Chapter 5: Problem 11
Find each indefinite integral. \(\int 6 e^{2 x / 3} d x\)
Short Answer
Expert verified
\( \int 6 e^{2x/3} \, dx = 9e^{2x/3} + C \)
Step by step solution
01
Identify the Type of Integral
The given integral \( \int 6 e^{2x/3} \, dx \) is an indefinite integral involving an exponential function. We need to apply the integration rule for exponential functions.
02
Set Up Substitution
Let \( u = \frac{2x}{3} \), then \( du = \frac{2}{3} \, dx \), which implies \( dx = \frac{3}{2} \, du \). This substitution will simplify the integral.
03
Substitute and Simplify
Substitute \( u \) and \( dx \) into the integral: \[ \int 6 e^{2x/3} \, dx = \int 6 e^u \times \frac{3}{2} \, du \]This simplifies to: \[ 9 \int e^u \, du \]
04
Integrate the Exponential Function
The integral of \( e^u \) with respect to \( u \) is simply \( e^u \). Therefore:\[ 9 \int e^u \, du = 9e^u + C \]where \( C \) is the constant of integration.
05
Substitute Back the Original Variable
Replace \( u \) back with \( \frac{2x}{3} \):\[ 9e^{2x/3} + C \] is the antiderivative with the original variable.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are crucial in mathematics and natural sciences. These functions have a constant base raised to a variable exponent. In an expression like \(e^{2x/3}\), the base \(e\) is a mathematical constant approximately equal to 2.71828, and the exponent \(\frac{2x}{3}\) makes it an exponential function.
This kind of function is powerful because of its unique rates of growth and decay, appearing frequently in real-world phenomena such as population growth, radioactive decay, and interest calculations.
This kind of function is powerful because of its unique rates of growth and decay, appearing frequently in real-world phenomena such as population growth, radioactive decay, and interest calculations.
- Exponential functions have the general form \(f(x) = a e^{bx}\), where \(a\) and \(b\) are constants.
- The derivative of an exponential function \(e^x\) is itself \(e^x\).
- The integral of \(e^x\) is also \(e^x\), plus a constant of integration \(C\).
Substitution Method
The substitution method is a highly effective technique in integral calculus. It involves transforming a complex integral into a simpler form, making it easier to evaluate. Think of it as changing variables to simplify the task at hand.
The idea is to choose a new variable \(u\) to replace a part of the integrand. For instance, in our exercise, \(u = \frac{2x}{3}\). The derivative \(du\) is then computed to express the original variable in terms of \(u\).
The idea is to choose a new variable \(u\) to replace a part of the integrand. For instance, in our exercise, \(u = \frac{2x}{3}\). The derivative \(du\) is then computed to express the original variable in terms of \(u\).
- Choose a substitution that simplifies the integral, often an inner function of a composite function.
- Adjust \(dx\) to \(du\) using the relationship like \(dx = \frac{3}{2} \, du\).
- Rewrite the integral in terms of \(u\) to make the integration process easier.
Integration Techniques
Integration techniques are methods used to solve integrals, whether they are indefinite or definite. Having a grip on various techniques can simplify and solve a wide range of integral problems efficiently. Let's review some crucial integration techniques:
- Basic Integration: Involves basic rules like the power rule and direct integration of functions, such as exponential functions.
- Substitution: A powerful method for dealing with composite functions, as demonstrated in our exercise, wherein \(dx\) is expressed in terms of \(du\).
- Integration by Parts: Useful for integrals that are products of functions, based on the product rule of differentiation.