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\(53-56 .\) Use a graphing calculator to evaluate each expression. \(\left[(0.1)^{0.1}\right]^{0.1}\)

Short Answer

Expert verified
The value of the expression is approximately 0.9772.

Step by step solution

01

Understand the Expression

The expression given is \( \left[(0.1)^{0.1}\right]^{0.1} \). We are dealing with powers and exponents, and we will evaluate it using a calculator.
02

Simplify the Inner Exponent

First, calculate the inner exponent \((0.1)^{0.1}\). This represents raising 0.1 to the power of 0.1.
03

Calculate Using a Graphing Calculator

Use a graphing calculator to evaluate \( (0.1)^{0.1} \). Enter 0.1 and use the power function to raise it to 0.1. The result is approximately 0.7943.
04

Evaluate the Outer Exponent

Now, calculate \( 0.7943^{0.1} \). Use the graphing calculator again to raise the result from the previous step to the power of 0.1.
05

Obtain Final Result

The result of \( 0.7943^{0.1} \) calculated using the calculator is approximately 0.9772.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponents
Exponents confuse many, but understanding them is key to mastering mathematics. An exponent indicates how many times a number, known as the base, is multiplied by itself. For instance, in the expression \( a^b \), \( a \) is the base and \( b \) is the exponent. This means you multiply \( a \) by itself \( b \) times. For example, \( 2^3 \) equals \( 2 \times 2 \times 2 = 8 \). This simple operation can be expanded to work with any real number, even fractions or decimals.

Exponents follow specific rules, such as:
  • Product of powers: \( a^m \times a^n = a^{m+n} \)
  • Power of a power: \( (a^m)^n = a^{mn} \)
  • Power of a product: \( (ab)^n = a^n \times b^n \)
By understanding these rules, you can simplify expressions and solve more complex problems effectively.
Powers
Powers are closely related to exponents and often the terms are used interchangeably in mathematics.When you see a power, you're looking at a number determined by raising a base to a particular exponent.

For example, when we write \( 3^4 \), "3" is the base, and "4" is the exponent or power, meaning \( 3 \) is multiplied by itself four times: \( 3 \times 3 \times 3 \times 3 = 81 \).

Powers are handy in various real-life applications, like computing interest rates or describing growth patterns. They provide a concise way to express repeated multiplication, making calculations more straightforward and efficient in both math and science.

In complex expressions, such as \( ext{{ig[}}(0.1)^{0.1} ext{{ig]}}^{0.1} \), each power plays a role in achieving the final result. Calculating such expressions often requires a calculator due to the precision needed.
Step by Step Calculation
Breaking down complex expressions into manageable steps is crucial in mathematics problem-solving. Take the expression \( ext{{ig[}}(0.1)^{0.1} ext{{ig]}}^{0.1} \) as an example.

The first step is focusing on the inner power: calculate \( 0.1^{0.1} \). This step itself may require using a calculator, as it involves a fractional exponent.

Once the inner part is simplified, move on to the next layer by evaluating \( 0.7943^{0.1} \), again utilizing the calculator for accuracy. Each stage builds upon the previous, showing the structure of complex expressions.

By mastering step-by-step calculations, you build confidence, ensuring consistent accuracy with your results in more difficult problems.
Mathematics Problem Solving
Effective problem-solving in mathematics often blends creativity with structured methodology. It involves identifying the problem, applying relevant mathematical principles, and using tools like calculators when necessary.

To tackle the expression \( ext{{ig[}}(0.1)^{0.1} ext{{ig]}}^{0.1} \), it's essential to understand each component: exponents, powers, and precision use of a calculator.

Calculators simplify complex arithmetic, but knowing which calculations to perform provides clarity and purpose. Approaching problems methodically, with a step-by-step plan, aids understanding and ensures you reach an accurate solution.

Developing such skills requires practice and exposure to small errors, which can illuminate learning opportunities and deepen comprehension of mathematical concepts.

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Most popular questions from this chapter

GENERAL: Earthquakes The sizes of major earthquakes are measured on the Moment Magnitude Scale, or MMS, although the media often still refer to the outdated Richter scale. The MMS measures the total energy relensed by an earthquake, in units denoted \(M_{W}\) (W for the work accomplished). An increase of \(1 M_{W}\) means the energy increased by a factor of \(32,\) so an increase from \(A\) to \(B\) means the energy increased by a factor of \(32^{B-A}\). Use this formula to find the increase in energy between the following earthquakes: The 2001 earthquake in India that measured \(7.7 M_{W}\) and the 2011 earthquake in Japan that measured \(9.0 M_{W}\). (The earthquake in Japan generated a 28 -foot tsunami wave that traveled six miles inland, killing 24,000 and causing an estimated \(\$ 300\) billion in damage, making it the most expensive natural disaster ever recorded.)

Should \(\sqrt{9}\) be evaluated as 3 or \(\pm 3 ?\)

BUSINESS: Isoquant Curves An isoquant curve (iso means "same" and quant is short for "quantity") shows the various combinations of labor and capital (the invested value of factory buildings, machinery, and raw materials) a company could use to achieve the same total production level. For a given production level, an isoquant curve can be written in the form \(K=a L^{b}\) where \(K\) is the amount of capital, \(L\) is the amount of labor, and \(a\) and \(b\) are constants. For each isoquant curve, find the value of \(K\) corresponding to the given value of \(L\). $$ K=4000 L^{-2 / 3} \text { and } L=125 $$

ENVIRONMENTAL SCIENCE: Biodiversity It is well known that larger land areas can support larger numbers of species. According to one study, multiplying the land area by a factor of \(x\) multiplies the number of species by a factor of \(x^{0.239}\). Use a graphing calculator to graph \(y=x^{0.239}\). Use the window [0,100] by [0,4]. Find the multiple \(x\) for the land area that leads to triple the number of species. That is, find the value of \(x\) such that \(x^{0.239}=3\). [Hint: Either use TRACE or find where \(y_{1}=x^{0.239}\) INTERSECTs \(\left.y_{2}=3 .\right]\)

GENERAL: Speed and Skidmarks Police or insurance investigators often want to estimate the speed of a car from the skidmarks it left while stopping. A study found that for standard tires on dry asphalt, the speed (in mph) is given approximately by \(y=9.4 x^{0.37}\), where \(x\) is the length of the skidmarks in feet. (This formula takes into account the deceleration that occurs even before the car begins to skid.) Estimate the speed of a car if it left skidmarks of: $$ 350 \text { feet. } $$

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