/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 An oil company has two refinerie... [FREE SOLUTION] | 91Ó°ÊÓ

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An oil company has two refineries. Each day, Refinery A produces 200 barrels of high-grade oil, 300 barrels of medium-grade oil, and 200 barrels of low- grade oil and costs $$\$ 12,000$$ to oper ate. Each day, Refinery B produces 100 barrels of high-grade oil, 100 barrels of medium-grade oil, and 200 barrels of low-grade oil and costs $$\$ 10,000$$ to oper ate. The company must produce at least 800 barrels of high-grade oil, 900 barrels of medium-grade oil, and 1,000 barrels of low-grade oil. How many days should each refinery be operated to meet the goals at a minimum cost?

Short Answer

Expert verified
The solution will depend on the method used to solve the problem. The objective is to find the least number of days each refinery should operate to meet the production goals at minimum cost. This will require using methods of linear programming.

Step by step solution

01

Define Variables

Let's use two variables to represent the number of days each refinery is in operation. Let \( x \) be the number of days Refinery A is in operation and \( y \) be the number of days Refinery B is in operation.
02

Setup Constraints

Now we set up the constraints. For high-grade oil: \(200x + 100y \geq 800\), for medium-grade oil: \(300x + 100y \geq 900\) and for low-grade oil: \(200x + 200y \geq 1000\). All of these must be met while keeping \(x\) and \(y\) nonnegative because you can't operate a refinery for negative number of days.
03

Set up Objective Function

The cost of operation should be minimized. So our objective function is the cost which can be written as \( C = 12000x + 10000y \)
04

Solve the Problem

This problem can now be solved using methods of linear programming, such as the simplex method or graphical method.
05

Interpret the Results

The solution will give the optimal number of days each refinery should be in operation to meet the production goals at minimum cost. It's always good to interpret the solution in terms of the given problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constraints in Linear Programming
In linear programming, constraints play a pivotal role as they define the conditions that the solution must satisfy. These constraints typically represent limitations or requirements in real-world scenarios that must be respected while optimizing the objective function. For example, an oil company might have minimum production requirements for different grades of oil, as well as limitations on how many days their refineries can operate due to factors like budget, resources, or regulations.

In essence, constraints are mathematical inequalities that shape the feasible region within which the optimal solution lies. In the context of the refinery example, we translate production requirements and operating limits into inequalities involving the decision variables, which represent the numbers of days refineries A and B operate. These are demonstrated as:
  • High-grade oil constraint: \(200x + 100y \geq 800\)
  • Medium-grade oil constraint: \(300x + 100y \geq 900\)
  • Low-grade oil constraint: \(200x + 200y \geq 1000\)
The non-negativity constraints also must be highlighted. It enforces that the solution has a practical meaning, which in this case, indicates that a refinery can't operate for a negative number of days.

Applying the Constraints in Solutions

When solving such problems, these constraints form the basis for the feasible solution set. It's necessary to solve these simultaneous inequalities to determine the feasible region or to employ methods such as the simplex method to find out the optimal solution within these bounds.
Objective Function Optimization
Once the constraints of a linear programming problem are established, the next step is to define the objective function, which needs to be optimized. In many cases, this involves either maximization or minimization. Our aim is to find the best possible outcome under the given constraints.

For the oil company in our example, the objective is to minimize the cost of operating the refineries. Hence, the objective function is translated into a cost function as follows: \( C = 12000x + 10000y \) where \(x\) and \(y\) are the variables representing the number of days Refinery A and Refinery B are in operation, respectively.

The objective function encapsulates the goal of the problem and guides the direction of optimization; in this case, we want the lowest possible value of \(C\). The solution to the linear programming problem is the set of values for our variables that will yield the optimum value of the objective function (least cost) while still satisfying all of the constraints of the problem.

Finding the Optimum

The process of finding this optimal point typically involves using mathematical methods and algorithms which can systematically search through the feasible region defined by the constraints to find where the objective function takes on its optimal value.
The Simplex Method
The simplex method is an algorithm designed for solving linear programming problems efficiently. It is particularly suited for problems like the one described, where we seek to minimize costs for the oil company. Developed by George Dantzig in 1947, this method has become one of the most widely used algorithms for this purpose.

It operates on the principle that the optimal solution for a linear programming problem lies at one of the vertices of the feasible region defined by the linear constraints. Therefore, the simplex method iteratively explores adjacent vertices of the feasible region in a way that either improves the objective function value or confirms that the current solution is optimal.

Steps in the Simplex Method

The approach typically begins with finding a basic feasible solution, then checking if it can be improved. If improvement is possible, a new, better feasible solution is found. This process continues until no further improvements can be made, meaning that the optimal solution has been obtained.

For our refinery problem, after setting up the problem with constraints and an objective function, the simplex method can systemically test out feasible solutions until it identifies the optimal numbers of days to operate each refinery while minimising the total cost.

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Most popular questions from this chapter

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