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15) Three points A, B, C on a motor racing track are such that \(B\) is \(1 \mathrm{~km}\) beyond A and \(\mathrm{C}\) is \(2 \mathrm{~km}\) beyond B. A car \(\mathrm{X}\), moving with uniform acceleration takes 1 minute to travel from \(A\) to \(B\) and \(1 \frac{1}{2}\) minutes to travel from \(B\) to \(C\). Find its acceleration in \(\mathrm{km} / \mathrm{h} / \mathrm{min}\) and show that its speed at \(\mathrm{C}\) is \(92 \mathrm{~km} / \mathrm{h}\). Another car Y, which is moving with uniform acceleration of \(8 \mathrm{~km} / \mathrm{h}\) per min. passes C 15 . seconds earlier than \(\mathrm{X}\), and its speed is then \(75 \mathrm{~km} / \mathrm{h}\). Find where \(\mathrm{X}\) passes \(\mathrm{Y}\). (Cambridge)

Short Answer

Expert verified
The acceleration is 8 km/h/min, and car Y is passed by car X after 0.25 km.

Step by step solution

01

Calculate the initial velocity (initial velocitya_0o 0\)

Given that point A to B is 1 km and point B to C is 2 km, let initial velocity at A be 饾憿 and acceleration be 饾憥.Use the equation for distance with uniform acceleration for A to B:d = ut + 0.5 * a * t^2 Givent = 1 minute (which is 1/60 hours) andd = 1 km,we get:1 = u * (1/60) + 0.5 * a * (1/60)^2Multiply by 60 to clear the fraction terms60 = u + 0.5 * a * (1/3600)So,u + 0.5 * a * = 216000(1)
02

Solve for the velocity at B:

By analogy, the distance traveled from B to C given t = 1.5 minutes (which is 3/60 hours or 1/40 hours)We apply the same theorm formula: So, D = 1.5/60
03

Solve the time to find

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is a branch of mechanics that deals with the motion of objects without considering the forces causing the motion. It's like focusing on where an object is, how fast it's moving, and how its speed changes over time.

In this exercise, we're looking at how a car moves along a track with uniform acceleration. This means the car's speed is constantly increasing.

  • The distance between points A and B is 1 km.
  • From B to C, the distance is 2 km.
  • It takes 1 minute for the car to travel from A to B.
  • From B to C, it takes an additional 1.5 minutes.

Uniform acceleration means we can use kinematic equations to describe the motion. For the initial velocity at A being u, and acceleration being a, we use:

\[ d = u t + \frac{1}{2} a t^2 \]

where d is the distance traveled, t is the time taken, u is the initial velocity, and a is the acceleration.
Equation of Motion
Equations of motion provide us with a way to describe the motion of an object mathematically. With uniform acceleration, there are three primary equations we use:

1. \[v = u + at\]
2. \[s = ut + \frac{1}{2} at^2\]
3. \[v^2 = u^2 + 2as\]

Here,
  • \(v\) is the final velocity
  • \(u\) is the initial velocity
  • \(a\) is the acceleration
  • \(t\) is the time
  • \(s\) is the displacement

In the given problem, to find the car's acceleration and speed at point C, we start with the second equation for motion covering points A to B:

\[1 = u \left( \frac{1}{60} \right) + \frac{1}{2} a \left( \frac{1}{60} \right)^2\]

Multiplying by 60 to clear the fractions:

\[60 = u + \frac{1}{2} a \left( \frac{1}{3600} \right) x 60\]

This simplifies to:
\[60 = u + \frac{a}{120}\]

The equation here helps us find the initial velocity u and acceleration a when we solve the simultaneous equations.

For B to C, we do a similar thing using the same principles but for the added distance and time.
Problem Solving in Physics
Solving physics problems often requires a systematic approach.

1. **Understand the problem:** Carefully read the given problem to identify what is known and what needs to be found. In this problem, we know the distances and times between points and need to find acceleration and velocity.

2. **Visualize the scenario:** Drawing a diagram can help visualize the motion. For instance, sketching the track with points A, B, and C, and labeling the given distances and times.

3. **Choose appropriate equations:** Based on what's given and what's needed, select the right equations of motion. Since the car has uniform acceleration, we use kinematic equations.

4. **Solve step-by-step:** Break the problem into smaller parts. Calculate intermediate values like initial velocity, acceleration first, and then move on to find the required final values.

5. **Check the units:** Always make sure to convert the units consistently, like converting minutes to hours when working in km/h.

  • For initial velocity u and acceleration a calculated from equations for A to B, and B to C, respectively, use the values to get the speed at point C.
  • Finally, set up an equation for the second car's motion and follow a similar approach for its acceleration and meeting point analysis.

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