Chapter 1: Problem 44
Solve the equation by using the quadratic formula. $$ \left(\frac{t}{t-1}\right)^{2}-\frac{2 t}{t-1}-3=0 $$
Short Answer
Expert verified
The solutions of the given equation are \(t = \frac{3}{2}\) and \(t = \frac{1}{2}\).
Step by step solution
01
Rewrite the equation in standard form
Let's substitute \(x = \frac{t}{t-1}\). Then the given equation becomes:
\[x^2 - 2x - 3 = 0.\]
Now, the equation is in the standard form \(ax^2 + bx + c = 0\) with \(a = 1\), \(b = -2\), and \(c = -3\).
02
Apply the quadratic formula
Plug the values of \(a\), \(b\), and \(c\) into the quadratic formula \(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\):
\[x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(1)(-3)}}{2(1)}.\]
03
Simplify the quadratic formula
Simplify the expression:
\[x = \frac{2 \pm \sqrt{4 + 12}}{2}.\]
\[x = \frac{2 \pm \sqrt{16}}{2}.\]
\[x = \frac{2 \pm 4}{2}.\]
04
Find the values of x
Calculate the two possible values of \(x\):
\[x_1 = \frac{2 + 4}{2} = \frac{6}{2} = 3\] and
\[x_2 = \frac{2 - 4}{2} = \frac{-2}{2} = -1\]
05
Find the values of t using the substitution
Now that we found the values of \(x\), we need to find their corresponding values of \(t\) using the substitution \(x = \frac{t}{t-1}\):
1. For \(x = 3\):
\[3 = \frac{t}{t-1}\]
\[3(t-1) = t\]
\[3t - 3 = t\]
\[2t = 3\]
\[t = \frac{3}{2}\]
2. For \(x = -1\):
\[-1 = \frac{t}{t-1}\]
\[-1(t-1) = t\]
\[-t + 1 = t\]
\[2t = 1\]
\[t = \frac{1}{2}\]
So, the solutions of the given equation are \(t = \frac{3}{2}\) and \(t = \frac{1}{2}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations, which are specific polynomial equations that have an equation of the form \( ax^2 + bx + c = 0 \). This formula helps find the roots of the equation, meaning the values of \( x \) that satisfy the equation. The quadratic formula is expressed as: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula works for all quadratic equations, irrespective of whether the roots are real or complex numbers. The expression under the square root, \( b^2 - 4ac \), is known as the discriminant, and it reveals the nature of the roots:
- If the discriminant is positive, there are two distinct real roots.
- If it's zero, there's exactly one real root (also called a repeated root).
- If negative, the equation has two complex roots.
Algebraic Substitution
Algebraic substitution is a technique used to simplify complex equations. By substituting a part of the equation with a single variable, it can make the equation more manageable and easier to solve. In our original problem, we used substitution by letting \( x = \frac{t}{t-1} \) to convert our complex rational equation into a standard quadratic form:\[ x^2 - 2x - 3 = 0 \]This substitution helps to reframe the problem, allowing us to use standard quadratic techniques, like factoring or using the quadratic formula. After solving for \( x \), we revert to the original variables to find the actual solutions to the initial problem. Such substitution can be particularly useful in real-world problems where relationships between variables are not straightforward but exhibit quadratic properties.
Problem-Solving Steps
Solving a quadratic equation methodically involves several concrete steps to ensure accuracy. Here's how you can systematically solve any quadratic equation using the quadratic formula:1. **Write the Equation in Standard Form:** Begin with writing your equation in the form \( ax^2 + bx + c = 0 \). This step often requires reorganizing or simplifying the equation.2. **Identify Values of \( a \), \( b \), and \( c \):** Extract the coefficients from the quadratic equation. These will be needed for the quadratic formula. 3. **Apply the Quadratic Formula:** With \( a \), \( b \), and \( c \) identified, substitute them into the quadratic formula. Simplifying the expressions under the square root is key here.4. **Simplify to Find \( x \):** Finish by simplifying the formula to solve for the values of \( x \), which will involve calculating both possible values from the \( \pm \) operation.5. **Reinterpret the Solutions (If Needed):** If original substitution was used, convert the solutions back to the original variables. Double-check all calculations to ensure the solutions satisfy the initial equation.
Standard Form of Quadratic Equations
The standard form for a quadratic equation is \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are coefficients, and \( a eq 0 \). This standardization sets the foundation for solving the quadratic equations through techniques like the quadratic formula, factorization, or completing the square.Each of the coefficients in the standard form serves a distinct purpose:
- \( a \): This coefficient multiplies the \( x^2 \) term and determines the parabola's direction (opening upwards if positive and downwards if negative).
- \( b \): The linear coefficient impacts the parabola's axis of symmetry and vertex position.
- \( c \): As the constant term, \( c \) alters the parabola's position along the \( y \)-axis, specifically where it intersects.