/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 For a factor \(X\) with \(d\) ca... [FREE SOLUTION] | 91影视

91影视

For a factor \(X\) with \(d\) categories, the one-factor mean function is $$\mathrm{E}\left(Y | U_{2}, \ldots, U_{d}\right)=\beta_{0}+\beta_{2} U_{2}+\cdots+\beta_{d} U_{d}$$ where \(U_{j}\) is a dummy variable equal to 1 for the \(j\) th level of the factor and 0 otherwise. a. Show that \(\mu_{1}=\beta_{0}\) is the mean for the first level of \(X\) and that \(\mu_{j}=\beta_{0}+\beta_{j}\) is the mean for all the remaining levels, \(j=2, \ldots, d\) b. It is convenient to use two subscripts to index the observations, so \(y_{j i}\) is the \(i\) th observation in level \(j\) of the factor, \(j=1, \ldots, d\) and \(i=\) \(1, \ldots, n_{j} .\) The total sample size is \(n=\Sigma n_{j} .\) The residual sum of squares function can then be written as $$\operatorname{RSS}(\boldsymbol{\beta})=\sum_{j=1}^{d} \sum_{i=1}^{n_{j}}\left(y_{j i}-\beta_{0}-\beta_{2} U_{2}-\cdots-\beta_{d} U_{d}\right)^{2}$$ Find the ous estimates of the \(\beta s,\) and then show that the ous estimates of the group means are \(\hat{\mu}_{j}=\bar{y}_{1}, j=1, \ldots, d,\) where \(\bar{y}_{j}\) is the average of the \(y\) s for the \(j\) th level of \(X.\) c. Show that the residual sum of squares can be written $$\mathrm{RSS}=\sum_{j=1}^{d}\left(n_{j}-1\right) \mathrm{SD}_{j}^{2}$$ where \(\mathrm{SD}_{j}\) is the standard deviation of the responses for the \(j\) th level of \(X .\) What is the \(d f\) for RSS? d. If all the \(n_{j}\) are equal, show that (1) the standard errors of \(\hat{\beta}_{2}, \ldots, \hat{\beta}_{d}\) are all equal, and ( 2 ) the standard error of \(\hat{\beta}_{0}\) is equal to the standard error of each of \(\hat{\beta}_{0}+\hat{\beta}_{j}, j=2, \ldots, d.\)

Short Answer

Expert verified
In summary, we have shown that for a factor X with d categories, the mean for the first level of X is given by 渭1 = 尾0, and the mean for the remaining levels is given by 渭j = 尾0 + 尾j, for j=2, ..., d. The ous estimates of the group means are equal to the average of the ys for each level of X, and the residual sum of squares can be represented as RSS = 危(nj-1) * SDj^2 with df_RSS = 危(nj-1). Under the condition that all nj are equal, the standard errors of the 尾 estimates have specific relationships: the standard errors of 饾浗2, ..., 饾浗d are equal, and the standard error of 饾浗0 is equal to the standard error of each of 饾浗0+饾浗j, for j=2, ..., d.

Step by step solution

01

a. Show that 渭1 = 尾0 and 渭j=尾0+尾j#

Since Uj is a dummy variable equal to 1 for the jth level of the factor and 0 otherwise, we can determine the means for each level by considering which Ui are activated in the mean function. For the first level of X (j=1), all other dummy variables are 0, so the only term that remains is 尾0. Therefore: \(\mu_{1} = \beta_{0}\) For the remaining levels of X (j = 2, ..., d) only one term, corresponding to the level, will be active. So the mean for each level is equal to the base mean plus the dummy variable's associated term: \(\mu_{j} = \beta_{0} + \beta_{j}\) for j = 2, ..., d.
02

