Chapter 6: Problem 65
True or False: If \(f(x)\) is continuous, nonnegative, and \(\lim _{x \rightarrow \infty} f(x)=0,\) then \(\int_{1}^{\infty} f(x) d x\) converges.
Short Answer
Expert verified
False, a counterexample (e.g., \(f(x) = \frac{1}{x}\)) shows divergence.
Step by step solution
01
Understanding the Problem
We need to determine if the statement is true or false: "If \(f(x)\) is continuous, nonnegative, and \(\lim _{x \rightarrow \infty} f(x)=0,\) then \(\int_{1}^{\infty} f(x) d x\) converges." This involves analyzing the behavior of an improper integral based on the behavior of a function.
02
Review Key Concepts
Recall that for an improper integral \(\int_{1}^{\infty} f(x) \, dx\) to converge, the function \(f(x)\) must approach zero fast enough as \(x\) approaches infinity. A limit at infinity of zero alone does not guarantee convergence.
03
Counterexample Exploration
Consider the function \(f(x) = \frac{1}{x}\). This function is continuous, nonnegative, and \(\lim_{x \rightarrow \infty} \frac{1}{x} = 0\). However, the integral \(\int_{1}^{\infty} \frac{1}{x} \, dx\) is known to diverge.
04
Evaluate the Counterexample
Evaluate the integral \(\int_{1}^{\infty} \frac{1}{x} \, dx\). We find \(\int_{1}^{t} \frac{1}{x} \, dx = [\ln(x)]_1^t = \ln(t) - \ln(1) = \ln(t)\). As \(t\) approaches infinity, \(\ln(t)\) goes to infinity, demonstrating the integral diverges.
05
Conclusion
Since \(f(x) = \frac{1}{x}\) meets all conditions but results in a divergent integral, the statement is false. The fact that \(f(x)\) approaches 0 is not sufficient for ensuring the convergence of the integral.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
continuity
Continuity is a fundamental concept in calculus and is essential when analyzing functions and their integrals. A function is continuous if its graph has no breaks, jumps, or holes. In formal terms, for a function \( f(x) \) to be continuous at a point \( x = a \), it must satisfy three conditions:
- The function \( f(x) \) is defined at \( x = a \).
- The limit of \( f(x) \) as \( x \) approaches \( a \) exists.
- The limit of \( f(x) \) as \( x \) approaches \( a \) is equal to \( f(a) \).
divergence
Divergence occurs when an integral does not settle at a finite value as its bounds extend to infinity. Even if a function \( f(x) \) is continuous, nonnegative, and approaches zero as \( x \) approaches infinity, this does not necessarily mean the integral converges. In the exercise, we explore
- a counterexample with \( f(x) = \frac{1}{x} \).
- This function meets all the initial conditions.
limits at infinity
Limits at infinity focus on understanding the behavior of a function as the input \( x \) grows larger and larger beyond all bounds. When we say \( \lim_{x \to \infty} f(x) = L \), it means as \( x \) becomes very large, \( f(x) \) gets arbitrarily close to \( L \). In improper integrals, these limits help us explore if the area under a curve extends infinitely or settles at a finite value.
- In the exercise, \( \lim_{x \to \infty} f(x) = 0 \) suggests that the function value decreases continuously toward zero.
- However, the critical mistake is assuming this always results in a convergent integral.