/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Disprove the following, assuming... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Disprove the following, assuming \(A, B,\) and \(C\) are sets: (a) \(A-B=B-A\). (b) \(A \times B=B \times A\). (c) \(A \cap B=A \cap C\) implies \(B=C\). (d) \(A \oplus(B \cap C)=(A \oplus B) \cap(A \oplus C)\)

Short Answer

Expert verified
None of the set equalities hold, as shown by counterexamples.

Step by step solution

01

Understand Set Difference

Set difference, denoted by \(A - B\), means elements that are in \(A\) but not in \(B\). If we reverse this, \(B - A\) would mean elements that are in \(B\) but not in \(A\). These are different unless \(A = B\).
02

Disprove Part (a)

Consider \(A = \{1, 2\}\) and \(B = \{2, 3\}\). Then, \(A - B = \{1\}\) and \(B - A = \{3\}\). The two results are different, thus \(A - B eq B - A\).
03

Understand Cartesian Product

The Cartesian product \(A \times B\) consists of ordered pairs \((a, b)\) where \(a \in A\) and \(b \in B\). The order matters, so \(A \times B\) is not equal to \(B \times A\) unless the sets have specific properties.
04

Disprove Part (b)

Set \(A = \{1\}\) and \(B = \{2\}\). Then, \(A \times B = \{(1, 2)\}\) while \(B \times A = \{(2, 1)\}\), showing that \(A \times B eq B \times A\).
05

Understand Set Intersection Implication

The statement \(A \cap B = A \cap C\) suggests that the elements common to \(A\) and \(B\) are the same as those common to \(A\) and \(C\). It does not necessarily follow that \(B = C\).
06

Disprove Part (c)

Let \(A = \{1, 2\}\), \(B = \{1\}\), and \(C = \{1, 3\}\). Then, \(A \cap B = \{1\} = A \cap C\), yet \(B eq C\). Therefore, \(A \cap B = A \cap C\) does not imply \(B = C\).
07

Understand Symmetric Difference

The symmetric difference \(A \oplus B\) refers to elements in either \(A\) or \(B\), but not both. Using this definition, we assess the given equation.
08

Disprove Part (d)

Let \(A = \{1\}\), \(B = \{2\}\), and \(C = \{2\}\). Then, \(B \cap C = \{2\}\), and \(A \oplus (B \cap C) = \{1, 2\}\). However, \((A \oplus B) \cap (A \oplus C) = \{1, 2\} \cap \{1, 2\} = \{1, 2\}\), which coincidentally matches, but other examples \(A = \{1\}\), \(B = \{2, 3\}\), \(C = \{3, 4\}\) will show the inequality: \(A \oplus (B \cap C) eq (A \oplus B) \cap (A \oplus C)\).
09

