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Find the total differential of each function. $$ g(x, y)=\sqrt{x^{2}+y^{2}} $$

Short Answer

Expert verified
The total differential is \( dg = \frac{x}{\sqrt{x^2 + y^2}} dx + \frac{y}{\sqrt{x^2 + y^2}} dy. \)

Step by step solution

01

Understanding the Function

The function given is a multivariable function: \( g(x, y) = \sqrt{x^2 + y^2} \). We need to find the total differential of this function, which involves taking partial derivatives with respect to both \( x \) and \( y \).
02

Finding Partial Derivatives

First, find \( \frac{\partial g}{\partial x} \). Apply the chain rule to the expression \( \sqrt{x^2 + y^2} \): \[ \frac{\partial}{\partial x} (x^2 + y^2)^{1/2} = \frac{1}{2}(x^2 + y^2)^{-1/2} \cdot 2x = \frac{x}{\sqrt{x^2 + y^2}}. \] Now find \( \frac{\partial g}{\partial y} \): \[ \frac{\partial}{\partial y} (x^2 + y^2)^{1/2} = \frac{1}{2}(x^2 + y^2)^{-1/2} \cdot 2y = \frac{y}{\sqrt{x^2 + y^2}}. \]
03

Constructing the Total Differential

The total differential, \( dg \), is given by: \[ dg = \frac{\partial g}{\partial x} dx + \frac{\partial g}{\partial y} dy. \] Substitute the partial derivatives found: \[ dg = \frac{x}{\sqrt{x^2 + y^2}} dx + \frac{y}{\sqrt{x^2 + y^2}} dy. \] This is the expression for the total differential of \( g(x, y) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
In multivariable calculus, understanding partial derivatives is crucial when dealing with functions of several variables. Given a function like \( g(x, y) = \sqrt{x^2 + y^2} \), partial derivatives help describe how the function changes as each variable is altered, while keeping the others constant. This is different from single-variable calculus, where we look at the change with respect to one variable alone.To find a partial derivative, we differentiate with respect to one variable, treating all other variables as constants. For example:
  • To compute \( \frac{\partial g}{\partial x} \), we differentiate \( \sqrt{x^2 + y^2} \) treating \( y \) as a constant. The result is \( \frac{x}{\sqrt{x^2 + y^2}} \).
  • Similarly, \( \frac{\partial g}{\partial y} \) is found by differentiating with respect to \( y \), keeping \( x \) constant, resulting in \( \frac{y}{\sqrt{x^2 + y^2}} \).
Partial derivatives are foundational to understanding how functions behave in a multidimensional space and are used in a variety of applications, from optimization problems to modeling real-world systems.
Total Differential
The total differential is a concept that combines the partial derivatives of a multivariable function to approximate changes in the function's value due to small changes in the variables. For a function \( g(x, y) \), the total differential is given by:\[ dg = \frac{\partial g}{\partial x} dx + \frac{\partial g}{\partial y} dy \]This formula essentially adds up all the partial changes, weighted by how much each variable changes (represented by \( dx \) and \( dy \)). It's an extension of the idea of differentials from single-variable calculus.For instance, we derived earlier:
  • \( \frac{\partial g}{\partial x} = \frac{x}{\sqrt{x^2 + y^2}} \)
  • \( \frac{\partial g}{\partial y} = \frac{y}{\sqrt{x^2 + y^2}} \)
Using these, the total differential \( dg \) is:\[ dg = \frac{x}{\sqrt{x^2 + y^2}} dx + \frac{y}{\sqrt{x^2 + y^2}} dy \]The total differential provides an approximation of the function's change and is particularly useful in problems involving linear approximations and error estimation.
Chain Rule
The chain rule is an important differentiation technique used in calculus to deal with composite functions. In the context of multivariable calculus, the chain rule is particularly useful when functions are in nested forms or when multiple variables are involved in the differentiation process.For the function \( g(x, y) = \sqrt{x^2 + y^2} \), we encountered a composition where \((x^2 + y^2)\) sits inside \( \sqrt{\cdot} \). The chain rule helped us differentiate these nested layers effectively:
  • When calculating \( \frac{\partial g}{\partial x} \), applying the chain rule gives an intermediate step of multiplying the derivative of the outside (square root) by the derivative of the inside \((x^2 + y^2)\).
  • Similarly for \( \frac{\partial g}{\partial y} \).
The result of these applications provides \( \frac{x}{\sqrt{x^2 + y^2}} \) and \( \frac{y}{\sqrt{x^2 + y^2}} \), showing clearly how the chain rule unpacks the differentiation of composite and multivariable expressions step-by-step.Using the chain rule efficiently can simplify complex differentiation tasks, making it an essential tool for anyone working in calculus and mathematical modeling.

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