Chapter 2: Problem 33
Graph the line that passes through the given point and has the given slope. (1,2) and \(m=-3 / 4\)
Short Answer
Expert verified
The equation of the line is \(y = -3/4 * x + 5/2\) and the line passes through the points (0, 5/2) and (4, 1/2)
Step by step solution
01
Identify given values
From the problem, we can see that the slope \(m\) of the line is -3/4 and it passes through the point (1,2). So, these are our values of \(x\), \(y\), and \(m\).
02
Apply point-slope form
We can use the point-slope form of a line equation to find the y-intercept. The point-slope form of a line equation is given by \[ y - y_1 = m (x - x_1)\] where \((x_1, y_1)\) are the coordinates of the given point and \(m\) is the slope. Substituting the given point (1,2) and the slope -3/4 into the equation, it becomes \[y - 2 = -3/4 * (x - 1)\].
03
Convert to slope-intercept form
Expanding the equation we get, \[ y - 2 = -3/4 * x + 3/4 \] which simplifies to \[ y = -3/4 * x + 5/2 \] after you add 2 (or 4/2) to both sides of the equation to isolate \(y\). The equation of the line in slope-intercept form (\(y = mx + c\)) is \[ y = -3/4 * x + 5/2 \] where -3/4 is the slope \(m\) and 5/2 is the y-intercept \(c\).
04
Graph the line
First plot the y-intercept, which is the point (0, 5/2) on the y-axis. Then, from this point, use the slope to find another point and draw the line. The slope is -3/4, which means 'go down 3 units and right 4 units'. So, start at the y-intercept (0, 5/2) move down 3 units and right 4 units which takes you to the point (4, 1/2). Draw a straight line that passes through these points. This line matches the equation of the line \[ y = -3/4 * x + 5/2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
Understanding the point-slope form is essential when learning about graphing linear equations. It's an equation that allows you to describe a line on a graph when you know a particular point through which the line passes and its slope.
The generic formula for point-slope form is written as: \[ y - y_1 = m(x - x_1) \] where \(m\) represents the slope of the line, and \(x_1, y_1\) are the coordinates of the known point on the line. This form is especially useful when you are not given the y-intercept directly, but instead have a point and the slope.
For example, if the slope of the line is \(m = -\frac{3}{4}\) and it passes through the point \( (1,2) \), inserting these values into the point-slope form, the equation becomes: \[ y - 2 = -\frac{3}{4}(x - 1) \] which can then be manipulated to reach other forms of linear equation representation, such as slope-intercept form.
The generic formula for point-slope form is written as: \[ y - y_1 = m(x - x_1) \] where \(m\) represents the slope of the line, and \(x_1, y_1\) are the coordinates of the known point on the line. This form is especially useful when you are not given the y-intercept directly, but instead have a point and the slope.
For example, if the slope of the line is \(m = -\frac{3}{4}\) and it passes through the point \( (1,2) \), inserting these values into the point-slope form, the equation becomes: \[ y - 2 = -\frac{3}{4}(x - 1) \] which can then be manipulated to reach other forms of linear equation representation, such as slope-intercept form.
Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most straightforward ways to represent a line. This form is handy because it neatly displays both the slope and the y-intercept, which are key characteristics of the line. Mathematically, the slope-intercept form is expressed as \( y = mx + c \), with \(m\) being the slope and \(c\) the y-intercept, the point where the line crosses the y-axis.
Transforming our previous point-slope example into slope-intercept form involves simplifying and re-arranging the equation: \[ y - 2 = -\frac{3}{4}x + \frac{3}{4} \] becomes \[ y = -\frac{3}{4}x + \frac{5}{2} \] after adding \(2\) to both sides to isolate the \(y\) variable. In this equation, the slope -\frac{3}{4} indicates the line falls three units for every four units it moves to the right, and the y-intercept \frac{5}{2} tells us where the line crosses the y-axis.
This information is vital as it allows for quick plotting of the line on a graph and understanding its behavior without additional computations.
Transforming our previous point-slope example into slope-intercept form involves simplifying and re-arranging the equation: \[ y - 2 = -\frac{3}{4}x + \frac{3}{4} \] becomes \[ y = -\frac{3}{4}x + \frac{5}{2} \] after adding \(2\) to both sides to isolate the \(y\) variable. In this equation, the slope -\frac{3}{4} indicates the line falls three units for every four units it moves to the right, and the y-intercept \frac{5}{2} tells us where the line crosses the y-axis.
This information is vital as it allows for quick plotting of the line on a graph and understanding its behavior without additional computations.
Plotting Lines on a Graph
To visually represent the linear equations, plotting lines on a graph is an invaluable skill. It starts by identifying two fundamental components from the equation: the y-intercept and the slope.
The y-intercept is the starting point where the line crosses the vertical y-axis. In our equation \( y = -\frac{3}{4}x + \frac{5}{2} \), the y-intercept is \(\frac{5}{2}\) or 2.5, which translates to a point on the graph where \(x=0\) and \(y=\frac{5}{2}\). This point serves as the initial marking on the graph from which we will build the rest of the line.
Next, the slope gives us the rise over run - in this case, \( -\frac{3}{4} \), meaning that for every 4 units the line moves horizontally, it will also move down 3 units due to the negative sign. Starting from the y-intercept, you can 'rise' down 3 units (because of the negative slope) and 'run' 4 units to the right to find another point. By connecting these points with a straight line, you will have a visual representation of the linear equation that was initially given in algebraic form.
The y-intercept is the starting point where the line crosses the vertical y-axis. In our equation \( y = -\frac{3}{4}x + \frac{5}{2} \), the y-intercept is \(\frac{5}{2}\) or 2.5, which translates to a point on the graph where \(x=0\) and \(y=\frac{5}{2}\). This point serves as the initial marking on the graph from which we will build the rest of the line.
Next, the slope gives us the rise over run - in this case, \( -\frac{3}{4} \), meaning that for every 4 units the line moves horizontally, it will also move down 3 units due to the negative sign. Starting from the y-intercept, you can 'rise' down 3 units (because of the negative slope) and 'run' 4 units to the right to find another point. By connecting these points with a straight line, you will have a visual representation of the linear equation that was initially given in algebraic form.