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(Calculus needed.) Derive the weighted least squares normal equations For letting a simple linear regression function when \(\sigma_{i}^{2}=k X_{i},\) where \(k\) is a proportionality constant.

Short Answer

Expert verified
The weighted least squares normal equations are derived as: \[ \beta_0 \sum_{i=1}^{n} X_i^{-1} + \beta_1 \sum_{i=1}^{n} X_i^0 = \sum_{i=1}^{n} Y_i X_i^{-1} \]\[ \beta_0 \sum_{i=1}^{n} X_i + \beta_1 \sum_{i=1}^{n} X_i^2 = \sum_{i=1}^{n} Y_i X_i \]

Step by step solution

01

- Write down the weighted least squares objective function

The weighted least squares objective function aims to minimize the sum of weighted squared residuals. The objective function can be written as: \[ Q(\beta_0, \beta_1) = \sum_{i=1}^{n} w_i (Y_i - \beta_0 - \beta_1 X_i)^2 \]where the weights are given by \[ w_i = \frac{1}{\sigma_{i}^{2}} = \frac{1}{k X_i} \]
02

- Substitute the weights

Substitute the weights into the objective function:\[ Q(\beta_0, \beta_1) = \sum_{i=1}^{n} \frac{1}{k X_i} (Y_i - \beta_0 - \beta_1 X_i)^2 \]
03

- Simplify the objective function

Simplify the objective function by factoring out \( \frac{1}{k} \): \[ Q(\beta_0, \beta_1) = \frac{1}{k} \sum_{i=1}^{n} \frac{(Y_i - \beta_0 - \beta_1 X_i)^2}{X_i} \]
04

- Calculate the partial derivatives

To find the normal equations, calculate the partial derivatives of \( Q(\beta_0, \beta_1) \) with respect to \( \beta_0 \) and \( \beta_1 \):\[ \frac{\partial Q}{\partial \beta_0} = \frac{2}{k} \sum_{i=1}^{n} \frac{-(Y_i - \beta_0 - \beta_1 X_i)}{X_i} = 0 \]\[ \frac{\partial Q}{\partial \beta_1} = \frac{2}{k} \sum_{i=1}^{n} \frac{-(Y_i - \beta_0 - \beta_1 X_i) X_i}{X_i} = 0 \]
05

- Simplify the equations

Simplify the equations obtained from the partial derivatives:For \( \beta_0 \): \[ \sum_{i=1}^{n} \frac{Y_i - \beta_0 - \beta_1 X_i}{X_i} = 0 \]For \( \beta_1 \): \[ \sum_{i=1}^{n} (Y_i - \beta_0 - \beta_1 X_i) = 0 \]
06

- Rearrange the simplified equations

Rearrange the simplified equations to solve for \( \beta_0 \) and \( \beta_1 \):For \( \beta_0 \): \[ \sum_{i=1}^{n} Y_i X_i^{-1} = \beta_0 \sum_{i=1}^{n} X_i^{-1} + \beta_1 \sum_{i=1}^{n} X_i^0 \]For \( \beta_1 \): \[ \sum_{i=1}^{n} X_i Y_i = \beta_0 \sum_{i=1}^{n} X_i + \beta_1 \sum_{i=1}^{n} X_i^2 \]
07

- Write final normal equations

Combine, rearrange, and solve the equations to write the final normal equations of the weighted least squares for simple linear regression:\[ \beta_0 \sum_{i=1}^{n} X_i^{-1} + \beta_1 \sum_{i=1}^{n} X_i^0 = \sum_{i=1}^{n} Y_i X_i^{-1} \]\[ \beta_0 \sum_{i=1}^{n} X_i + \beta_1 \sum_{i=1}^{n} X_i^2 = \sum_{i=1}^{n} Y_i X_i \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a statistical method used to create a straight-line relationship between two variables. The goal is to fit a line, called the regression line, that best predicts the dependent variable based on the independent variable.

In simple linear regression, the model can be written as:
i.e., fit a line such a way that i calculated a slope and intercept to minimize error comparing the predicted and actual residue.i.e. $$Y = \beta_{0} + \beta_{1}X_{1} $$

Where:
  • - **\(Y\)** is the dependent variable
  • - **\(X\)** is the independent variable
  • - **\(\beta_{0}\)** is the y-intercept
  • - **\(\beta_{1}\)** is the slope of the line
Ìý
In regular regression, the residues calculated, the weight assigned to each data point, used to calculate the coefficients \(\beta_{0}\) and \(\beta_{1}\).
Weighted Least Squares
Unlike simple linear regression, weighted least squares (WLS) assigns different weights to each data point. This approach is helpful when the variability of the error changes across different values of the independent variable.

Think of it as giving more importance to some points than others. The objective function to minimize in WLS is:
$$Q (\beta_{0},\beta_{1} ) = \sum_{i=1}^{n} w_{i} (Y_{i}-\beta_{0}- \beta_{1} X_{i} ) ^{2}$$
where
- **\(w_{i}\)** is the weight for data point \(i\).

The benefit of using weights is that it can handle heteroscedasticity (non-constant variance of errors). This means that if certain data points are noisier than others, we can adjust the regression to account for this variability using the appropriate weights.
Normal Equations
Normal equations arise from the process of minimizing the weighted least squares objective function. By taking partial derivatives of this objective function with respect to coefficients \(\beta_{0}\) and \(\beta_{1}\) and setting them to zero, we can derive the formulas to solve for our coefficients.

The partial derivatives of the simplified WLS objective function with weights included:
$$Q (\beta_{0},\beta_{1} ) = \sum_{i=1}^{n} \frac{1}{k X_{i} } (Y_{i} - \beta_{0} - \beta_{1} X_{i} ) $$ \(^{2}\)

are given by:
ForÌý \(\beta_{0}\):
$$\sum_{i=1} ^{n} \frac{ \partial Q}{ \partial \beta_{0}} = \sum_{i=1}^{n} \frac{ -(Y_{i} - \beta_{0} - \beta_{1} \ X_{i}}{X_{i}} = 0$$

For \(\beta_{1}\):
$$\sum_{i=1}^{n} \frac{\partial Q }{\partial \beta_{1}} = \sum_{i=1}^{n} \frac{ -(Y_{i} - \beta_{0} - \beta_{1} X_{i} ) X_{i} }{X_{i} } = 0$$


  • By solving these equations, we can find the optimal values of \(\beta_{0}\) and \(\beta_{1}\) that minimize the WLS objective function.
  • Variance Proportionality
    In the given exercise, the variance of the errors is proportional to the independent variable, i.e., \(\sigma_{i}^{2} = k X_{i}\). This means that the variance increases or decreases in direct proportion to the values of \(X_{i}\).

    This situation can occur in real-world data where variability isn’t constant. For instance:
    • Higher income may lead to higher variability in spending
    • ÌýIncreased time spent studying may lead to more variability in scores

    By incorporating this variance proportionality into our weights, we get:

    $$w_{i} = \frac{1}{ \sigma_{i} ^{2} } = \frac{1 }{k X_{i}}$$

    meaning the weights assign more importance to data points where the variance is lower.
    Consequently, when we use these weights in the WLS objective function, it helps handle and correct the effect that changing variance would have on the estimates of our regression coefficients. This is another way of ensuring our model is robust and accurate, even when facing real-world data complexities.

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