/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 If the random variable \(X\) is ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If the random variable \(X\) is normally distributed with mean \(\mu=7\) and standard deviation \(\sigma=2\), what is \(P(X \geq 9)\) ?

Short Answer

Expert verified
P(X \geq 9) = 0.1587.

Step by step solution

01

Convert to Standard Normal Variable

First, convert the normal variable to a standard normal variable (Z) using the formula: \[ Z = \frac{X - \mu}{\sigma} \] Here, \(X = 9\), \(\mu = 7\) and \(\sigma = 2\). Substitute these values into the formula to get: \[ Z = \frac{9 - 7}{2} = 1 \]
02

Find Z-Score Probability

Next, find the probability corresponding to \(Z=1\) using standard normal distribution tables or a calculator. Typically, \(P(Z < 1)\) is found to be 0.8413.
03

Calculate the Desired Probability

Since we need \(P(X \geq 9)\), which in terms of Z is \(P(Z \geq 1)\), recognize that \(P(Z \geq 1) = 1 - P(Z < 1)\). Using the value from Step 2, \[ P(Z \geq 1) = 1 - 0.8413 = 0.1587 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

standard normal variable
In statistics, a standard normal variable (denoted as Z) is essential for simplifying calculations involving normally distributed data. Normal distributions have variables with a specific mean and standard deviation. By converting these variables to standard normal variables, we can use just one standard normal distribution for all cases. This process is called standardization. Using the formula: \[ Z = \frac{X - \mu}{\sigma} \]we can convert any normal variable X into Z. Here, X is the original variable value, \mu is the mean, and \sigma is the standard deviation. This conversion helps when comparing different datasets or determining probabilities involving normal distributions.
Z-score
The Z-score represents how many standard deviations a data point is from its mean. It's a critical concept in statistics for comparing data. By determining Z, you can easily understand where a specific value lies within a normal distribution. The formula is simple: \[ Z = \frac{X - \mu}{\sigma} \].
For example, to find the Z-score for X = 9 when the mean \mu is 7 and \sigma is 2, you get: \[ Z = \frac{9 - 7}{2} = 1 \].
This Z-score tells you that 9 is exactly one standard deviation above the mean. Understanding Z-scores simplifies working with probability tables and helps in comparing different datasets.
probability calculation
Once you've found the Z-score, you can calculate probabilities. For any given Z value, standard normal distribution tables or online calculators give the probability of a variable being less than the Z value. This is denoted as \( P(Z < z) \).
Looking at standard normal distribution tables, the probability for \( Z = 1 \) is 0.8413. This means there's an 84.13% chance that a value is less than 1 standard deviation above the mean.
To find the probability of a value being greater than a Z value (\(P(Z \geq z) \)), subtract the table value from 1:
\[ P(Z \geq 1) = 1 - P(Z < 1) = 1 - 0.8413 = 0.1587 \].
Thus, for our example, there's a 15.87% chance that a value is greater than one standard deviation above the mean.
mean and standard deviation
The mean \mu and standard deviation \sigma are fundamental concepts in statistics that describe a dataset. The mean is the average value of a dataset and gives a central location of the data.
Standard deviation describes the spread of data around the mean, indicating how dispersed the values are. A smaller standard deviation means the data points are close to the mean, while a larger standard deviation indicates more variability.
In our example, the mean \mu is 7, and the standard deviation \sigma is 2. To find the probability of \( X \geq 9 \) where \mu = 7 and \sigma = 2, convert X to a Z-score and find the corresponding probability. This conversion and probability calculation are essential in understanding where the data point lies within the distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a number \(c\) so that the following function \(f(x)\) is a probability density function: $$ f(x)= \begin{cases}\frac{c}{x^{4}} & \text { if } x \geq 1 \\ 0 & \text { otherwise }\end{cases} $$

JOURNALISM Suppose that the number of typographical errors on a page of a local newspaper follows a Poisson distribution with an average of \(2.5\) errors per page. a. Find the probability that a randomly selected page is free from typographical errors. b. Find the probability that a randomly selected page has at least one typographical error. c. Find the probability that a randomly selected page has at least three typographical errors. d. Find the probability that a randomly selected page has fewer than three typographical errors.

PEDIATRICS There are 200 children in a certain school, and the weight of the children is a random variable \(X\) that is normally distributed with mean \(\mu=80\) pounds and standard deviation \(\sigma=7\) pounds. a. How many children weigh more than 90 pounds? b. How many children weigh less than 70 pounds? c. How many children weigh exactly 80 pounds?

MEDICINE Suppose that the number of children who die each year from leukemia follows a Poisson distribution and that on average, \(7.3\) children per 100,000 die from leukemia. For a city with 100,000 children, find the probability of each of the following events: a. Exactly seven children in the city die from leukemia each year. b. Fewer than two children in the city die from leukemia each year. c. More than five children in the city die from leukemia each year.

In each of Exercises 3 through 6 , determine whether the given random variable \(X\) is discrete or continuous. \(X\) measures the annual distance flown by a randomly selected airplane from a particular airline.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.