Chapter 1: Problem 5
Rewrite the following without summation sign for \(n=3 .\) It is not necessary that you understand or expand the notation \(\left(\begin{array}{c}n \\\ k\end{array}\right)\) at this point. \((x+y)^{n}=\sum_{k=0}^{n}\left(\begin{array}{l}n \\ k\end{array}\right) x^{n-k} y^{k}\)
Short Answer
Expert verified
\((x+y)^3 = \binom{3}{0} x^3 + \binom{3}{1} x^2 y + \binom{3}{2} x y^2 + \binom{3}{3} y^3\).
Step by step solution
01
Identify the Values for the Summation
We are given the expression \((x+y)^n\) where \(n=3\). The goal is to replace the summation notation with an expanded form without the summation symbol, based on this value of \(n\).
02
Substitute the Value of n
Replace \(n=3\) in the given summation formula: \((x+y)^3 = \sum_{k=0}^{3} \binom{3}{k} x^{3-k} y^{k}\).
03
Expand the Summation
Write out the terms of the summation individually for each \(k\) from 0 to 3: - When \(k=0\), the term is \(\binom{3}{0} x^{3-0} y^0 = \binom{3}{0} x^3 y^0\).- When \(k=1\), the term is \(\binom{3}{1} x^{3-1} y^1 = \binom{3}{1} x^2 y^1\).- When \(k=2\), the term is \(\binom{3}{2} x^{3-2} y^2 = \binom{3}{2} x^1 y^2\).- When \(k=3\), the term is \(\binom{3}{3} x^{3-3} y^3 = \binom{3}{3} x^0 y^3\).
04
Write the Expanded Form Without the Summation Symbol
Combine all these individual terms to express the polynomial without the summation symbol:\[ (x+y)^3 = \binom{3}{0} x^3 y^0 + \binom{3}{1} x^2 y^1 + \binom{3}{2} x^1 y^2 + \binom{3}{3} x^0 y^3 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Expansion
In algebra, expansion is the process of expressing a mathematical expression in an extended form. This is particularly useful to simplify calculations and to make complicated expressions more manageable. For instance, when we have o the expression \[(x+y)^n\], we can expand it to express each term by using the Binomial Theorem. This theorem helps us to write polynomial expressions without using the summation notation. To expand \((x+y)^3\), we take each value of \(k\) one by one, from 0 to \(n\). For \(n=3\), we compute each term for \(k = 0, 1, 2, 3\). By doing this, we break down the problem into smaller parts, making it simpler to handle each component separately.
- When \(k=0\), the term is \(\binom{3}{0} x^3 y^0\).
- When \(k=1\), the term is \(\binom{3}{1} x^2 y^1\).
- When \(k=2\), the term is \(\binom{3}{2} x^1 y^2\).
- When \(k=3\), the term is \(\binom{3}{3} x^0 y^3\).
Binomial Coefficient
The term 'Binomial Coefficient' plays a key role in the expansion of binomial expressions. Represented by \(\binom{n}{k}\), it is essentially a value that tells us how many different ways we can choose \(k\) items from a total of \(n\) items. In the context of expanding \((x+y)^n\), it specifies the coefficient that each term of the expanded expression should have. For example, in \((x+y)^3\) expansion, each term's coefficient is determined by the following:
- \(\binom{3}{0} = 1\), which makes the first term \(1 \times x^3 y^0\).
- \(\binom{3}{1} = 3\), affecting the second term as \(3 \times x^2 y^1\).
- \(\binom{3}{2} = 3\), giving us the third term \(3 \times x^1 y^2\).
- \(\binom{3}{3} = 1\), rendering the last term \(1 \times x^0 y^3\).
Polynomial Expression
A Polynomial Expression is an algebraic expression made up of variables raised to whole number exponents, coefficients, and an addition of several terms. In simpler terms, it can be seen as a sum of various terms which are combined through addition or subtraction. When using the Binomial Theorem for expansion, a polynomial expression results from the expanded form of \((x+y)^n\). In the exercise, we expand \((x+y)^3\) into the polynomial:\[(x+y)^3 = \binom{3}{0} x^3 y^0 + \binom{3}{1} x^2 y^1 + \binom{3}{2} x^1 y^2 + \binom{3}{3} x^0 y^3 \]Each term in this polynomial expression is composed of the binomial coefficient, followed by the variable terms raised to appropriate powers, resulting in a simplified and usable form. For achieving this:
- The variable \(x\) is progressively decremented in power from the initial power of 3 to 0.
- Similarly, the variable \(y\) is incremented in power from 0 to 3.