Chapter 15: Problem 15
Six forces act round the sides of a hexagon. Find the equation of the line of action of their resultant. (a) Their magnitudes are \(P, 2 P, 4 P, 3 P, P, 2 P\) along \(\overrightarrow{\mathrm{AB}}, \overrightarrow{\mathrm{BC}}, \overrightarrow{\mathrm{CD}}, \overrightarrow{\mathrm{ED}}, \overrightarrow{\mathrm{FE}}, \overrightarrow{\mathrm{AF}}\) respectively. (b) The hexagon is regular. (c) The co-ordinates of vertex \(\mathbf{B}\) are \((1,1)\).
Short Answer
Step by step solution
Identify and Label Forces
Determine Position of Hexagon Vertices
Calculate the Coordinates of Force Vectors
Resolve Forces into Components
Calculate X and Y Components of Each Force
Find Resultant Force Magnitude and Direction
Determine the Line of Action
Find Equation of Line of Action
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Resolution
In the context of a hexagon, which has lines of action directed along its sides, this involves taking each force acting along the hexagon's sides and finding its components.
For example, if a force vector has a magnitude of P along the side \(\overrightarrow{AB}\), we need to determine how much of this force acts in the x-direction and how much in the y-direction. This can be done using trigonometric principles.
- Determine the angle the side makes with the horizontal.
- Use cosine for the x-component: \(\P_x = P \times \cos(θ)\) .
- Use sine for the y-component: \(\P_y = P \times \sin(θ)\).
Resultant Force Calculation
- \(\R_x = \sum{F_{i,x}}\)
- \(\R_y = \sum{F_{i,y}}\)
Line of Action Equations
Trigonometry in Hexagons
- An interior angle of a regular hexagon is 120 degrees.
- The distance between opposite vertices across the center equals traversing two side lengths.
- Each side is of equal length.
- \[ ( \cos{ \(θ + k \frac{π}{3} \) }, \( \sin{\theta + k \frac{π}{3} } \) \]