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Decide whether the expression is a number or a family of functions. (Assume \(f(x)\) is a function.) $$\int_{3}^{5} 2 f(x) d x$$

Short Answer

Expert verified
The expression is a number.

Step by step solution

01

Identify the elements of the expression

The given expression is \( \int_{3}^{5} 2 f(x) \,dx \). It involves an integral from 3 to 5, with the integrand being \( 2 f(x) \). This integral is a definite integral because it has specific lower and upper limits, 3 and 5, respectively.
02

Understand the nature of definite integrals

Definite integrals calculate the area under the curve of the function \( f(x) \) from the lower limit to the upper limit. This process results in a specific numerical value, not a function.
03

Evaluate the definite integral conceptually

Even though the explicit function \( f(x) \) is not given, the integral with specific limits (3 to 5) and an integrand (\( 2 f(x) \)) implies that it calculates a specific numerical value based on \( f(x) \). The result of this calculation will be a number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integral
A definite integral is an essential concept in calculus that helps us measure the total accumulation of a quantity over a specific interval. This type of integral is characterized by its two distinct limits: a lower limit and an upper limit. For instance, in the expression \( \int_{3}^{5} 2 f(x) \, dx \), the numbers 3 and 5 are these limits.When performing a definite integral, we aim to calculate the area under the curve described by the function involved, bounded by the interval from the lower limit to the upper limit. This conversion of the curve into an area results in a single, specific number. In contrast to an indefinite integral, which produces a family of functions as solutions, a definite integral provides a singular numerical answer.
  • This method is particularly useful in physics and engineering, where it may represent quantities such as displacement, area, volume, or total accumulated change.
  • Because it yields a number, a definite integral does not depend on the variable of integration once evaluated.
Function
In calculus, a function is a relationship between two sets that assigns each element from the first set to exactly one element in the second set. Essentially, functions map inputs to outputs.When dealing with integrations, functions play a vital role. In our given expression, \( f(x) \) represents a function that we are integrating over a specified interval. The role of \( f(x) \) is to describe how values change within the interval from 3 to 5.Functions can be complex and multifaceted, but at their core, they allow us to understand relationships and changes in variables. For example:
  • \( f(x) \) in the integral could represent anything from a linear change like temperature variation over time to more complex motion paths.
  • Understanding the behavior of \( f(x) \) is crucial for obtaining meaningful results from the definite integral.
Numerical Value
A numerical value is what we ultimately obtain from evaluating a definite integral when limits are applied. While dealing with a definite integral, the result is not an expression or a function but a single number that signifies the total sum of changes caused by the integrand across the defined interval.For example, in the integral \( \int_{3}^{5} 2 f(x) \, dx \), computing this in practical terms means calculating the net area under the curve presented by \( 2 f(x) \) between the x-values of 3 and 5.To achieve this numerical result, it typically involves:
  • Understanding, or sometimes calculating, the exact expression for \( f(x) \).
  • Using antiderivatives or numerical techniques to find the area accurately.
  • The process effectively constructs a snapshot of total quantity accumulation within defined limits, which is expressed as a lone number, often reflecting real-world phenomena like distance traveled or volume.
Integrand
The integrand in an integral expression is the function being evaluated within the bounds of the integral. It serves as the 'main character' in the integral, determining the shape and nature of the area calculated.In the expression \( \int_{3}^{5} 2 f(x) \, dx \), the integrand is \( 2 f(x) \). Here, \( 2 \) acts as a constant multiplier scaling the output of \( f(x) \), essentially changing the height of the curve being integrated over, and thus affecting the area beneath it.Key points to keep in mind about integrands:
  • They are central to defining how the integral behaves. If \( f(x) \) is transformed, the nature and outcome of the integral will change accordingly.
  • Recognizing and simplifying integrands can make the process of evaluating integrals more straightforward.
  • The choice and manipulation of the integrand can model various behaviors of physical systems or financial growth.

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Most popular questions from this chapter

Oil is leaking out of a ruptured tanker at the rate of \(r(t)=50 e^{-0.02 t}\) thousand liters per minute. (a) At what rate, in liters per minute, is oil leaking out at \(t=0 ?\) At \(t=60 ?\) (b) How many liters leak out during the first hour?

(a) Graph \(f(x)=e^{-x^{2}}\) and shade the area represented by the improper integral \(\int_{-\infty}^{\infty} e^{-x^{2}} d x\) (b) Use a calculator or computer to find \(\int_{-a}^{a} e^{-x^{2}} d x\) for \(a=1, a=2, a=3, a=5\) (c) The improper integral \(\int_{-\infty}^{\infty} e^{-x^{2}} d x\) converges to a finite value. Use your answers from part (b) to estimate that value.

Find an antiderivative and use differentiation to check your answer. $$h(x)=\frac{x}{\sqrt{x}}+\frac{\sqrt{x}}{x}$$

Over the past fifty years the carbon dioxide level in the atmosphere has increased. Carbon dioxide is believed to drive temperature, so predictions of future carbon dioxide levels are important. If \(C(t)\) is carbon dioxide level in parts per million (ppm) and \(t\) is time in years since 1950 , three possible models are: \(^{2}$$$\begin{aligned}&\begin{array}{l} \text { I } C^{\prime}(t)=1.3 \\\\\text { II } C^{\prime}(t)=0.5+0.03 t\end{array}\\\&\text { III } C^{\prime}(t)=0.5 e^{0.02 t}\end{aligned}$$ (a) Given that the carbon dioxide level was 311 ppm in \)1950,\( find \)C(t)$ for each model. (b) Find the carbon dioxide level in 2020 predicted by each model.

Use integration by substitution and the Fundamental Theorem to evaluate the definite integrals. $$\int_{-1}^{2} \sqrt{x+2} d x$$

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