Chapter 4: Problem 9
\(4 \ln x=8\)
Short Answer
Expert verified
The solution is \( x = e^2 \).
Step by step solution
01
Understand the Equation
The given equation is \(4 \ln x = 8\). First, identify that it's an equation involving a logarithm.
02
Isolate the Natural Logarithm
Divide both sides of the equation by 4 to isolate \(\ln x\): \[ \frac{4 \ln x}{4} = \frac{8}{4} \] This simplifies to: \ln x = 2.
03
Exponentiate Both Sides
Since \(\ln x = 2\), exponentiate both sides using the base of the natural logarithm, which is e. Thus, \[ e^{\ln x} = e^2 \] Recall that \( e^{\ln x} = x \). Therefore, \[ x = e^2. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Logarithm
The natural logarithm, often denoted as \(\text{ln}\), is a logarithm to the base e, where e is an irrational constant approximately equal to 2.71828. It has unique properties that make it especially useful in calculus and solving certain types of equations.
When you see \(\text{ln} x\), it means the power to which e must be raised to obtain x. In other words, if \(\text{ln} x = y\), then \(\text{e}^y = x\).
Some key points to remember about the natural logarithm include:
Understanding these properties will help you manipulate and solve equations involving natural logarithms more efficiently.
When you see \(\text{ln} x\), it means the power to which e must be raised to obtain x. In other words, if \(\text{ln} x = y\), then \(\text{e}^y = x\).
Some key points to remember about the natural logarithm include:
- \(\text{ln}(1) = 0\) because \(e^0=1\)
- \(\text{ln}(e) = 1\) because \(e^1= e\)
- \(\text{ln}(a \times b) = \text{ln}(a) + \text{ln}(b)\)
- \(\text{ln}\bigg(\frac{a}{b}\bigg) = \text{ln}(a) - \text{ln}(b)\)
- \(\text{ln}(x^y) = y \times \text{ln}(x)\)
Understanding these properties will help you manipulate and solve equations involving natural logarithms more efficiently.
Exponential Function
The exponential function, denoted as \(e^x\), is one of the most important functions in mathematics, especially in calculus and complex analysis. It is the inverse function of the natural logarithm.
The function \(f(x) = e^x\) has several key characteristics:
One of the main reasons the exponential function is so critical is its relationship with the natural logarithm. If \(y = e^x\), then the natural logarithm of y (log base e) brings us back to x: \(\text{ln} y = x\). This inverse property is essential when solving logarithmic equations.
The function \(f(x) = e^x\) has several key characteristics:
- The rate of growth of \(e^x\) is proportional to its current value.
- The graph of \(e^x\) is always increasing and never touches the x-axis.
- It passes through the point (0,1) because \(e^0=1\).
- The derivative of \(e^x\) with respect to x is \(e^x\).
One of the main reasons the exponential function is so critical is its relationship with the natural logarithm. If \(y = e^x\), then the natural logarithm of y (log base e) brings us back to x: \(\text{ln} y = x\). This inverse property is essential when solving logarithmic equations.
Solving Logarithmic Equations
Solving logarithmic equations often requires the use of natural logarithms and exponential functions. Let’s take a closer look at solving the equation \(4 \text{ln} x = 8\).
Therefore, the solution to the equation is x=\text{e}^2. This method of solving works for many logarithmic equations. Always try to isolate the logarithm first and then exponentiate to solve for the variable.
- Step 1: Understand the Equation
The given equation involves a natural logarithm, and our goal is to isolate the variable x. - Step 2: Isolate the Natural Logarithm
Divide both sides by 4 to simplify the equation:
\(\frac{4 \text{ln} x}{4} = \frac{8}{4}\)
This reduces to \(\text{ln} x = 2\). - Step 3: Exponentiate Both Sides
Exponentiating both sides with base e helps us get rid of the natural logarithm:
\(e^{\text{ln} x} = e^2\)
We know that \(e^{\text{ln} x} = x\), so:
\(\text{x} = e^2\)
Therefore, the solution to the equation is x=\text{e}^2. This method of solving works for many logarithmic equations. Always try to isolate the logarithm first and then exponentiate to solve for the variable.