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Find the general solution of each differential equation or state that the differential equation is not separable. If the exercise says "and check," verify that your answer is a solution. $$ y^{\prime}=(a y+b)^{2} \quad \text { (for constants } a \neq 0 \text { and } \left.b\right) $$

Short Answer

Expert verified
The general solution is \( y = -\frac{1}{a(ax + C)} - \frac{b}{a} \).

Step by step solution

01

Identify the Nature of the Differential Equation

The given differential equation is \( y' = (ay + b)^2 \), which appears to be a first-order, nonlinear equation. We will attempt to determine if the equation is separable.
02

Express in Separable Form

To check for separability, we attempt to rewrite the equation in the form \( g(y) \, dy = f(x) \, dx \). Here, the function of \( y \) given by \( (ay + b)^2 \) is initially unclear if it can be directly separated, so let's perform algebraic manipulation.
03

Substitute and Rearrange

Substitute \( y' \) as \( \frac{dy}{dx} \), resulting in \( \frac{dy}{dx} = (ay + b)^2 \). This can be rearranged to \( \frac{dy}{(ay + b)^2} = dx \). Now, the equation is in a separable form.
04

Integrate Both Sides

Integrate both sides: \[ \int \frac{dy}{(ay+b)^2} = \int dx \]. The left integral evaluates to \( -\frac{1}{a(ay+b)} + C_1 \), whereas the right becomes \( x + C_2 \).
05

Solve for the Constant of Integration

Combine the constants of integration into a single constant \( C \), thus obtaining \( -\frac{1}{a(ay+b)} = x + C \). Manipulate to solve for \( y \).
06

Solve for y

Rearrange to solve for \( y \): \[ y = -\frac{1}{a(ax + C)} - \frac{b}{a} \]. This represents the general solution of the differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

First-Order Differential Equations
First-order differential equations involve functions and their first derivatives. These equations describe the rate of change of a function.
They are crucial in modeling real-world systems where change is dependent on only the current state, like Newton’s law of cooling or population growth.
First-order differential equations can be written in the general form: \[ \frac{dy}{dx} = f(x, y) \] This form shows that the change in \( y \) regarding \( x \) depends on both \( x \) and \( y \).
Such equations can be linear or nonlinear based on the form of \( f(x, y) \). Linear equations have the form where \( f(x, y) = ax + by + c \).
In our exercise, the equation \( y' = (ay + b)^2 \) is nonlinear due to the squared term. Solving these equations often requires specific techniques like separation or integrating factors.
The primary goal is usually to find the function \( y \) that satisfies the differential equation for given boundary or initial conditions.
Nonlinear Differential Equations
Nonlinear differential equations are those in which the relationship between the variable and its derivatives is not linear. Simply put, any equation in which the terms higher than first-degree appear or involve products of the variables or their derivatives is nonlinear.
They can model complex and chaotic systems such as weather prediction, fluid dynamics, or biological systems. In equations like \( y' = (ay + b)^2 \), nonlinearity is clear because \( (ay + b)^2 \) involves squaring a function of \( y \).
This makes the problem more complex, requiring specific solutions techniques like numerical methods, perturbation methods, or in specific cases, exact analytical techniques.
While these equations can pose challenges, they also represent a more realistic approach to modeling real-world phenomena. Breaking them down into simpler, solvable forms, or using computer simulations, often aids in tackling these equations.
Understanding the coherence in its structure helps predict and manage the outcomes or resolution paths of correlated systems.
Separable Differential Equations
Separable differential equations are a special class where the equation's variables can be rewritten such that all terms involving one variable can be moved to one side of the equation, leaving all terms involving the other variable on the opposite side.
This allows us to integrate each side separately to solve the equation. An equation can be expressed as separable if it can be transformed into the form:\[ g(y) \, dy = f(x) \, dx \] The example \( y' = (ay + b)^2 \) was successfully shown to be separable after expressing it as \( \frac{dy}{(ay + b)^2} = dx \).
This separates \( y \) and terms involving it from \( x \), allowing us to integrate both sides effectively.
By integrating, we find a relationship between \( x \) and \( y \), leading towards the solution.
Due to its ease once identified, separable equations often appear in foundational differential equation studies and various applied problems where solutions can be directly calculated.

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Most popular questions from this chapter

Solve each differential equation with the given initial condition. $$ \begin{array}{l} y^{\prime}+4 y=e^{-3 x} \\ y(0)=4 \end{array} $$

For each initial value problem: a. Use an Euler's method graphing calculator program to find the estimate for \(y(2)\). Use the interval [0,2] with \(n=50\) segments. b. Solve the differential equation and initial condition exactly by separating variables or using an integrating factor. c. Evaluate the solution that you found in part (b) at \(x=2\). Compare this actual value of \(y(2)\) with the estimate of \(y(2)\) that you found in part (a). $$ \begin{array}{l} \frac{d y}{d x}=-y \\ y(0)=1 \end{array} $$

The following problems extend and augment the material presented in the text. BIOMEDICAL: Fick's Law Fick's Law governs the diffusion of a solute across a cell membrane. According to Fick's Law, the concentration \(y(t)\) of the solute inside the cell at time \(t\) satisfies \(\frac{d y}{d t}=\frac{k A}{V}\left(C_{0}-y\right),\) where \(k\) is the diffusion constant, \(A\) is the area of the cell membrane, \(V\) is the volume of the cell, and \(C_{0}\) is the concentration outside the cell. a. Find the general solution of this differential equation. (Your solution will involve the constants \(k, A, V\) and \(C_{0}\).) b. Find the particular solution that satisfies the initial condition \(y(0)=y_{0},\) where \(y_{0}\) is the initial concentration inside the cell.

Solve each differential equation with the given initial condition. $$ \begin{array}{l} y^{\prime}-3 x^{2} y=6 x^{2} \\ y(0)=1 \end{array} $$

A 10,000 -cubic-foot-room has an initial radon level of \(800 \mathrm{pCi}\) (picocuries) per cubic foot. A ventilation system is installed that each hour brings in 500 cubic feet of outside air (containing \(5 \mathrm{pCi}\) per cubic foot), while an equal volume of air leaves the room. Assume that the air in the room mixes thoroughly. a. Find a differential equation and initial condition that govern the total amount \(y(t)\) of radon in the room after \(t\) hours. b. Solve this differential equation and initial condition. c. Graph the solution on a graphing calculator and find how soon the radon level will fall to the EPA safety level of \(112 \mathrm{pCi}\) per cubic foot.

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