Conclusion

In each case, the statements are false as demonstrated by counterexamples, showing that the given set equalities do not hold universally.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Difference
Set difference is a fundamental concept in set theory that helps us identify elements that belong to one set but not the other. We denote the difference of set \(A\) from set \(B\) as \(A - B\). This operation results in a new set containing all elements that are in \(A\) but not in \(B\). For instance, if \(A = \{1, 2, 3\}\) and \(B = \{2, 3, 4\}\), then \(A - B = \{1\}\), because \(1\) is the only element in \(A\) that is not in \(B\).
When we reverse the order and calculate \(B - A\), we get the elements in \(B\) but not in \(A\). Continuing our example, \(B - A = \{4\}\). As this highlights, \(A - B\) is generally not the same as \(B - A\) unless the two sets are identical. This concept is vital in understanding differences across data sets in computer science and mathematics.
Cartesian Product
The Cartesian Product is an operation used to combine two sets, \(A\) and \(B\), into a set of ordered pairs. The notation for this is \(A \times B\). Each element of this product takes the form of \((a, b)\), where \(a\) is an element from set \(A\) and \(b\) is from set \(B\).
Notably, the order in which elements are paired is important. Thus, the Cartesian product \(A \times B\) is not equal to \(B \times A\) unless the elements can form symmetric pairs, which is uncommon. As an example, let \(A = \{x\}\) and \(B = \{y\}\). Then \(A \times B = \{(x, y)\}\) and \(B \times A = \{(y, x)\}\). This operation finds extensive use in fields that handle relational databases and coordinate systems.
Set Intersection
Set Intersection refers to the operation that identifies elements common to both sets. The intersection is denoted as \(A \cap B\) and results in a new set with only those elements found in both \(A\) and \(B\).
For example, if \(A = \{1, 2, 3\}\) and \(B = \{2, 3, 4\}\), then \(A \cap B = \{2, 3\}\). It's essential to recognize that sharing intersections does not imply the sets are identical. If we have a third set \(C = \{2, 3, 5\}\), \(A \cap C = \{2, 3\}\), just like \(A \cap B\), yet \(B eq C\) because their other elements differ. Understanding intersections aids in solving problems such as finding commonalities in data sets or optimizing queries in database systems.
Symmetric Difference
Symmetric difference is a set operation that combines the elements of two sets, but excludes any elements that appear in both. We denote the symmetric difference of sets \(A\) and \(B\) as \(A \oplus B\). The result is a new set, where you'll find elements that are in \(A\) or \(B\), but not in their intersection.
Taking an example where \(A = \{1, 2, 3\}\) and \(B = \{3, 4, 5\}\), \(A \oplus B = \{1, 2, 4, 5\}\). Notice that 3 is excluded as it is common to both sets. In practical terms, the symmetric difference can highlight discrepancies between two datasets effectively, helping in identifying unique elements that are not shared.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Partition \(\\{1,2, \ldots .9\\}\) into the minsets generated by \(B_{1}=\\{5,6,7\\}\), \(B_{2}=\\{2,4,5,9\\},\) and \(B_{3}=\\{3,4,5,6,8,9\\}\) (b) How many different subsets of \(\\{1,2, \ldots, 9\\}\) can you create using \(B_{1}, B_{2},\) and \(B_{3}\) with the standard set operations? (c) Do there exist subsets \(C_{1}, C_{2}, C_{3}\) whose minsets will generate every subset of \(\\{1,2, \ldots, 9\\} ?\)

Partition the set of strings of 0 's and 1 's of length two or less, using the minsets generated by \(B_{1}=\\{s \mid s\) has length 2\(\\},\) and \(B_{2}=\\{s \mid\) \(s\) starts with a 0\(\\}\).

The rules that determine the order of evaluation in a set expression that involves more than one operation are similar to the rules for logic. In the absence of parentheses, complementations are done first, intersections second, and unions third. Parentheses are used to override this order. If the same operation appears two or more consecutive times, evaluate from left to right. In what order are the following expressions performed? (a) \(A \cup B^{c} \cap C\). (c) \(A \cup B \cup C^{c}\) (b) \(A \cap B \cup C \cap B\).

Let \(A, B\) and \(C\) be sets. Prove or disprove: $$ A \cap B \neq \emptyset, B \cap C \neq \emptyset \Rightarrow A \cap C \neq \emptyset $$

Prove the following: (a) Let \(A, B,\) and \(C\) be sets. If \(A \subseteq B\) and \(B \subseteq C,\) then \(A \subseteq C\). (b) Let \(A\) and \(B\) be sets. Then \(A-B=A \cap B^{c}\). (c) Let \(A, B,\) and \(C\) be sets. If \((A \subseteq B\) and \(A \subseteq C)\) then \(A \subseteq B \cap C\). (d) Let \(A\) and \(B\) be sets. \(A \subseteq B\) if and only if \(B^{c} \subseteq A^{c}\). (e) Let \(A, B,\) and \(C\) be sets. If \(A \subseteq B\) then \(A \times C \subseteq B \times C\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.