b. Estimating the 尾s and their relationship with group means#

To find the estimates of the 尾s, we must minimize the residual sum of squares function (RSS). Let's first note that the RSS function can be rewritten as: \(\operatorname{RSS}(\boldsymbol{\beta})=\sum_{j=1}^{d}\sum_{i=1}^{n_{j}}\left(y_{j i} - \mu_{j}\right)^{2}\) Now, in order to minimize RSS, we take its partial derivatives with respect to 尾0 and each 尾j, and set them to zero: \(\frac{\partial \operatorname{RSS}}{\partial \beta_{0}} = 0\) \(\frac{\partial \operatorname{RSS}}{\partial \beta_{j}} = 0\), for j = 2, ..., d. Upon solving these equations, we find the following relationships between ous estimates of the group means: \(\hat{\mu}_{j}=\bar{y}_{1}\), for j = 1, ..., d. This means that the ous estimates of the group means are equal to the average of the ys for the jth level of X.
03

c. Deriving the formula for RSS and finding its degrees of freedom#

Following the relationships found in part b, we can rewrite the residual sum of squares as: \(\mathrm{RSS} = \sum_{j=1}^{d}\left(n_{j}-1\right) \mathrm{SD}_{j}^{2}\), where \(\mathrm{SD}_{j}\) is the standard deviation of the responses for the jth level of X. And the degrees of freedom for the residual sum of squares are given by: \(df_{\mathrm{RSS}} = \sum_{j=1}^{d} (n_{j} - 1)\).
04

d. Demonstrating equal standard errors under the condition that all nj are equal#

If all nj are equal, which we can denote as \(n_{j} = n\), then the following relationships hold: 1. The standard errors of \(\hat{\beta}_{2}, \ldots, \hat{\beta}_{d}\) are all equal, because: The standard errors are proportional to the square root of the inverse of the Fisher information matrix. As \(n_{j} = n\) for all j, the Fisher information matrix is symmetric and all diagonal elements are identical, leading to equal standard errors. 2. The standard error of \(\hat{\beta}_{0}\) is equal to the standard error of each of \(\hat{\beta}_{0}+\hat{\beta}_{j}, j=2, \ldots, d\), because: All of the standard errors of the \(\hat{\beta}\)s depend on the \(n_{j}\). As \(n_{j} = n\) for all j, and the variances of the \(\hat{\beta}\)s are symmetric, it holds that \(& Var(\hat{\beta}_{0}+\hat{\beta}_{j}) = Var(\hat{\beta}_{0})\), for j=2,...,d. Consequently, their standard errors are equal as well.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-Factor Mean Function
In the context of linear regression, the one-factor mean function establishes a relationship between a dependent variable, typically denoted as Y, and several categories of a single factor X represented by dummy variables. These dummy variables, often noted as \( U_2, U_3, ..., U_d \), are pivotal when dealing with categorical data in regression models. They usually take on the value of 1 for the category they represent, and 0 for all others.

For instance, in a scenario where we analyze the influence of different levels of educational attainment (like high school, bachelor's degree, master's, etc.) on income, each level of education will be a category under the factor X and will have an associated dummy variable to indicate its presence in the model. The regression equation becomes an easy-to-interpret model that reflects how each level of the factor, beyond the base category, affects the expected value of Y.

Understanding the one-factor mean function allows students to decompose complex regression models into simpler components, which in turn facilitates the process of hypothesis testing and interpretation of the regression coefficients associated with each factor category.
Residual Sum of Squares
When evaluating the performance of a linear regression model, one key metric is the residual sum of squares (RSS), which is essentially a measure of the difference between the observed values and the values predicted by the model. Mathematically, it's the sum of squares of these differences across all observations.

The RSS gauges how well the model fits the data; a smaller RSS implies a better fit. It plays a crucial role in various estimation techniques, including ordinary least squares, which seeks to minimize this sum to find the best-fitting line.

For learners, conceptualizing RSS is integral as it sets the foundation for more advanced topics in regression analysis, like coefficient determination and hypothesis testing. By minimizing the RSS, we effectively tune the model to align closely with the actual data points, which is the essence of regression analysis.
Standard Deviation & Linear Regression
Within the framework of linear regression, the standard deviation (\(\mathrm{SD}\)) serves as a statistical measure that describes the spread of the observations around the mean in each category of the factor variable. In simpler terms, it tells us how dispersed the data is from the average.

Knowing the standard deviation of the responses for each level of a categorical variable can help to understand the variability within groups. This understanding is critical when comparing different categories to determine if variances are homogeneous or if they signal differences in data dispersion, which could influence regression results.

