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Either find the given limit or show it does not exist. If the limit is infinite, indicate whether it is \(+\infty\) or \(-\infty\). $$ \lim _{x \rightarrow-\infty} \frac{x^{3}-3 x+5}{2 x+3} $$

Short Answer

Expert verified
+\infty

Step by step solution

01

- Identify Dominant Terms

Examine the given function's numerator and denominator. For large negative values of x, the dominant term in the numerator is \(x^3\) and the dominant term in the denominator is \(2x\).
02

- Simplify the Expression

Divide both the numerator and the denominator by the highest power of x present in the denominator. So, divide by x:equation: \[\lim_{x \rightarrow -\infty} \frac{x^3/x - 3x/x + 5/x}{2x/x + 3/x}\] which simplifies to \[ \lim_{x \rightarrow -\infty} \frac{x^2 - 3 + 5/x}{2 + 3/x} \]
03

- Evaluate the Limit

For \(x \rightarrow -\infty\), the term \(\frac{5}{x}\) approaches 0, as does \(\frac{3}{x}\). Therefore, the limit becomes:equation: \[ \lim_{x \rightarrow -\infty} \frac{x^2 - 3}{2} \]
04

- Determine the Behavior of x^2

Notice that \(x^2\) is always positive and grows larger as \(x\) becomes more negative. Therefore, as \(x \rightarrow -\infty\), \(x^2\) approaches \(+\infty\).
05

- Conclude the Result

Since the term \( \frac{x^2 - 3}{2} \) will grow infinitely large because \(x^2\) dominates and the subtraction of 3 has negligible effect at infinity, the limit is:equation: \[ \lim_{x \rightarrow -\infty} \frac{x^3 - 3x + 5}{2x + 3} = +\infty \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Limits
When we talk about infinite limits, we deal with functions that do not approach a real number as the variable grows indefinitely in the positive or negative direction. Instead, the function increases or decreases without bound. For example, if you consider the simple function \(f(x) = x^2\), you'll notice that as \(x \rightarrow +\infty\), \(f(x) \rightarrow +\infty\). This also applies when examining negative directions. Understanding infinite limits helps us determine the behavior of functions in extreme conditions.

For the problem at hand, we are given a rational function \(\frac{x^{3}-3x+5}{2x+3}\) and need to find its limit as \(x \rightarrow-\infty\). When \(x\) grows very negative, the function's terms do not settle at a finite value, guiding us to the conclusion of either \(+\infty\) or \(-\infty\).

This process of examining infinite limits is crucial, especially in rational functions where dominance of terms plays a significant role.
Rational Functions
Rational functions are fractions where both the numerator and the denominator are polynomials. The general form is \(\frac{P(x)}{Q(x)}\), where both \(P(x)\) and \(Q(x)\) are polynomials. Analyzing these functions involves understanding how the degrees (largest exponent terms) of the polynomials influence the behavior of the function.

In the given exercise, the rational function is \(\frac{x^3 - 3x + 5}{2x + 3}\). We observe that the numerator is a cubic polynomial (degree 3), while the denominator is a linear polynomial (degree 1). The degrees of these polynomials determine how the function behaves as \(x \rightarrow \pm \infty\).

Since the degree of the numerator is higher than that of the denominator, the function's behavior will reflect the dominant term in the numerator over powers of \(x\). This mismatch in degrees leads us to scrutinize the highest powers in each part of the fraction.
Dominant Terms
Dominant terms are the terms in a polynomial that have the highest power of the variable, often the ones that dictate the behavior of the function as the variable grows very large or very small. For example, in \(x^3 - 3x + 5\), \(x^3\) is the dominant term as it has the highest exponent. Similarly, \(2x\) is dominant in \(2x + 3\).

When simplifying a rational function to find its limit, we focus on these dominant terms. Here’s why: Dominant terms grow the fastest compared to other terms. This property means that for large values of \(x\) (positive or negative), lesser terms like \(-3x\) or \(+5\) in the numerator, and \(+3\) in the denominator, become negligible. They do not significantly alter the end behavior of the function.

In the exercise, we identified \(x^3\) and \(2x\) as dominant. This leads us to simplify the function by dividing every term by \(x\), resulting in the simplified limit as \(x \rightarrow -fty\). Consequently, this analysis simplifies our understanding and solves the limit efficiently.

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Most popular questions from this chapter

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Either find the given limit or show it does not exist. If the limit is infinite, indicate whether it is \(+\infty\) or \(-\infty\). $$ \lim _{x \rightarrow 0^{-}}\left(x^{3}-\frac{1}{x^{2}}\right) $$

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