/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Graph the parabola \(y_{1}=1-x^{... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph the parabola \(y_{1}=1-x^{2}\) and the semicircle \(y_{2}=\sqrt{1-x^{2}}\) on the window [-1,1] by \([0,1] .\) (You may want to adjust the window to make the semicircle look more like a semicircle.) Use TRACE to determine which is the "inside" curve (the parabola or the semicircle) and which is the "outside" curve. These graphs show that when you graph a parabola, you should draw the curve near the vertex to be slightly more "pointed" than a circular curve.

Short Answer

Expert verified
The semicircle is the 'outside' curve, and the parabola is the 'inside' curve.

Step by step solution

01

Understand the Functions

We have two functions; the first is a parabola given by \( y_1 = 1 - x^2 \) and the second is a semicircle given by \( y_2 = \sqrt{1 - x^2} \). The parabola is an inverted U-shape, and the semicircle is the top half of a circle with radius 1. Both functions are to be graphed within the window \([-1, 1]\) by \([0, 1]\).
02

Set Up the Graphing Plot Window

Set your graphing tool to the specified window dimensions \([-1, 1]\) on the x-axis and \([0, 1]\) on the y-axis. Adjust the window if necessary to better visualize the semicircle as accurately rounded.
03

Graph the Parabola \( y_1 = 1 - x^2 \)

Start by graphing the function \( y_1 = 1 - x^2 \). For values of \( x \) from \(-1\) to \( 1 \), calculate \( y \) using the equation and connect these points smoothly. The vertex of this parabola is at \( (0, 1) \), and it opens downward.
04

Graph the Semicircle \( y_2 = \sqrt{1 - x^2} \)

Next, graph the semicircle using \( y_2 = \sqrt{1 - x^2} \). This also spans \( x \) values from \(-1\) to \( 1 \). Here, for each value of \( x \), calculate \( y \) and plot these points to form a smooth, rounded semicircle. It should touch the x-axis at \(-1\) and \(1\) and have its highest point at \( (0,1) \).
05

Determine Inside and Outside Curves Using TRACE

Use the TRACE feature on your graphing tool to move along each curve. Compare the \( y \)-coordinates of corresponding \( x \) values for both functions. Identify which function has higher \( y \)-values at each point. This function will be the 'outer' curve, and the other will be the 'inner' curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabola
A parabola is a U-shaped curve that appears frequently in mathematics, especially in quadratic functions. The equation for a parabola can usually be written in the form of \( y = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. In the provided exercise, the parabola is described by the equation \( y_1 = 1 - x^2 \). This specific parabola is a downward-facing, or inverted, parabolic shape. This is because of the negative coefficient in front of \( x^2 \).

Parabolas have interesting properties such as symmetry around their vertical axis, and they always open either upwards or downwards, depending on their leading coefficient. Here are some key aspects of parabolas:
  • **Direction**: The direction of a parabola (opening up or down) is determined by the sign of the coefficient of \( x^2 \). If the sign is negative, the parabola opens downward, like in our exercise.
  • **Vertex**: This point represents the peak or the "bottom" of the parabola, depending on its orientation.
  • **Axis of Symmetry**: A vertical line that passes through the vertex, dividing the parabola into two mirror-image halves. This line is important for identifying symmetry.
Semicircle
A semicircle represents half of a circle and can be graphed using parts of the circle's equation. In the current problem, the semicircle is given by \( y_2 = \sqrt{1 - x^2} \). This represents the top half of a circle with a radius of 1, which would normally be described by the full equation \( x^2 + y^2 = 1 \). In this exercise, only the part above the x-axis is considered.

Key features of semicircles include:
  • **Radius**: Half the diameter, which is the maximum extent from the center to any point on the semicircle.
  • **Center**: The semicircle is centered at the origin (0,0) given the equation in this exercise.
  • **Endpoints on the x-axis**: The semicircle touches the x-axis at its limits, which are \(-1\) and \(1\) in this example.
By understanding the constraints and shape of a semicircle, it's easier to accurately plot it on a graph.
Graphing Calculator
A graphing calculator is a useful tool that can simplify the process of graphing complex functions, including parabolas and semicircles. With a graphing calculator, you can visualize the shape of a function by inputting its equation and setting appropriate window dimensions.

Here are steps to use a graphing calculator for graphing such functions:
  • **Enter Equations**: Input the equations for your functions one by one, making sure each is labeled correctly (like \( y_1 \) and \( y_2 \)).
  • **Set Window**: Adjust the window size to appropriate values that allow a clear view of both the parabola and semicircle. For instance, set the x-axis from [-1, 1] and the y-axis from [0, 1] to align with the exercise.
  • **Use TRACE**: This feature allows you to explore different points on the graphed functions. Compare these points to identify which function relates to which parts, such as determining feedback on which curve is outer or inner.
Graphing calculators not only provide visuals but also offer features like zooming and differentiating between multiple graphs, which are valuable for mathematics students.
Vertex of a Parabola
The vertex is the highest or lowest point on a parabola, depending on its direction. For the exercise's parabola \( y = 1 - x^2 \), the vertex is positioned at the point \( (0,1) \). This point is found by recognizing that the value of \( x \) that makes \( x^2 \) minimal (\( x = 0 \)) will result in the maximum value of \( y \) for this downward-opening parabola.

Characteristics of the vertex include:
  • **Turning Point**: It's the point of symmetry and the peak/minimum of the parabola. Here, it's a maximum at (0,1).
  • **Calculation**: In a standard parabola \( y = ax^2 + bx + c \), the vertex's x-coordinate can be computed using the formula \( -\frac{b}{2a} \). With the current simple form, this isn't needed, as there is no \( b \) term.
  • **Symmetrical Nature**: Both sides of the parabola mirror each other from this central point.
Understanding the vertex is vital because it not only helps in plotting the parabola accurately but also in interpreting its properties like range and symmetry in mathematics.

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