Chapter 5: Problem 49
Find each integral. [Hint: Try some algebra.] $$ \int(x+1)^{2} x^{3} d x $$
Short Answer
Expert verified
\( \int (x+1)^2 x^3 \, dx = \frac{x^6}{6} + \frac{2x^5}{5} + \frac{x^4}{4} + C \)
Step by step solution
01
Expand the Integrand
First, expand \((x + 1)^2\) using the polynomial expansion. \[(x+1)^2 = x^2 + 2x + 1\] Now replace this in the integral:\[ \int (x^2 + 2x + 1) x^3 \, dx \] This simplifies to:\[\int (x^5 + 2x^4 + x^3) \, dx \]
02
Split the Integral
Split the integral into separate integrals for each term:\[\int x^5 \, dx + \int 2x^4 \, dx + \int x^3 \, dx\]
03
Integrate Each Term
Each of these integrals is a basic polynomial integral:- For \int x^5 \, dx\, apply the power rule \((n+1)\):\[ \frac{x^6}{6} + C_1\]- For \int 2x^4 \, dx\:\[\frac{2x^5}{5} + C_2\] - For \int x^3 \, dx\:\[\frac{x^4}{4} + C_3\]
04
Combine the Results
Combine the results from Step 3:\[\frac{x^6}{6} + \frac{2x^5}{5} + \frac{x^4}{4} + C\]Combine constants \(C_1\), \(C_2\), and \(C_3\) into one constant \(C\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Expansion
Polynomial expansion is a fundamental technique in algebra that you use to express a power of a binomial as a polynomial. In the given problem, you need to expand \((x+1)^2\). This is achieved by multiplying \((x + 1)\) by itself: \[(x+1) \times (x+1) = x^2 + 2x + 1\]. This expansion results in three distinct terms, each representing a different power of \(x\). The next step involves distributing \(x^3\) over each term of the expanded polynomial, thus allowing you to create individual terms that are simple enough to integrate later.
- Step 1: Multiply \(x^3\) with \(x^2\), \(2x\), and \(1\) to get \(x^5 + 2x^4 + x^3\).
Power Rule
The power rule is a basic and powerful tool in calculus for finding the derivative and integral of terms raised to a power. In integration, it allows you to integrate terms of the form \(x^n\). The power rule states that for any real number \(n\), except \(n = -1\), the integral of\(x^n\) is \((x^{n+1}/(n+1)) + C\), where \(C\) is the constant of integration.
The power rule makes it simple to integrate polynomial functions by dealing with each term individually. In this exercise:
The power rule makes it simple to integrate polynomial functions by dealing with each term individually. In this exercise:
- For \(\int x^5 \, dx\): apply the rule (where \(n = 5\)), to get \(\frac{x^6}{6}\).
- For \(\int 2x^4 \, dx\): use \(2\) as a constant multiplier, so it remains, giving \(\frac{2x^5}{5}\).
- Finally for \(\int x^3 \, dx\), applying the rule yields \(\frac{x^4}{4}\).
Basic Polynomial Integral
Integrating polynomials is a building block skill in calculus, where you find the antiderivative of polynomial expressions. We use the power rule here, as it provides a straightforward way to integrate each term individually.
In this problem, once the polynomial \((x+1)^2 x^3\) is expanded using polynomial expansion, it results in simpler terms, \(x^5, 2x^4,\) and \(x^3\). Each of these terms can be integrated independently using their respective power rules. By integrating each separate term:
In this problem, once the polynomial \((x+1)^2 x^3\) is expanded using polynomial expansion, it results in simpler terms, \(x^5, 2x^4,\) and \(x^3\). Each of these terms can be integrated independently using their respective power rules. By integrating each separate term:
- Integrating \(x^5\) results in \(\frac{x^6}{6}\).
- Integrating \(2x^4\) results in \(\frac{2x^5}{5}\).
- Integrating \(x^3\) results in \(\frac{x^4}{4}\).