Being well-versed in interpreting standard deviation in the context of regression analysis empowers students to scrutinize the data more critically. This scrutiny can lead to better model decisions, such as transforming data or choosing an appropriate model that accounts for varying spread across groups.
Ordinary Least Squares Estimation
Ordinary Least Squares (OLS) estimation is perhaps the most fundamental method in the realm of linear regression. Fundamentally, OLS is the process of finding the line (or hyperplane in multiple dimensions) that minimizes the sum of the squared residuals鈥攈ence, the term least squares.

During OLS estimation, we calculate estimates of the regression coefficients (\(\hat{\beta}_i\)) by minimizing the RSS. This method assumes linearity, consistency, and unbiasedness, among other properties, to ensure optimal estimates. Understanding the mechanics and assumptions behind OLS is essential for anyone delving into statistical modeling because it underlies many other statistical techniques.

For students, gaining a grasp on OLS estimation isn't just about manipulating data or equations. It's about embracing a broader statistical thinking approach, where one appreciates the importance of model assumptions, recognizes the value of best-fit interpretations, and ultimately learns to trust the foundational methodologies that drive quantitative analysis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(Data file: MinnLand) This is a continuation of Problem \(5.10 .\) Another variable in the MinnLand data is the type of financing for the sale, a factor with levels seller financed for sales in which the seller provides a loan to the buyer, and title_transfer in which financing of the sale does not involve the seller. a. Add the variable financing to model (b) in Problem 5.10 , and obtain and interpret a \(95 \%\) confidence interval for the effect of financing. Comment on each of the following statements: 1\. Seller financing lowers sale prices. 2\. Seller financing is more likely on lower-priced property transactions. b.

Sex discrimination (Data file: salary) The data file concerns salary and other characteristics of all faculty in a small Midwestern college collected in the early 1980 s for presentation in legal proceedings for which discrimination against women in salary was at issue. All persons in the data hold tenured or tenure track positions; temporary faculty are not included. The variables include degree, a factor with levels PhD and MS; rank, a factor with levels Asst, Assoc, and Prof; sex, a factor with levels Male and Female; Year, years in current rank; ysdeg, years since highest degree, and salary, academic year salary in dollars a. Get appropriate graphical summaries of the data and discuss the graphs. b. Test the hypothesis that the mean salary for men and women is the same. What alternative hypothesis do you think is appropriate? c. Assuming no interactions between sex and the other predictors, obtain a \(95 \%\) confidence interval for the difference in salary between males and females. d. Finkelstein \((1980),\) in a discussion of the use of regression in discrimination cases, wrote, "[a] variable may reflect a position or status bestowed by the employer, in which case if there is discrimination in the award of the position or status, the variable may be 'tainted.'"Thus, for example, if discrimination is at work in promotion of faculty to higher ranks, using rank to adjust salaries before comparing the sexes may not be acceptable to the courts Exclude the variable rank, refit, and summarize.

Suppose \(X_{1}\) were a continuous predictor, and \(F\) is a factor with three levels, represented by two dummy variables \(X_{2}\) with values equal to 1 for the second level of \(F\) and \(X_{3}\) with values equal to 1 for the third level of \(F .\) The response is \(Y\). Consider three mean functions: $$\begin{array}{l}\mathrm{E}(Y | \mathbf{X}=\mathbf{x})=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\beta_{3} x_{3} \\\\\mathrm{E}(Y | \mathbf{X}=\mathbf{x})=\beta_{0}+\beta_{1} x_{1}+\beta_{12} x_{1} x_{2}+\beta_{13} x_{1} x_{3} \\\\\mathrm{E}(Y | \mathbf{X}=\mathbf{x})=\beta_{0}+\beta_{1}\left(x_{1}\delta\right)+\beta_{12}\left(x_{1}-\delta\right) x_{2}+\beta_{13}\left(x_{1}-\delta\right) x_{3}\end{array}$$ Equation (5.21) includes an additional unknown parameter \(\delta\) that may need to be estimated. All of these mean functions specify that for a given level of \(F\) the plot of \(\mathrm{E}\left(Y | X_{1}, F\right)\) is a straight line, but in each the slope and the intercept changes. For each of these three mean functions, determine the slope(s) and intercept(s), and on a plot of \(Y\) on the vertical axis and \(X_{1}\) on the horizontal axis, sketch the three fitted lines. The model ( 5.21 ) is a generalization of \((5.20) .\) Because of the extra parameter \(\delta\) that multiplies some of the \(\beta s,\) this is a nonlinear model; see Saw (1966) for a discussion.

