Chapter 5: Problem 32
AREA BETWEEN CURVES In Exercises 31 through 38 , sketch the indicated region \(R\) and find its area by integration. \(R\) is the region under the curve \(y=e^{x}+e^{-x}\) over the interval \(-1 \leq x \leq 1\).
Short Answer
Expert verified
The area is \( 2(e - e^{-1}) \).
Step by step solution
01
Identify the curves and the interval
The function given is the exponential function: \[ y = e^{x} + e^{-x} \] The interval over which the area needs to be calculated is \[ -1 \text{ to } 1 \]
02
Sketch the region
Draw the graph of the function \( y = e^{x} + e^{-x} \) for the interval \( -1 \text{ to } 1 \). The function is symmetric about the y-axis and increases rapidly as \( x \to \ infty \).
03
Set up the integral for the area
The area under the curve can be found by integrating the function \( y = e^{x} + e^{-x} \) from \( x = -1 \text{ to } 1 \). The integral is: \[ A = \int_{-1}^{1} (e^{x} + e^{-x}) \, dx \]
04
Evaluate the integral
Evaluate the definite integral: \[ \int_{-1}^{1} e^{x} \, dx + \int_{-1}^{1} e^{-x} \, dx \]
05
Integrate each term separately
Calculate the integral of each exponential term separately: \[ \int_{-1}^{1} e^{x} \, dx = e^{x} \bigg|_{-1}^{1} = e^{1} - e^{-1} \] \[ \int_{-1}^{1} e^{-x} \, dx = -e^{-x} \bigg|_{-1}^{1} = -e^{-1} + e^{1} \]
06
Combine the results
Add the results of the integrals: \[ A = (e^{1} - e^{-1}) + (-e^{-1} + e^{1}) = 2(e^{1} - e^{-1}) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
definite integrals
A definite integral is a key concept in calculus. It helps us find the area under a curve over a particular interval. For example, in our exercise, we find the area under the curve of the function \( y = e^{x} + e^{-x} \) from \( x = -1 \) to \( x = 1 \). The notation for a definite integral looks like this: \[ A = \int_{-1}^{1} (e^{x} + e^{-x}) \, dx \] This integral tells us to find the sum of areas, or more specifically, the net area, between the curve and the x-axis, between the limits of integration which are -1 and 1.
Basic rules you'll need include:
Basic rules you'll need include:
- The Fundamental Theorem of Calculus, which links differentiation and integration.
- Setting up the integral based on the given function and interval.
exponential functions
Exponential functions are a type of mathematical function where the variable appears as an exponent. Common exponential functions include \( e^{x} \), where \( e \) is the base of natural logarithms (approximately 2.718). In this exercise, the function is \( y = e^{x} + e^{-x} \).
Key properties of exponential functions are:
Key properties of exponential functions are:
- They grow rapidly either positively or negatively, depending on whether the exponent is positive or negative.
- They are always positive for real values of x.
- They have an inverse called the logarithmic function.
graphical region analysis
Graphical region analysis involves sketching the curve given by a function and identifying regions of interest under the curve. For the function \( y = e^{x} + e^{-x} \), we focus on the interval \( -1 \leq x \leq 1 \). The following steps help in analyzing such regions:
- Draw the graph of the function within the given interval. Notice if the function is symmetric or has any particular shape which can simplify calculations.
- Shade the area under the curve between the specified interval. This highlighted region is where the area will be calculated using integration.
- Evaluate the definite integral to compute the total area of this region.