Chapter 7: Problem 6
Find the total differential of each function. $$ g(x, y)=\frac{x}{x+y} $$
Short Answer
Expert verified
dz = \frac{y}{(x+y)^2} \, dx + \frac{-x}{(x+y)^2} \, dy.
Step by step solution
01
Understand the Total Differential
The total differential of a function of two variables, say a function \( z = g(x, y) \), is given by: \( dz = rac{\partial g}{\partial x} \, dx + rac{\partial g}{\partial y} \, dy \). This means we need to find the partial derivatives of \( g(x, y) \) with respect to \( x \) and \( y \).
02
Find the Partial Derivative with Respect to x
Differentiate \( g(x, y) = \frac{x}{x+y} \) with respect to \( x \), treating \( y \) as constant. Using the quotient rule, we have:\[\frac{\partial g}{\partial x} = \frac{(x+y) \cdot 1 - x \cdot 1}{(x+y)^2} = \frac{y}{(x+y)^2}.\]
03
Find the Partial Derivative with Respect to y
Differentiate \( g(x, y) = \frac{x}{x+y} \) with respect to \( y \), treating \( x \) as constant. Also use the quotient rule, which gives:\[\frac{\partial g}{\partial y} = \frac{(x+y) \cdot 0 - x \cdot 1}{(x+y)^2} = \frac{-x}{(x+y)^2}.\]
04
Write the Total Differential
Using the results from Steps 2 and 3, write the total differential as:\[ dz = \frac{y}{(x+y)^2} \, dx + \frac{-x}{(x+y)^2} \, dy.\] This is the expression for the total differential of the given function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Derivatives
In multivariable calculus, a partial derivative represents the rate at which a function changes as one of its variables is varied, while keeping the other variables constant. It's like focusing on one direction of change at a time. For a function \( g(x, y) \), the partial derivative with respect to \( x \) is denoted as \( \frac{\partial g}{\partial x} \), and it signifies how \( g \) changes as \( x \) changes, with \( y \) fixed.
- To find \( \frac{\partial g}{\partial x} \), treat \( y \) as a constant.
- To find \( \frac{\partial g}{\partial y} \), treat \( x \) as a constant.
Multivariable Calculus
Multivariable calculus extends the concepts of calculus to functions with more than one variable. It includes learning about functions like \( g(x, y) \) where both \( x \) and \( y \) can vary, offering a richer view of how systems change in response to different inputs.
- In single-variable calculus, we focus on functions of one variable, looking at how they change as their single input varies.
- In multivariable calculus, we deal with multi-dimensional spaces, exploring functions of two or more variables.
Quotient Rule
When dealing with functions defined by a fraction, the quotient rule is a powerful tool for differentiation. It allows us to find the derivative of a ratio of two functions, which is essential for problems like finding partial derivatives in our given function \( g(x, y) = \frac{x}{x+y} \).
Let's break down the quotient rule:
Let's break down the quotient rule:
- The rule states: \( \frac{d}{dx} \left( \frac{u}{v} \right) = \frac{v \cdot u' - u \cdot v'}{v^2} \), where \( u \) and \( v \) are functions of \( x \).
- For \( g(x, y) \), set \( u(x) = x \) and \( v(x) = x+y \).
- The derivatives are \( u'(x) = 1 \) and \( v'(x) = 1 \) if differentiating with respect to \( x \), and \( v'(y) = 1 \) if differentiating with respect to \( y \).