Chapter 6: Problem 88
Find an antiderivative \(F(x)\) with \(F^{\prime}(x)=f(x)\) and \(F(0)=5\) $$f(x)=x^{2}+1$$
Short Answer
Expert verified
The antiderivative is \( F(x) = \frac{x^3}{3} + x + 5 \).
Step by step solution
01
Integrate the Function
To find the antiderivative \( F(x) \) of \( f(x) = x^2 + 1 \), we need to integrate \( f(x) \). The integral of \( x^2 \) is \( \frac{x^3}{3} \) and the integral of \( 1 \) is \( x \). Therefore, \( F(x) = \frac{x^3}{3} + x + C \), where \( C \) is the constant of integration.
02
Apply the Initial Condition
We know that \( F(0) = 5 \). We substitute \( x = 0 \) into the equation \( F(x) = \frac{x^3}{3} + x + C \) to find \( C \). This gives us \( F(0) = 0 + 0 + C = C \). Since \( F(0) = 5 \), \( C = 5 \).
03
Write the Final Antiderivative
Now that we have determined \( C = 5 \), the antiderivative \( F(x) \) of \( f(x) = x^2 + 1 \) satisfying the condition \( F(0) = 5 \) is \( F(x) = \frac{x^3}{3} + x + 5 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration
Integration is a fundamental concept in calculus that allows us to find the antiderivative, or the area under the curve, of a given function. When we integrate a function such as \( f(x) = x^2 + 1 \), we are essentially reversing the process of differentiation to recover the original function, often called \( F(x) \). This function is the antiderivative.
The process involves finding a function whose derivative is the given function. For \( x^2 \), the antiderivative is \( \frac{x^3}{3} \), and for a constant like \( 1 \), the antiderivative is \( x \). Therefore, the integral of \( x^2 + 1 \) results in:
Learning integration is crucial for understanding how systems change over time or across different dimensions.
The process involves finding a function whose derivative is the given function. For \( x^2 \), the antiderivative is \( \frac{x^3}{3} \), and for a constant like \( 1 \), the antiderivative is \( x \). Therefore, the integral of \( x^2 + 1 \) results in:
- \( F(x) = \frac{x^3}{3} + x + C \)
Learning integration is crucial for understanding how systems change over time or across different dimensions.
Initial Condition
An initial condition is a specific value that allows us to determine the constant in an indefinite integral. In our exercise, we find that \( F(0) = 5 \) is provided as an initial condition. This means when \( x = 0 \), the antiderivative \( F(x) \) should be equal to \( 5 \).
This crucial piece of information helps us pinpoint the exact antiderivative among the infinite set of possible functions that differ by a constant. Without this, the antiderivative remains general.
This crucial piece of information helps us pinpoint the exact antiderivative among the infinite set of possible functions that differ by a constant. Without this, the antiderivative remains general.
- Substitute \( x = 0 \) into \( F(x) = \frac{x^3}{3} + x + C \).
- This gives us \( 0 + 0 + C = 5 \).
- Thus, \( C = 5 \).
Constant of Integration
The constant of integration, denoted typically as \( C \), plays a vital role when calculating indefinite integrals. It represents the unknown constant that arises because the derivative of a constant is zero, meaning multiple antiderivatives can exist for a single derivative function.
When we perform integration to find \( F(x) \), the \( C \) accounts for all possible vertical shifts of the function graph that result in the same derivative. Thus, when integrating \( x^2 + 1 \), writing \( \int (x^2+1) \, dx = \frac{x^3}{3} + x + C \) acknowledges this ambiguity.
When we perform integration to find \( F(x) \), the \( C \) accounts for all possible vertical shifts of the function graph that result in the same derivative. Thus, when integrating \( x^2 + 1 \), writing \( \int (x^2+1) \, dx = \frac{x^3}{3} + x + C \) acknowledges this ambiguity.
- The constant of integration ensures the solution covers all potential functions.
- To find \( C \), specific conditions like initial conditions are needed.
- In this case, \( F(0) = 5 \) provides clarity and allows us to solve \( C = 5 \).