discriminant: $$ \Delta = 4b^2 - 12ac $$ For a quadratic equation, there will be real solutions if \(\Delta > 0\), a repeated solution if \(\Delta = 0\), and no real solutions if \(\Delta < 0\). Since we are trying to prove the condition \(b^2 - 3ac \leq 0\) for the non-existence of relative extrema, let's rewrite the discriminant inequality in the form we need: $$ b^2 - 3ac \geq \frac{1}{3}\Delta $$ In other words, the cubic function will not have a relative extremum if \(b^2 - 3ac \leq 0\) because the derivative will not have real solutions under this condition.
04

Conclusion

A cubic function \(f(x) = ax^3 + bx^2 + cx + d\) with \(a \neq 0\) has no relative extremum if and only if: $$ b^2 - 3ac \leq 0 $$ By analyzing the discriminant of the first derivative, we can deduce this condition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Points in Calculus
In calculus, critical points are significant because they are the x-values where the slope of the function is zero or undefined; essentially, they're where the graph of the function has a horizontal tangent line or a cusp. These points are monumental in identifying the function's local maxima and minima—commonly known as

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