/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Find the slope (if it is defined... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the slope (if it is defined) of the line determined by each pair of points. $$ (-4,0) \text { and }(2,2) $$

Short Answer

Expert verified
The slope of the line is \(\frac{1}{3}\).

Step by step solution

01

Understand the Slope Formula

The slope of a line given two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated using the formula:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]where \(m\) represents the slope of the line.
02

Plug in the Coordinates of the Points

Substitute the given points \((-4, 0)\) and \((2, 2)\) into the slope formula. Here, \(x_1 = -4, y_1 = 0, x_2 = 2,\) and \(y_2 = 2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Calculation
The slope of a line is a measure of its steepness and is represented by the letter \( m \). To find the slope between two points, you use the slope formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \). This equation takes the vertical change (difference in the \( y \)-coordinates) and divides it by the horizontal change (difference in the \( x \)-coordinates). This ratio tells us how much the line rises for each unit it runs.When you plug in the coordinates of the points
  • Point 1: \((-4, 0)\)
  • Point 2: \((2, 2)\)
we substitute them into the formula:\[ m = \frac{2 - 0}{2 - (-4)} \]This calculation gives:\[ m = \frac{2}{6} = \frac{1}{3} \]Thus, the slope of the line that connects these two points is \( \frac{1}{3} \). The positive value indicates that the line ascends from left to right.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, connects algebra with geometry through graphs and coordinates. It allows us to represent geometric figures like lines and curves using coordinate planes.
This branch of mathematics utilizes a system where every point is defined by ordered pairs \((x, y)\), known as coordinates.This method is highly versatile. It helps in solving geometric problems algebraically and visualizing algebraic equations geometrically.
  • The horizontal line on the plane is the \( x \)-axis.
  • The vertical line is the \( y \)-axis.
  • The intersection point where both meet is the origin, \((0,0)\).
When given a pair of points, like in our exercise, coordinate geometry makes it possible to find the slope, distances, and midpoint values easily. Understanding this concept is crucial as it forms the foundation for more complex topics in mathematics.
Linear Equations
Linear equations are algebraic expressions that form straight lines when plotted on a graph. They are typically written in the standard format \( y = mx + c \), where:
  • \( m \) represents the slope of the line
  • \( x \) is the independent variable
  • \( y \) is the dependent variable
  • \( c \) is the y-intercept, which is the point where the line crosses the \( y \)-axis
Linear equations are fundamental because they describe a constant rate of change between two variables, making them useful in numerous real-life applications. For example, understanding distances, speed relations, or predicting trends.In our exercise, after finding the slope \( \frac{1}{3} \) using the two points given, one could further develop the full linear equation of the line passing through those points by using one point and the slope-intercept form \( y = mx + c \). With this capability, the power of linear equations becomes apparent as it permits prediction and analysis of linear relationships efficiently.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

ATHLETICS: Juggling If you toss a ball \(h\) feet straight up, it will return to your hand after \(T(h)=0.5 \sqrt{h}\) seconds. This leads to the juggler's dilemma: Juggling more balls means tossing them higher. However, the square root in the above formula means that tossing them twice as high does not gain twice as much time, but only \(\sqrt{2} \approx 1.4\) times as much time. Because of this, there is a limit to the number of balls that a person can juggle, which seems to be about ten. Use this formula to find: a. How long will a ball spend in the air if it is tossed to a height of 4 feet? 8 feet? b. How high must it be tossed to spend 2 seconds in the air? 3 seconds in the air?

If an object is thrown upward so that its height (in feet) above the ground \(t\) seconds after it is thrown is given by the function \(h(t)\) below, find when the object hits the ground. That is, find the positive value of \(t\) such that \(h(t)=0 .\) Give the answer correct to two decimal places. [Hint: Enter the function in terms of \(x\) rather than \(t .\) Use the ZERO operation, or TRACE and ZOOM IN, or similar operations. $$ h(t)=-16 t^{2}+40 t+4 $$

93 -94. ALLOMETRY: Heart Rate It is well known that the hearts of smaller animals beat faster than the hearts of larger animals. The actual relationship is approximately (Heart rate) \(=250(\text { Weight })^{-1 / 4}\) where the heart rate is in beats per minute and the weight is in pounds. Use this relationship to estimate the heart rate of: A 16 -pound \(\operatorname{dog}\).

\(87-88 .\) ALLOMETRY: Dinosaurs The study of size and shape is called "allometry," and many allometric relationships involve exponents that are fractions or decimals. For example, the body measurements of most four-legged animals, from mice to elephants, obey (approximately) the following power law: $$ \left(\begin{array}{c} \text { Average body } \\ \text { thickness } \end{array}\right)=0.4 \text { (hip-to-shoulder length) }^{3 / 2} $$ where body thickness is measured vertically and all measurements are in feet. Assuming that this same relationship held for dinosaurs, find the average body thickness of the following dinosaurs, whose hip-toshoulder length can be measured from their skeletons: Diplodocus, whose hip-to-shoulder length was 16 feet.

Write each expression in power form \(a x^{b}\) for numbers \(a\) and \(b\). $$ \sqrt[3]{\frac{8}{x^{6}}} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.