/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 What is an upper bound for the a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is an upper bound for the absolute value of \(a n y\) derivative of \(f(x)=\sin x\) on any interval?

Short Answer

Expert verified
The upper bound is 1.

Step by step solution

01

Understand the Function and Its Derivatives

The function in question is \( f(x) = \sin x \). The derivative of \( f(x) \) is \( f'(x) = \cos x \), the second derivative is \( f''(x) = -\sin x \), the third derivative is \( f'''(x) = -\cos x \), and they continue in a cyclical pattern. The pattern for the nth derivative is \( f^{(n)}(x) = \sin x \) or \( \cos x \) or their negatives. All of these functions (\( \sin x \) and \( \cos x \) and their negatives) have known absolute maximum values on any interval.
02

Determine the Maximum Value of Derivatives

The absolute value of both \( \sin x \) and \( \cos x \) is always less than or equal to 1 for any x, as both functions oscillate between -1 and 1. Thus, the maximum value of the absolute value of any derivative of \( f(x) = \sin x \), considering the periodic nature of sine and cosine functions, is 1.
03

Justify the Upper Bound

Since all derivatives of \( \sin x \), whether \( \sin x \) or \( \cos x \) or their negatives, have an absolute value that cannot exceed 1, the upper bound for the absolute value of any derivative of \( f(x) = \sin x \) is clearly 1. This holds true for any interval because these trigonometric functions' max and min values do not exceed ±1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Upper Bound in Calculus
An upper bound in calculus refers to the greatest value that a function or its derivative can achieve over a specific interval. For trigonometric functions like sine and cosine, identifying an upper bound is crucial for understanding their behavior. The derivatives of these functions exhibit a predictable cyclic pattern, which leads to a consistent upper bound across any interval.
Consider the function \( f(x) = \sin x \). Its first few derivatives are:
  • \( f'(x) = \cos x \)
  • \( f''(x) = -\sin x \)
  • \( f'''(x) = -\cos x \)
This pattern continues indefinitely, switching back and forth between \( \sin x \) and \( \cos x \) and their negatives. Each of these functions has an absolute maximum value of 1, regardless of the interval, as their values oscillate between -1 and 1. Hence, the upper bound of any derivative of \( \sin x \) is 1.
Sine and Cosine Functions
Sine and cosine functions are fundamental in trigonometry and calculus. Their characteristics are essential for understanding periodic behavior, as they repeat their values in a rhythmic cycle. Both \( \sin x \) and \( \cos x \) complete a full cycle of their values from 0 to 2\( \pi \), where:
  • \( \sin(0) = 0 \) and peaks at \( 1 \) at \( \pi/2 \)
  • \( \cos(0) = 1 \) and decreases to \( 0 \) at \( \pi/2 \)
The important property of these functions is that they are bounded between -1 and 1, which directly influences the maximum absolute values of their derivatives. The peaks (maximum and minimum values) of these functions mean that any trigonometric derivative does not exceed these bounds.
Calculus Derivatives
Calculus derivatives allow us to determine the rate of change of a function with respect to a variable. Trigonometric derivatives, like those of \( \sin x \) and \( \cos x \), are especially interesting due to their rotational properties and periodic behavior.
When we differentiate \( \sin x \), we get \( \cos x \), and differentiating \( \cos x \) gives \( -\sin x \). This cyclic derivative pattern demonstrates how trigonometric functions transition smoothly from one to the other, emphasizing their interconnectedness. Each derivative returns back to the original function after four differentiations, i.e., \( f^{(4)}(x) = \sin x \).
This sequence of derivatives remains consistent, confirming that the oscillating nature of \( \sin x \) and \( \cos x \)—bounded by -1 and 1—provides a straightforward framework for analyzing and predicting their behavior in calculus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

BIOMEDICAL: Long-Term Population A population (of cells or people) is such that each year a number \(a\) of individuals are added (call them "immigrants"), and a proportion \(p\) of the individuals who have been there die. Therefore, the proportion that survives is \((1-p),\) so that just after an immigration the population will consist of new immigrants plus \(a(1-p)\) from the previous year's immigration plus \(a(1-p)^{2}\) from the immigration before that, and so on. In the long run, the size of the population just after an immigration will then be the sum \(a+a(1-p)+a(1-p)^{2}+a(1-p)^{3}+\cdots\) If the number of immigrants each year is 800 and the survival proportion is \(0.95,\) find the long-run size of the population just after an immigration. Then find the long-run size just before an immigration.

Use the Ratio Test to show that the Taylor series \(\sin x=\sum_{n=0}^{\infty} \frac{(-1)^{n} x^{2 n+1}}{(2 n+1) !}\) converges for all \(x\)

Find the Taylor series at \(x=0\) for each function by calculating three or four derivatives and using the definition of Taylor series. \(\cos 2 x\)

Find the Taylor series at \(x=0\) for each function by modifying one of the Taylor series from this section. \(\frac{e^{x}-1}{x}\)

a. GENERAL: Saving Pennies You make a New Year's resolution to save pennies, promising to save on successive days \(1 \Phi, 2 \phi, 4 \notin, 8 \Phi,\) and so on, doubling the number each day throughout January. How much will you have saved by the end of January? b. (Graphing calculator with series operations helpful) How many days will it take for the savings to reach a million dollars?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.