/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Fill in the blank: If a function... [FREE SOLUTION] | 91Ó°ÊÓ

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Fill in the blank: If a function is decreasing on a closed interval, then an upper bound for its value is its value at the \(\longrightarrow\) -hand endpoint of the interval.

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Step by step solution

01

Understanding the Problem

We need to determine where the value of a decreasing function will be the highest on a closed interval. Since the function is decreasing, its value decreases as we move along the interval from one endpoint to the other.
02

Analyzing the Properties of Decreasing Functions

For a function that is decreasing on an interval, the function's value at any point is greater than or equal to its value at subsequent points. This means that the maximum value within the interval occurs at the start of the interval.
03

Identifying the Endpoints

A closed interval is typically defined with two endpoints, often labeled as left and right: \[ [a, b] \] where \(a\) is the left endpoint and \(b\) is the right endpoint.
04

Determining the Right Answer

Since the function is decreasing and the greatest value occurs at the beginning, the upper bound for the function's value is its value at the left-hand endpoint of the interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Closed Interval
In mathematics, an interval refers to a set of real numbers lying between two endpoints. A closed interval is a special type of interval where both endpoints are included. It is denoted with square brackets like this: \[ [a, b] \] This notation means that the interval starts at \(a\) and ends at \(b\), including both \(a\) and \(b\) as part of the interval.
This inclusion is important because it means the function can take on values at these endpoints too. When analyzing functions on closed intervals, we consider how the function behaves between and at these two points. Knowing this can help determine where maximum and minimum function values occur, especially when the function is either decreasing or increasing. Understanding the concept of a closed interval is crucial for figuring out upper and lower bounds of function values within that range.
It helps us pinpoint where to look for these critical values, especially if the function is either strictly increasing or decreasing.
Function Value
The function value is essentially the output of a function given an input from its domain. When you have a specific function, like \(f(x)\), and you input a value \(x\), the function processes this input and produces a corresponding output, \(f(x)\).
This output is what we call the function value at that point.For instance, in a mathematical function stated as \(f(x) = 3x + 1\), if we input \(x = 2\), the function value is calculated as:\[f(2) = 3(2) + 1 = 7\]In the context of closed intervals, understanding function values is important to determine boundaries, like the maximum or minimum values that a function can take on within that interval.
For a decreasing function, knowing that function values drop as \(x\) increases, helps us locate the maximum function value at the beginning of the interval. It simplifies the search for the upper bound of function values within the interval.
Upper Bound
The term "upper bound" refers to the greatest value that a function can achieve within a specific domain or interval. When dealing with decreasing functions, identifying the upper bound can provide great insight into the function's behavior.
For a decreasing function on a closed interval like \( [a, b] \), the values of the function decrease as you move from the left endpoint \(a\) to the right endpoint \(b\).This means that the highest value—or the upper bound—of the function value occurs at the left endpoint. The function value at this point is not surpassed within the interval, given the function's decreasing nature.So, if you have a function that is decreasing on \([2, 5]\), the upper bound of this function on this interval is simply the function's value at \(x = 2\), providing a clear limit or cap for the function's output.
Understanding this concept in the context of decreasing functions aids in mathematical reasoning and problem-solving by clearly defining constraints and expectations on function behavior.

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