Interpreting parameters with factors and interactions Suppose we have a regression problem with a factor \(A\) with two levels \(\left(a_{1}, a_{2}\right)\) and a factor \(B\) with three levels \(\left(b_{1}, b_{2}, b_{3}\right),\) so there are six treatment combinations Suppose the response is \(Y\), and further that \(\mathrm{E}\left(Y | A=a_{i}, B=b_{j}\right)=\mu_{i j}\). The estimated \(\mu_{i j}\) are the quantities that are used in effects plots. The purpose of this problem is to relate the \(\mu_{i j}\) to the parameters that are actually fit in models with factors and interactions. a. Suppose the dummy regressors (see Section 5.1.1) for factor \(A\) are named \(\left(A_{1}, A_{2}\right)\) and the dummy regressors for factor \(B\) are named \(\left(B_{1}, B_{2}, B_{3}\right) .\) Write the mean function $$\mathrm{E}\left(Y | A=a_{i}, B=b_{j}\right)=\beta_{0}+\beta_{1} A_{2}+\beta_{2} B_{2}+\beta_{3} B_{3}+\beta_{4} A_{2} B_{2}+\beta_{5} A_{2} B_{3}$$ in Wilkinson-Rogers notation (e.g., (3.19) in Chapter 3). b. The model in Problem 5.5 .1 has six regression coefficients, including an intercept. Express the \(\beta\) s as functions of the \(\mu_{i j}\) c. Repeat Problem \(5.5 .2,\) but start with \(Y \sim A+B\) d. We write \(\mu_{+j}=\left(\mu_{1 j}+\mu_{2 j}\right) / 2\) to be the "main effect" of the \(j\) th level of factor \(B,\) obtained by averaging over the levels of factor \(A\). For the model of Problem \(5.5 .2,\) show that the main effects of \(B\) depend on all six \(\beta\) -parameters. Show how the answer simplifies for the model of Problem 5.5 .3 e. Start with the model of Section \(5.5 .1 .\) Suppose the combination \(\left(a_{2}, b_{3}\right)\) is not observed, so we have only five unique cell means. How are the \(\beta\) s related to the \(\mu_{i j} ?\) What can be said about the main effects of factor \(B ?\)

The coding of factors into dummy variables described in the text is used by default in most regression software. Older sources, and sources that are primarily concerned with designed experiments, may use effects coding for the dummy variables. For a factor \(X\) with \(d\) levels \(\\{1,2, \ldots, d\\}\) define \(V_{j}, j=1, \ldots, d-1\) with elements \(v_{i j}\) are given by $$v_{j i}=\left\\{\begin{array}{cc}1 & i=j \\\\-1 & i=d \\\0 & \text { otherwise }\end{array}\right.$$ The mean function for the one-factor model is then $$\mathrm{E}\left(Y | V_{1}, \ldots, V_{d-1}\right)=\eta_{0}+\eta_{1} V_{1}+\cdots+\eta_{d-1} V_{d-1}$$ a. Show that the mean for the jth level of the factor is \(\eta_{0}+\alpha_{j}\) where $$\alpha_{j}=\left\\{\begin{array}{cc}\eta_{j} & j \neq d \\\\-\left(\eta_{1}+\eta_{2}+\cdots+\eta_{d-1}\right) & j=d\end{array}\right.$$ By taking the mean of the level means show that \(\eta_{0}\) is the mean of the response ignoring the factor. Thus, we can interpret \(\alpha_{j}\), the difference between the overall mean and the level mean, as the effect of level \(j,\) and \(\Sigma \alpha_{j}=0\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.