Chapter 16: Problem 9
Let \(\mathbb{Q}(\sqrt{2})=\\{a+b \sqrt{2} \mid a, b \in \mathbb{Q}\\}\). (a) Prove that \([\mathbb{Q}(\sqrt{2}) ;+, \cdot]\) is a field. (b) Show that \(\mathbb{Q}\) is a subfield of \(\mathbb{Q}(\sqrt{2})\). For this reason, \(\mathbb{Q}(\sqrt{2})\) is called an extension field of \(\mathbb{Q}\). (c) Show that all the roots of the equation \(x^{2}-4 x+\frac{7}{2}=0\) lie in the extension field \(\mathbb{Q}(\sqrt{2})\). (d) Do the roots of the equation \(x^{2}-4 x+3=0\) lie in this field? Explain.
Short Answer
Step by step solution
Understanding the Definition of a Field
Closure Properties
Associativity and Commutativity
Identity and Inverses
Conclusion for Part (a)
Subfield Verification for \(\mathbb{Q}\)
Roots of Quadratic Equation
Analyzing Roots of Another Quadratic Equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Extension field
- The origin field here is \(\mathbb{Q}\), or the set of all rational numbers.
- By adjoining \(\sqrt{2}\), we create the extension field \(\mathbb{Q}(\sqrt{2})\).
- This extension allows solutions to polynomial equations, which \(\mathbb{Q}\) alone cannot resolve.
Subfield
This subfield relationship means:
- All elements of \(\mathbb{Q}\) can be expressed as elements of \(\mathbb{Q}(\sqrt{2})\).
- The operations defined on \(\mathbb{Q}\) naturally extend to \(\mathbb{Q}(\sqrt{2})\).
- \(\mathbb{Q}\) maintains its field properties even within \(\mathbb{Q}(\sqrt{2})\).
Quadratic equations
In our exercises, examining if the roots of specific quadratic equations lie in \(\mathbb{Q}(\sqrt{2})\) is important.
- For the equation \(x^2 - 4x + \frac{7}{2} = 0\), the roots \(2.5\) and \(1.5\) are clearly rational and thus in \(\mathbb{Q}(\sqrt{2})\).
- The equation \(x^2 - 4x + 3 = 0\) gives roots \(3\) and \(1\), both rational, and thus also in \(\mathbb{Q}(\sqrt{2})\).
Field properties
- Closure: For any elements \(a+b\sqrt{2}\) and \(c+d\sqrt{2}\) in \(\mathbb{Q}(\sqrt{2})\), both their sum and product remain in \(\mathbb{Q}(\sqrt{2})\).
- Associativity and Commutativity: These hold as expected due to the properties of rational numbers, from which \(\mathbb{Q}(\sqrt{2})\) is derived.
- Identity: The additive identity is \(0 + 0\sqrt{2}\), while the multiplicative is \(1 + 0\sqrt{2}\).
- Inverses: Any non-zero element \(a+b\sqrt{2}\) has an inverse \(\frac{a-b\sqrt{2}}{a^2-2b^2}\), ensuring division is always possible.