Chapter 11: Problem 1
Write out the group table of \(\mathbb{Z}_{2} \times \mathbb{Z}_{3}\) and find the two proper subgroups of this group.
Short Answer
Expert verified
The proper subgroups are \{ (0,0), (1,0) \} and \{ (0,0), (0,1), (0,2) \}.
Step by step solution
01
Understand the Group
The group \( \mathbb{Z}_2 \times \mathbb{Z}_3 \) is formed by the Cartesian product of \( \mathbb{Z}_2 \) and \( \mathbb{Z}_3 \). This means every element of the group is a pair, where the first element is from \( \mathbb{Z}_2 = \{0, 1\} \) and the second element is from \( \mathbb{Z}_3 = \{0, 1, 2\} \). Therefore, the elements of \( \mathbb{Z}_2 \times \mathbb{Z}_3 \) are \{ (0,0), (0,1), (0,2), (1,0), (1,1), (1,2) \}.
02
Construct the Group Table
To construct the group table, calculate the sum of every pair of elements by adding their individual components. Since \(\mathbb{Z}_2\) is modulo 2 and \(\mathbb{Z}_3\) is modulo 3, the addition is done as follows: - For element pairs \((a,b)\) and \((c,d)\), the result is \(((a+c)\mod 2, (b+d)\mod 3)\). Complete the table based on this rule—making sure each operation results in an element within the group.
03
Identify the Subgroups
A subgroup must contain the identity element \((0,0)\) and must be closed under group operation. 1. Consider the subgroup generated by \((1,0)\). Perform successive operations: - \((1,0) + (1,0) = (0,0)\). Thus, subgroup is \{ (0,0), (1,0) \}. 2. Consider the subgroup generated by \((0,1)\). Perform successive operations: - \((0,1) + (0,1) = (0,2)\), - \((0,1) + (0,1) + (0,1) = (0,0)\). Thus, subgroup is \{ (0,0), (0,1), (0,2) \}.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cartesian Product
The Cartesian product is a fundamental concept in group theory and mathematics in general. It represents the combination of two sets to create a new set of ordered pairs. In our context, we take two sets, \( \mathbb{Z}_2 \) and \( \mathbb{Z}_3 \), and combine them.
- **\( \mathbb{Z}_2 \)** is the set \( \{0, 1\} \), which represents integers under modulo 2 arithmetic.- **\( \mathbb{Z}_3 \)** is the set \( \{0, 1, 2\} \), which represents integers under modulo 3 arithmetic.
The Cartesian product, \( \mathbb{Z}_2 \times \mathbb{Z}_3 \), includes all possible ordered pairs where the first element comes from \( \mathbb{Z}_2 \) and the second from \( \mathbb{Z}_3 \). Thus, the elements of \( \mathbb{Z}_2 \times \mathbb{Z}_3 \) are \( \{ (0,0), (0,1), (0,2), (1,0), (1,1), (1,2) \} \).
This operation essentially combines two simpler systems into a more complex one, providing a richer structure for analysis.
- **\( \mathbb{Z}_2 \)** is the set \( \{0, 1\} \), which represents integers under modulo 2 arithmetic.- **\( \mathbb{Z}_3 \)** is the set \( \{0, 1, 2\} \), which represents integers under modulo 3 arithmetic.
The Cartesian product, \( \mathbb{Z}_2 \times \mathbb{Z}_3 \), includes all possible ordered pairs where the first element comes from \( \mathbb{Z}_2 \) and the second from \( \mathbb{Z}_3 \). Thus, the elements of \( \mathbb{Z}_2 \times \mathbb{Z}_3 \) are \( \{ (0,0), (0,1), (0,2), (1,0), (1,1), (1,2) \} \).
This operation essentially combines two simpler systems into a more complex one, providing a richer structure for analysis.
Modular Arithmetic
Modular arithmetic, often called "clock arithmetic," deals with numbers wrapped around upon reaching a certain value, the modulus. In group theory, modular arithmetic is crucial as it provides a way to work within finite sets.
- In the group \( \mathbb{Z}_2 \), numbers take on values of 0 or 1, and operations wrap around at 2. Thus, for any addition operation, the result modulo 2 is considered.- Similarly, in \( \mathbb{Z}_3 \), numbers can be 0, 1, or 2 with operations wrapping around at 3.
When creating a group table for \( \mathbb{Z}_2 \times \mathbb{Z}_3 \), you calculate the result for each pair by performing modular arithmetic on each component of the ordered pairs. Therefore, for the element pairs \((a,b)\) and \((c,d)\), the operation is:\[((a+b) \mod 2, (c+d) \mod 3)\]where you apply \( \mod 2 \) on the first components and \( \mod 3 \) on the second components, ensuring closure within the group.
- In the group \( \mathbb{Z}_2 \), numbers take on values of 0 or 1, and operations wrap around at 2. Thus, for any addition operation, the result modulo 2 is considered.- Similarly, in \( \mathbb{Z}_3 \), numbers can be 0, 1, or 2 with operations wrapping around at 3.
When creating a group table for \( \mathbb{Z}_2 \times \mathbb{Z}_3 \), you calculate the result for each pair by performing modular arithmetic on each component of the ordered pairs. Therefore, for the element pairs \((a,b)\) and \((c,d)\), the operation is:\[((a+b) \mod 2, (c+d) \mod 3)\]where you apply \( \mod 2 \) on the first components and \( \mod 3 \) on the second components, ensuring closure within the group.
Subgroup
A subgroup is a subset of a group that itself forms a group under the group operation. In the structure \( \mathbb{Z}_2 \times \mathbb{Z}_3 \), identifying subgroups involves checking several conditions:
- **Contains Identity**: Every subgroup must include the identity element of the parent group, which is \((0,0)\) in \( \mathbb{Z}_2 \times \mathbb{Z}_3 \).- **Closure Under Operation**: If you take any two elements from the subgroup and perform the group operation, the result must also be in the subgroup.- **Inverses**: Each element within the subgroup must have an inverse within the subgroup as well.
For example, the subgroup \( \{(0,0), (1,0)\} \) contains the identity and is closed under addition. Performing the operation \((1,0) + (1,0)\) returns \( (0,0) \), demonstrating closure.
Another example is \( \{(0,0), (0,1), (0,2)\} \), generated by \((0,1)\), which also satisfies all subgroup conditions due to modular arithmetic properties.
- **Contains Identity**: Every subgroup must include the identity element of the parent group, which is \((0,0)\) in \( \mathbb{Z}_2 \times \mathbb{Z}_3 \).- **Closure Under Operation**: If you take any two elements from the subgroup and perform the group operation, the result must also be in the subgroup.- **Inverses**: Each element within the subgroup must have an inverse within the subgroup as well.
For example, the subgroup \( \{(0,0), (1,0)\} \) contains the identity and is closed under addition. Performing the operation \((1,0) + (1,0)\) returns \( (0,0) \), demonstrating closure.
Another example is \( \{(0,0), (0,1), (0,2)\} \), generated by \((0,1)\), which also satisfies all subgroup conditions due to modular arithmetic properties.