/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Write out each finite series. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write out each finite series. $$ \sum_{i=1}^{5} \frac{1}{i+1} $$

Short Answer

Expert verified
\( \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} \)

Step by step solution

01

Understand the Sigma Notation

The symbol \( \sum \) indicates summation, meaning that we need to add up a series of terms. The expression given is \( \sum_{i=1}^{5} \frac{1}{i+1} \), which means we will replace \( i \) with each integer from 1 through 5, calculating \( \frac{1}{i+1} \) for each value of \( i \), and then add them together.
02

Substitute Values into the Expression

We need to substitute each value of \( i \) from 1 to 5 into the expression \( \frac{1}{i+1} \):1. For \( i=1 \), the term becomes \( \frac{1}{1+1} = \frac{1}{2} \).2. For \( i=2 \), the term becomes \( \frac{1}{2+1} = \frac{1}{3} \).3. For \( i=3 \), the term becomes \( \frac{1}{3+1} = \frac{1}{4} \).4. For \( i=4 \), the term becomes \( \frac{1}{4+1} = \frac{1}{5} \).5. For \( i=5 \), the term becomes \( \frac{1}{5+1} = \frac{1}{6} \).
03

Write Out the Finite Series

With the expressions for each term worked out, write down the entire finite series as:\[ \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sigma Notation
In mathematics, the capital Greek letter \( \Sigma \) is used to denote summation. This means you are adding a collection of numbers together. When you see an expression written as \( \sum_{i=1}^{5} \frac{1}{i+1} \), it tells you to sum up a series of terms. Each term is obtained by substituting values of \( i \) from the starting index, in this case, 1, to the end index, which is 5. After evaluating the expression for each value of \( i \), the resulting numbers are added together.

The general formula looks like:
\( \sum_{i=a}^{b} f(i) \), meaning evaluate the function \( f(i) \) from \( i=a \) to \( i=b \). Using sigma notation is a concise way to represent long sums, helping you avoid writing long lists of additions.
Summation
Summation is the process of adding a sequence of numbers; the result is their sum. In the context of finite series, like our example where you see the formula \( \sum_{i=1}^{5} \frac{1}{i+1} \), summation involves calculating each term's value from the sequence and adding these values together.

Let's break it down:
  • Calculate each term by substituting the specific values into the expression.
  • Summate or add all these results together.
In the example given, once you've substituted the values of \( i \) into \( \frac{1}{i+1} \), the terms become \( \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \frac{1}{6} \). The final summation is the addition of all these fractions, resulting in a finite series.
Substitution
Substitution is a fundamental step in evaluating series, where each term is determined by replacing a variable with actual numbers. In the case of our exercise, the expression \( \frac{1}{i+1} \) requires you to substitute \( i \) with each integer from the starting to the ending index specified in the summation notation.
  • Start with \( i=1 \), calculate \( \frac{1}{1+1} = \frac{1}{2} \).
  • Next, substitute \( i=2 \), yielding \( \frac{1}{2+1} = \frac{1}{3} \).
  • Continue this process for \( i=3, 4, 5 \).
This method ensures each term in the series is accurately calculated before being summed.

Substitution helps you transform a general expression into specific numerical terms needed for the summation.
Series Expression
A series expression represents the total of all terms calculated from a sequence. After substituting the values and performing the required calculations for each term, you sum them all to form the series. In our example, the series becomes: \[ \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} \].

Key points to consider about series expressions include:
  • It's the culmination of evaluating the summation expression for a specified range.
  • The result is a finite sum since there are only a limited number of terms in our sequence.
Series expressions elegantly summarize lengthy repetitive addition, often seen in calculus and discrete mathematics. Understanding how to evaluate and express these calculates is essential for deeper math comprehension.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

True or False: If the partial sums \(S_{n}\) of an infinite series all satisfy \(S_{n}<1,\) then the sum \(S\) also satisfies \(\quad S<1\)

Let \(a\) be a given number and suppose that the function \(f\) is \(n+1\) times differentiable between \(a\) and \(x\). Since \(a\) and \(x\) are now fixed, we will use \(t\) for a variable taking values between them. $$ \begin{aligned} &\text { Show that }\\\ &\begin{array}{l} \int_{a}^{x} f^{(k+1)}(t) \cdot(x-t)^{k} d t \\ =\frac{1}{k+1}(x-a)^{k+1} f^{(k+1)}(a) \\ \quad+\frac{1}{k+1} \int_{a}^{x} f^{(k+2)}(t) \cdot(x-t)^{k+1} d t \end{array} \end{aligned} $$ $$ \begin{aligned} &\text { for } 1

$$ \begin{aligned} &\text { How many terms are in the following finite geometric }\\\ &\text { series? } 2+2 \cdot 3+2 \cdot 3^{2}+\cdots+2 \cdot 3^{5280} \end{aligned} $$

PERSONAL FINANCE: Payments (Graphing calculator with series operations helpful) A person gives you \(\$ 1,\) waits 1 minute, gives you another dollar, waits 2 minutes, gives you another dollar, waits four minutes, etc., doubling the wait each time. How much money will you have at the end of the first year?

(Requires sequence and series operations) a. Use your calculator to find \(e^{2}\) rounded to six decimal places. b. The Taylor series for \(e^{x}\) evaluated at \(x=2\) gives \(e^{2}=\sum_{n=0}^{\infty} \frac{2^{n}}{n !}\). Set your calculator to find the sum of this series up to any number of terms. How many terms are required for the sum (rounded to six decimal places) to agree with your answer to part (a)?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.