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Chapter 5: Problem 1

Find each indefinite integral. \(\int x^{4} d x\)

Short Answer

Expert verified
The integral of \\(x^4\\) is \\(\frac{x^5}{5} + C\\).

Step by step solution

01

Identify the Integral Type

This integral is in the form of \(\int x^n \, dx\), where \(n\) is a constant. This is a basic power rule integral.
02

Apply the Power Rule for Integration

According to the power rule, the integral of \(x^n\) with respect to \(x\) is \(\frac{x^{n+1}}{n+1} + C\), where \(C\) is the constant of integration.
03

Substitute the Power

Here, \(n = 4\), so substituting into the formula, we get \((n+1) = 5\). Therefore, the integral becomes \(\frac{x^{5}}{5} + C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Integration
The power rule for integration is one of the first tools you'll learn in calculus, specifically for handling polynomials. It allows you to find the antiderivative of power functions, which are of the form \(x^n\), where \(n\) is any real number. To use it, you increase the exponent \(n\) by one and divide by the new exponent, thus the indefinite integral of \(x^n\) is \(\frac{x^{n+1}}{n+1} + C\). The \(+ C\) represents the constant of integration because indefinite integrals produce a family of functions.

Key points to remember include:
  • Always check the form of the expression to ensure it's suitable for the power rule.
  • The rule doesn't work for \(n = -1\) since division by zero is undefined; this is a special case handled by the natural logarithm function.
  • Don鈥檛 forget the constant of integration, \(C\), as it reflects the indefinite nature of the integral.
Basic Calculus
Calculus itself is the study of change and it comes in two primary branches: differential calculus and integral calculus. Indefinite integrals fall under the umbrella of integral calculus, which is concerned with finding antiderivatives or the reverse process of differentiation.

When working with indefinite integrals, you aren't trying to find a specific value. Instead, you are looking for a general formula or function that describes a class of possible solutions.

Important aspects of basic calculus in this context:
  • An antiderivative is a function whose derivative equals the original function you started with.
  • The process of integration is essentially the reverse of differentiation.
  • Indefinite integrals are represented without bounds and thus include the arbitrary constant \(C\).
Integration Techniques
In addition to the power rule, there are various integration techniques to solve different types of functions. Each technique is designed to handle different forms and complexity of polynomial expressions. Two frequently used techniques are:
  • Substitution: Useful when an integral contains a function and its derivative. By substituting a part of the function with a single variable, the integral becomes simpler to solve.
  • Integration by Parts: This technique is based on the product rule for differentiation and applies to integrals of products of functions. It helps break down complex integrals into simpler parts.
Understanding when and how to apply these techniques improves your calculus skills and enables you to tackle a wider variety of integral problems efficiently.

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Most popular questions from this chapter

Evaluate \(\int_{1}^{1} \frac{x^{43} e^{-17 x}+219 \sqrt[3]{x^{2}}}{\ln \sqrt[29]{6 x^{3}-x^{-11}}-\pi^{3}} d x .\) [Hint: No work necessary.

An aircraft company estimates its marginal revenue function for helicopters to be \(M R(x)=(x+40) \sqrt{x^{2}+80 x}\) thousand dollars, where \(x\) is the number of helicopters sold. Find the total revenue from the sale of the first 10 helicopters.

A friend says that if you can move numbers across the integral sign, you can do the same for variables since variables stand for numbers, and in this way you can always "fix" the differential \(d u\) to be what you want. Is your friend right?

On a hot summer afternoon, a city's electricity consumption is \(-3 t^{2}+18 t+10\) units per hour, where \(t\) is the number of hours after noon \((0 \leq t \leq 6) .\) Find the total consumption of electricity between the hours of 1 and \(5 \mathrm{p} \cdot \mathrm{m}\)

Find the derivative of each function. \(e^{x^{2}+5 x}\)
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