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Give the rates of growth of two populations, \(x\) and \(y,\) measured in thousands. (a) Describe in words what happens to the population of each species in the absence of the other. (b) Describe in words how the species interact with one another. Give reasons why the populations might behave as described by the equations. Suggest species that might interact in that way. $$\begin{aligned} &\frac{d x}{d t}=0.2 x\\\ &\frac{d y}{d t}=0.4 x y-0.1 y \end{aligned}$$

Short Answer

Expert verified
Species \(x\) grows exponentially alone, \(y\) declines alone; \(x\) enhances \(y\)'s growth, suggesting mutualism.

Step by step solution

01

Analyzing the Growth of Population X

The rate of change of population \(x\) is given by the differential equation \(\frac{d x}{d t} = 0.2 x\). This is a simple exponential growth equation, indicating that in the absence of species \(y\), the population \(x\) grows continuously at an exponential rate of 0.2 per unit time. This means population \(x\) will grow without bound as long as no other factors affect it.
02

Analyzing the Growth of Population Y

The rate of change of population \(y\) is given by \(\frac{d y}{d t} = 0.4 x y - 0.1 y\). In the absence of species \(x\), the term \(0.4 x y\) drops to zero, leaving \(\frac{d y}{d t} = -0.1 y\). This indicates that population \(y\) decreases exponentially due to a natural decay rate of 0.1 per unit time.
03

Understanding the Interaction between X and Y

The interaction between the populations is described by the term \(0.4 x y\) in the equation for \(y\). This implies that population \(x\) positively affects the growth of population \(y\). Specifically, as the population of \(x\) increases, it contributes to the growth of population \(y\) by providing more of some beneficial effect or resource, suggesting a mutualistic or commensal relationship.
04

Suggesting Rational Species Interactions

Given the equations, one could suggest that species \(x\) and \(y\) might reflect a relationship like that of a flowering plant (species \(x\)) and a pollinator insect (species \(y\)). Here, as the number of plants \(x\) increases, they provide more food or pollination opportunities, hence boosting the growth of the insect population \(y\). Meanwhile, the plant itself grows independently of the insect presence.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical tools used to describe how things change. In population dynamics, they help us understand how populations grow or shrink over time. A differential equation like \( \frac{d x}{d t} = 0.2 x \) tells us that the population \( x \) changes at a rate proportional to itself. This equation is simple because it models the change in the population over time without including other factors. It shows pure exponential growth for population \( x \) because the rate of change depends solely on the population size at that moment. Understanding these equations is like knowing the rules of a game. Knowing these rules allows us to predict how a population might behave in an unchanging environment. Similarly, for \( y \)'s rate of change, the equation \( \frac{d y}{d t} = 0.4 x y - 0.1 y \) means that the change in \( y \) is influenced by both its current size and other factors, like population \( x \). This equation helps us see that interactions between species can majorly affect population dynamics.
Exponential Growth
Exponential growth describes how populations can increase rapidly when each member contributes to a constant rate of increase. For population \( x \), characterized by the equation \( \frac{d x}{d t} = 0.2 x \), this means that it doubles over regular intervals when left unchecked. Each individual in the population leads to more growth, making the number of individuals grow faster over time.
  • In exponential growth, the bigger the population, the faster it grows.
  • The growth is unlimited unless other factors, like scarcity or predators, limit it.
Exponential growth is common in ecosystems when resources are abundant, and there are no significant threats. However, unchecked exponential growth is rare in nature because resources eventually run out or conditions change, leading to stability or decline. That's why understanding the beginning phases of population growth with exponential models is crucial for understanding potential future scenarios.
Species Interaction
Species interaction refers to how different species in an ecosystem affect one another. In our exercise, the interaction comes from the term \( 0.4 x y \) in the differential equation for \( y \), suggesting that species \( x \) positively impacts species \( y \). This term models a mutualistic interaction where the increase in species \( x \) leads to beneficial effects on species \( y \).
  • Positive interaction: Species \( x \) positively influences the growth of species \( y \).
  • Mutualism: Both parties benefit from the interaction.
  • Dependency: Species \( y \) relies on species \( x \) for its positive growth rate.
Such interactions can occur between a flowering plant and its pollinator. As the plant population increases, more resources become available for the pollinator, boosting its population. This mutual benefit promotes biodiversity and stability in ecosystems. Understanding these interactions helps us realize the interconnectedness of life and the importance of balancing ecosystems.

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Most popular questions from this chapter

Create a system of differential equations to model the situations. You may assume that all constants of proportionality are 1. A population of fleas is represented by \(x,\) and a population of dogs is represented by \(y .\) The fleas need the dogs in order to survive. The dog population, however, is unaffected by the fleas.

Money in a bank account grows continuously at an annual rate of \(r\) (when the interest rate is \(5 \%, r=0.05,\) and so on). Suppose \(\$ 2000\) is put into the account in 2010 . (a) Write a differential equation satisfied by \(M,\) the amount of money in the account at time \(t,\) measured in years since 2010. (b) Solve the differential equation. (c) Sketch the solution until the year 2040 for interest rates of \(5 \%\) and \(10 \%\).

Morphine is administered to a patient intravenously at a rate of 2.5 mg per hour. About \(34.7 \%\) of the morphine is metabolized and leaves the body each hour. Write a differential equation for the amount of morphine, \(M,\) in milligrams, in the body as a function of time, \(t,\) in hours.

A bank account earns \(5 \%\) annual interest, compounded continuously. Money is deposited in a continuous cash flow at a rate of \(\$ 1200\) per year into the account.\( (a) Write a differential equation that describes the rate at which the balance \)B=f(t)\( is changing. (b) Solve the differential equation given an initial balance \)B_{0}=0$. (c) Find the balance after 5 years.

A bank account earns \(7 \%\) annual interest compounded continuously. You deposit \(\$ 10,000 in the account, and withdraw money continuously from the account at a rate of \)\$ 1000\( per year.\) (a) Write a differential equation for the balance, \(B\), in the account after \(t\) years. (b) What is the equilibrium solution to the differential equation? (This is the amount that must be deposited now for the balance to stay the same over the years.) (c) Find the solution to the differential equation. (d) How much is in the account after 5 years? (e) Graph the solution. What happens to the balance in the long run?

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