Chapter 9: Problem 16
Find the general solution of each differential equation or state that the differential equation is not separable. If the exercise says "and check," verify that your answer is a solution. $$ y^{\prime}=e^{x}+y $$
Short Answer
Expert verified
The general solution is \( y = e^{x}(x + C) \).
Step by step solution
01
Analyze the Equation for Seperability
The given differential equation is \( y' = e^x + y \). To determine if the equation is separable, we check if it can be rearranged to the form \( g(y) dy = h(x) dx \). For this, we attempt to isolate terms involving \( y \) on one side and terms involving \( x \) on the other side. However, \( y' = e^x + y \) cannot be rearranged in this way. Thus, the equation is non-separable.
02
Recognize the Type of Differential Equation
Since the equation is not separable, let's check its form. The equation is linear of the form \( y' - y = e^x \), which suggests using the integrating factor method applicable to linear first-order differential equations.
03
Compute the Integrating Factor
For a linear differential equation \( y' - y = e^x \), the integrating factor \( \mu(x) \) is given by \( e^{\int P(x) \, dx} \) where \( P(x) = -1 \). So, the integrating factor is \( e^{-\int 1 \, dx} = e^{-x} \).
04
Multiply Through by the Integrating Factor
Multiply the entire differential equation by the integrating factor \( e^{-x} \):\[ e^{-x} y' - e^{-x} y = e^{x} e^{-x} \]This simplifies to:\[ e^{-x} y' - e^{-x} y = 1 \]
05
Recognize the Left Side as a Derivative
The left-hand side of the equation \( e^{-x} y' - e^{-x} y \) is the derivative of \( (e^{-x} y) \). Therefore, the equation can be rewritten as:\[ \frac{d}{dx}(e^{-x} y) = 1 \]
06
Integrate Both Sides
Integrate both sides with respect to \( x \):\[ \int \frac{d}{dx}(e^{-x} y) \, dx = \int 1 \, dx \]This integration yields:\[ e^{-x} y = x + C \] where \( C \) is the constant of integration.
07
Solve for y
To find the general solution, multiply both sides by \( e^{x} \):\[ y = e^{x}(x + C) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Differential Equations
A linear differential equation is an equation involving a function and its derivatives. These types of equations can typically be written in the form of \( y' + P(x)y = Q(x) \). The equation is considered linear because the dependent variable \( y \) and its derivative \( y' \) appear with a degree of one and are not multiplied together. Linear differential equations are significant because they are one of the simplest types of differential equations that can be solved analytically.
- First-order linear differential equations only involve the first derivative of the unknown function.
- They are accessible to solve using different techniques, with the integrating factor method being particularly common.
Integrating Factor Method
The integrating factor method is a powerful technique used to solve linear first-order differential equations. The idea is to multiply the entire differential equation by a special function, called the integrating factor, which simplifies the equation into an easily integrable form. This method is particularly useful for equations that are not separable.
- The standard form for applying this method is \( y' + P(x)y = Q(x) \).
- The integrating factor, \( \mu(x) \), is calculated as \( e^{\int P(x) \; dx} \).
Non-separable Differential Equations
Differential equations can sometimes be categorized as separable or non-separable. A separable differential equation can be written so that all terms involving the dependent variable \( y \) are on one side and all terms involving the independent variable \( x \) are on the other. Non-separable equations, as the name suggests, do not allow for such simple separation.
- Separable equations can be solved by direct integration after rearrangement.
- Non-separable equations require alternative methods, like the integrating factor method, for solutions.