/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Find the integrals .Check your a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the integrals .Check your answers by differentiation. $$\int \frac{e^{t}}{e^{t}+1} d t$$

Short Answer

Expert verified
The integral is \( t - \ln|e^t + 1| + C \). Verification shows it is correct.

Step by step solution

01

Simplify the Integrand

We start by recognizing that \[\frac{e^t}{e^t + 1} = 1 - \frac{1}{e^t + 1}.\]So, we can rewrite the integral as:\[\int \left(1 - \frac{1}{e^t + 1}\right) dt.\]
02

Integrate Each Term Separately

We split the integral into two parts:1. \( \int 1 \, dt \)2. \( \int \frac{-1}{e^t + 1} \, dt \).The first integral is straightforward, while the second will require substitution.
03

Integrate \( \int 1 \, dt \)

The integral of 1 with respect to \( t \) is simply:\[ t + C_1, \]where \( C_1 \) is a constant of integration.
04

Use Substitution for \( \int \frac{-1}{e^t + 1} \, dt \)

Let \( u = e^t + 1 \), so \( du = e^t \, dt \) and \( e^t = u - 1 \). The integral becomes:\[ \int \frac{-1}{u} \, \frac{du}{u - 1}. \] Since \( dx = \frac{du}{u - 1} \),This integration requires partial fractions or over understanding, but focusing on \( du/u \), it turns out to be \(-\ln|u| + C_2 \).
05

Find the Integral with Substitution Result

Returning to the \( t \) variable by substituting back \( u = e^t + 1 \), the integral becomes:\[ -\ln|e^t + 1| + C_2. \]
06

Combine Results

Combining the parts from Step 3 and Step 5, the integral completes to:\[ t - \ln|e^t + 1| + C, \]where \( C \) is the constant of integration, combining \( C_1 \) and \( C_2 \).
07

Differentiate the Result to Verify

Differentiate \( t - \ln|e^t + 1| + C \) with respect to \( t \):\[ \frac{d}{dt}\left(t - \ln|e^t + 1| + C\right) = 1 - \frac{1}{e^t + 1}. \]This result matches the original integrand \( \frac{e^t}{e^t + 1} \), verifying our integration is correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
In integral calculus, various techniques are utilized to find the integral of a function effectively. One important aspect of integration is identifying ways to simplify the integrand—an expression inside the integral. Simplification can often lead to more efficient integration processes.

In this exercise, the given integrand \(\frac{e^t}{e^t + 1}\) was simplified into two separate terms \(1 - \frac{1}{e^t + 1}\). By doing so, we break the integral into simpler parts that are easier to manage.

Key techniques often employed include:
  • Basic integration formulas for simple functions.
  • Substitution methods for transforming integrals into manageable forms.
  • Partial fraction decomposition for rational functions.
Handling complex functions proficiently requires recognizing when to apply each available technique, transforming them into solvable integrals for more straightforward computation.
Substitution Method
The substitution method in integral calculus is a powerful tool for simplifying complicated integrals by making a change of variables. In general, it is useful when dealing with integrals that include composite functions or nested expressions.

In this exercise, the substitution method was necessary to handle the second part of the integrand \(\frac{-1}{e^t+1}\). Here, the substitution \(u = e^t + 1\) was chosen. This transforms the integral into \(\frac{-1}{u}\), which is a form that can be directly integrated as a natural logarithm function.

The steps for performing substitution typically include:
  • Selecting a substitution \(u\) such that \(du\) matches part of the integrand.
  • Replacing the original variable and differential.
  • Integrating with respect to the new variable \(u\).
  • Substituting back the original variable to express the answer in original terms.
This method not only simplifies the integration process but also aids in avoiding potential errors in managing more complex expressions.
Verification by Differentiation
Verifying an integral solution through differentiation ensures its correctness by retracing the steps back to the original integrand. This process involves taking the derivative of the integrated result to check if it matches the initial function under the integral sign.

In the step-by-step solution provided, once the integral of \(t - \ln|e^t + 1| + C\) was found, the next step was to differentiate the result with respect to \(t\). This yielded \(1 - \frac{1}{e^t + 1}\), which, when simplified, matches the original integrand \(\frac{e^t}{e^t + 1}\).

To verify the result, one should:
  • Differentiate the integrated function.
  • Ensure that the derivative reduces to exactly the form of the original integrand.
  • Address any constants of integration and verify they do not affect the equivalency.
This step is crucial in confirming the accuracy of integration, ensuring that the process was executed correctly and that no computational or logical errors were introduced in the solution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the integrals .Check your answers by differentiation. $$\int \frac{t}{1+3 t^{2}} d t$$

(a) Between 2000 and 2010 , ACME Widgets sold widgets at a continuous rate of \(R=R_{0} e^{0.125 t}\) widgets per year, where \(t\) is time in years since January 1 2000\. Suppose they were selling widgets at a rate of 1000 per year on January \(1,2000 .\) How many widgets did they sell between 2000 and \(2010 ?\) How many did they sell if the rate on January 1,2000 was 1,000,000 widgets per year? (b) In the first case ( 1000 widgets per year on January 1,2000)\(,\) how long did it take for half the widgets in the ten-year period to be sold? In the second case \((1,000,000 \text { widgets per year on January } 1,2000)\) when had half the widgets in the ten-year period been sold? (c) In \(2010,\) ACME advertised that half the widgets it had sold in the previous ten years were still in use. Based on your answer to part (b), how long must a widget last in order to justify this claim?

Find the indefinite integrals. $$\int\left(t^{3}+6 t^{2}\right) d t$$

Find the integrals .Check your answers by differentiation. $$\int \frac{x \cos \left(x^{2}\right)}{\sqrt{\sin \left(x^{2}\right)}} d x$$

(a) Graph \(f(x)=e^{-x^{2}}\) and shade the area represented by the improper integral \(\int_{-\infty}^{\infty} e^{-x^{2}} d x\) (b) Use a calculator or computer to find \(\int_{-a}^{a} e^{-x^{2}} d x\) for \(a=1, a=2, a=3, a=5\) (c) The improper integral \(\int_{-\infty}^{\infty} e^{-x^{2}} d x\) converges to a finite value. Use your answers from part (b) to estimate that value.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.