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33-62. Sketch the graph of each rational function after making a sign diagram for the derivative and finding all relative extreme points and asymptotes. $$ f(x)=\frac{3 x+6}{x-2} $$

Short Answer

Expert verified
The graph of \( f(x) = \frac{3x+6}{x-2} \) has a vertical asymptote at \( x = 2 \) and a horizontal asymptote at \( y = 3 \), and is decreasing everywhere.

Step by step solution

01

Determine the Asymptotes

Identify the vertical and horizontal asymptotes for the function. A vertical asymptote occurs where the denominator equals zero. For \( f(x) = \frac{3x + 6}{x - 2} \), set \( x - 2 = 0 \) which gives a vertical asymptote at \( x = 2 \). Horizontal asymptotes are determined by the ratio of the leading coefficients. Since the degrees of the numerator and denominator are equal, the horizontal asymptote is \( y = \frac{3}{1} = 3 \).
02

Find the Critical Points

Calculate the derivative of the function to find critical points. The derivative \( f'(x) \) is obtained using the quotient rule: \[ f'(x) = \frac{(x-2)(3) - (3x+6)(1)}{(x-2)^2} = \frac{3x - 6 - 3x - 6}{(x-2)^2} = \frac{-12}{(x-2)^2} \]The derivative is never zero since \(-12\) is a constant, but it is undefined at \( x = 2 \), the point of the vertical asymptote.
03

Analyze the Derivative Sign

Since \( f'(x) = \frac{-12}{(x-2)^2} \) is negative for all \( x eq 2 \), the function is decreasing everywhere except at \( x = 2 \) where it is undefined. There are no critical points where the derivative equals zero, indicating no local extremum.
04

Sketch the Graph

To sketch the graph, plot the vertical asymptote at \( x = 2 \) and the horizontal asymptote at \( y = 3 \). Since the function is decreasing for all intervals, check behavior near the asymptotes: as \( x \) approaches 2 from the left, \( f(x) \to -\infty \); as \( x \to 2^+ \), \( f(x) \to +\infty \). As \( x \to -\infty \) or \( x \to +\infty \), \( f(x) \to 3 \). The left and right of the asymptote \( x = 2 \) need to be drawn along these trends.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Asymptotes
In calculus and graphing, asymptotes represent lines that a graph approaches but never touches. For rational functions like \( f(x)=\frac{3x+6}{x-2} \), identifying asymptotes is crucial for understanding their behavior.
- **Vertical Asymptotes**: These occur when the denominator of the function is zero because division by zero is undefined. For our function, setting \( x - 2 = 0 \) gives a vertical asymptote at \( x = 2 \).
- **Horizontal Asymptotes**: These describe the behavior as \( x \) approaches infinity. Since the degree of the numerator and denominator are the same, the horizontal asymptote is determined by the ratio of the leading coefficients, resulting in \( y = 3 \).
Asymptotes greatly influence the sketch of the graph, acting as guiding lines that the curve will get infinitely close to but never actually cross.
Derivative Sign Analysis
Analyzing the sign of the derivative \( f'(x) \) helps in understanding the function's behavior across its domain. The derivative tells us where the function is increasing or decreasing.
For \( f(x)=\frac{3x+6}{x-2} \), we find that \( f'(x) = \frac{-12}{(x-2)^2} \) is negative for all \( x eq 2 \). Since the denominator \((x-2)^2 \) is always positive (squared terms are non-negative), the negative sign of the numerator \(-12\) means \( f'(x) \) is always negative, indicating that the function decreases everywhere except where the derivative is undefined at \( x = 2 \).
This consistent sign reveals that there are no intervals of increase and the function does not have any relative extremes other than at the asymptote.
Critical Points Identification
The search for critical points involves finding where the derivative \( f'(x) \) is zero or undefined. These points often correspond to local maxima, minima, or points of inflection.
In our function \( f(x)=\frac{3x+6}{x-2} \), \( f'(x) = \frac{-12}{(x-2)^2} \) is never zero because the numerator is a constant non-zero value, \(-12\). This indicates there are no critical points where the slope of the tangent is zero.
However, \( f'(x) \) is undefined at \( x = 2 \), aligning with our vertical asymptote rather than a typical critical point like a peak or trough. Therefore, this function lacks any traditional critical points or relative extreme values, simplifying the graphing process.
Rational Functions
Rational functions are ratios of two polynomials and can often define complex shapes with interesting properties. In our example, \( f(x) = \frac{3x+6}{x-2} \), the structure of the function indicates several features:
- **Asymptotes**: The denominator helps define vertical asymptotes, while the degrees of numerator and denominator guides horizontal ones.
- **Behaviors & Patterns**: The polynomial terms in the numerator and denominator interact to influence growth or decay, creating sticking points like \( x=2 \).
Rational functions are versatile, appearing in diverse applications from physics to finance, because they model situations where rates or relationships change smoothly, controlled by the underlying polynomials.

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Most popular questions from this chapter

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