Chapter 8: Problem 13
Draw a contour diagram for \(C(d, m)=40 d+0.15 m\) Include contours for \(C=50,100,150,200\)
Short Answer
Expert verified
Plot lines for each contour equation for \( C = 50, 100, 150, 200 \) on a graph with \( d \) and \( m \) axes.
Step by step solution
01
Understand the Function
The given function is \( C(d, m) = 40d + 0.15m \). Here, \(d\) is likely representing the number of days and \(m\) the minutes. The function is linear, meaning it has a constant rate of change.
02
Set Up Contour Levels
To draw the contour diagram, we need to solve for \( m \) given specific values of \( C \). We have contour levels \( C = 50, 100, 150, 200 \). For each contour, we will solve \( C = 40d + 0.15m \) for \( m \).
03
Solve for Contour \( C = 50 \)
Set \( 40d + 0.15m = 50 \). Solve for \( m \):\[ 0.15m = 50 - 40d \]\[ m = \frac{50 - 40d}{0.15} \]
04
Solve for Contour \( C = 100 \)
Set \( 40d + 0.15m = 100 \). Solve for \( m \):\[ 0.15m = 100 - 40d \]\[ m = \frac{100 - 40d}{0.15} \]
05
Solve for Contour \( C = 150 \)
Set \( 40d + 0.15m = 150 \). Solve for \( m \):\[ 0.15m = 150 - 40d \]\[ m = \frac{150 - 40d}{0.15} \]
06
Solve for Contour \( C = 200 \)
Set \( 40d + 0.15m = 200 \). Solve for \( m \):\[ 0.15m = 200 - 40d \]\[ m = \frac{200 - 40d}{0.15} \]
07
Draw the Contour Diagram
Plot each contour by using the equations derived for \( m \) against \( d \). Each equation represents a line, and you should plot these lines on the same graph to create the contour diagram. The x-axis typically represents \( d \) (days), and the y-axis \( m \) (minutes).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Functions
Linear functions are a fundamental concept in mathematics characterized by a constant rate of change. These functions are often expressed in the form \( f(x) = mx + b \), where \( m \) is the slope of the line and \( b \) is the y-intercept. The key properties include:
- A linear graph is a straight line.
- The slope \( m \) indicates the steepness and direction of the line.
- The y-intercept \( b \) is where the line crosses the y-axis.
Solving Equations
Solving equations often involves isolating the variable of interest. In our linear function, particular contour levels are given as \( C = 50, 100, 150, 200 \). The task is to solve for \( m \) when \( d \) is constant. Here are the steps to solve for \( m \):
- Rearrange the equation to isolate \( m \) on one side, such as \( 0.15m = C - 40d \).
- Divide both sides by 0.15 to solve for \( m \): \( m = \frac{C - 40d}{0.15} \).
Graphing Techniques
Graphing is a crucial skill for visualizing functions and interpreting their relationships. Here are some basic graphing techniques:
- Identify the variables: on a graph, typically one variable is plotted on the x-axis and another on the y-axis. For this exercise, \( d \) is the x-axis, and \( m \) is the y-axis.
- Use a consistent scale: choose a reasonable scale that allows all data points and lines to fit clearly on the graph.
- Plot each equation as a separate line: solve for different \( C \) values and plot their corresponding lines. In this case, for \( C = 50, 100, 150, 200 \).
- Check the intersections and trends: since each equation depicts a contour level, observing how these lines interact can give insights into the solution's behavior.
Contour Levels
Contour levels in mathematics are a way to represent a three-dimensional surface on a two-dimensional plane through lines or curves. Each contour line corresponds to a specific value (level). In this case, each level represents a specific cost \( C \): 50, 100, 150, and 200.
- Each contour line corresponds to a constant \( C \) value.
- The spacing between the lines can indicate the rate of change; closer lines mean a steeper gradient.
- Contour diagrams are commonly used in fields like meteorology, geography, and economics to represent concepts such as elevation changes, temperature changes, and cost changes.