Chapter 12: Problem 1
Solve the following systems by describing the solution sets completely: (a) $$ 2 x_{1}+x_{2}=3 \quad x_{1}+x_{2}+2 x_{3}=1 $$ $$ \begin{array}{lll} x_{1}-x_{2}=1 & \text { (c) } & x_{1}+2 x_{2}-x_{3}=-1 \\ 2 x_{1}+x_{2}+3 x_{3}=5 & & x_{1}+3 x_{2}+x_{3}=5 \\ \text { (b) } 4 x_{1}+x_{2}+2 x_{3}=-1 & & x_{1}-x_{2}+3 x_{3}=7 \end{array} $$ (d) $$ 8 x_{1}+2 x_{2}+4 x_{3}=-2 \quad x_{1}+3 x_{2}+x_{3}=4 $$
Short Answer
Step by step solution
Solving System (a)
Solving System (b)
Solving System (c)
Solving System (d)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solution Sets
- \( x_1 = 2x_3 + 2 \)
- \( x_2 = -4x_3 - 1 \)
- \( x_3 = x_3 \)
Inconsistencies
- Equation becomes: \[ 9 - 3x_3 = -1 \]
- Leading to: \[ 10 = -3x_3 \]
- Result: \[ x_3 = \frac{10}{3} \]
Solving Equations
- \( x_1 = -1 - 2x_2 + x_3 \)
Substitution Method
- Simplify equation: \( 4x_1 + x_2 + 2x_3 = -1 \)
- Isolate \( x_1: \)
- \( x_1 = -\frac{1}{4} - \frac{x_2}{4} - \frac{x_3}{2} \)