/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 The following table shows the nu... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following table shows the number of hours worked in a week, \(f(t),\) hourly earnings, \(g(t),\) in dollars, and weekly earnings, \(h(t),\) in dollars, of production workers as functions of \(t\), the year. \(^{6}.\) (a) Indicate whether each of the following derivatives is positive, negative, or zero: \(f^{\prime}(t), g^{\prime}(t), h^{\prime}(t) .\) Interpret each answer in terms of hours or earnings. (b) Estimate each of the following derivatives, and interpret your answers: (i) \(f^{\prime}(1970)\) and \(f^{\prime}(1995)\) (ii) \(g^{\prime}(1970)\) and \(g^{\prime}(1995)\) (iii) \(h^{\prime}(1970)\) and \(h^{\prime}(1995)\) $$\begin{array}{c|c|c|c|c|c|c|c}\hline t & 1970 & 1975 & 1980 & 1985 & 1990 & 1995 & 2000 \\\\\hline f(t) & 37.0 & 36.0 & 35.2 & 34.9 & 34.3 & 34.3 & 34.3 \\\\\hline g(t) & 3.40 & 4.73 & 6.84 & 8.73 & 10.09 & 11.64 & 14.00 \\\\\hline h(t) & 125.80 & 170.28 & 240.77 & 304.68 & 349.29 & 399.53 & 480.41 \\\\\hline\end{array}$$

Short Answer

Expert verified
(a) \(f'(t)\) is negative; \(g'(t)\) and \(h'(t)\) are positive. (b) 1970: \(f'(t) = -0.2\), \(g'(t) = 0.266\), \(h'(t) = 8.896\); 1995: \(f'(t) = 0\), \(g'(t) = 0.472\), \(h'(t) = 16.176\).

Step by step solution

01

Understanding the Derivatives

A derivative, such as \( f'(t) \), \( g'(t) \), and \( h'(t) \), indicates the rate of change over time. It illustrates whether a function is increasing, decreasing, or stable over the years. A positive derivative indicates an increase, a negative derivative indicates a decrease, and a zero derivative indicates no change.
02

Analyzing \( f'(t) \)

The function \( f(t) \) represents hours worked per week. By observing the table, \( f(t) \) decreased from 37.0 in 1970 to 34.3 in 2000. Therefore, \( f'(t) \) is negative overall, implying a general decrease in the number of hours worked over time.
03

Analyzing \( g'(t) \)

The function \( g(t) \) stands for hourly earnings. The values increase from 3.40 in 1970 to 14.00 in 2000. Hence, \( g'(t) \) is positive, indicating hourly earnings are rising over the years.
04

Analyzing \( h'(t) \)

The function \( h(t) \) indicates weekly earnings. Weekly earnings grow from 125.80 in 1970 to 480.41 in 2000. As such, \( h'(t) \) is positive, reflecting an increase in weekly earnings.
05

Estimating \( f'(1970) \) and \( f'(1995) \)

The approximate derivative \( f'(t) \) at 1970 can be estimated as \( \frac{f(1975) - f(1970)}{5} = \frac{36 - 37}{5} = -0.2 \). Similarly, at 1995: \( \frac{f(2000) - f(1995)}{5} = \frac{34.3 - 34.3}{5} = 0 \). Hours worked decrease at 1970 and stabilize by 1995.
06

Estimating \( g'(1970) \) and \( g'(1995) \)

Calculate \( g'(1970) \) as \( \frac{g(1975) - g(1970)}{5} = \frac{4.73 - 3.40}{5} = 0.266 \). Calculate \( g'(1995) \) as \( \frac{g(2000) - g(1995)}{5} = \frac{14 - 11.64}{5} = 0.472 \). Hourly earnings increase at a higher rate in 1995 than in 1970.
07

Estimating \( h'(1970) \) and \( h'(1995) \)

Estimate \( h'(1970) \): \( \frac{h(1975) - h(1970)}{5} = \frac{170.28 - 125.80}{5} = 8.896 \). For 1995: \( \frac{h(2000) - h(1995)}{5} = \frac{480.41 - 399.53}{5} = 16.176 \). Weekly earnings increase faster in 1995 than in 1970.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rates of Change
Rates of change fundamentally describe how a quantity changes with respect to a change in another variable, often time. In calculus, the rate of change is represented by the derivative. For the given problem, three key derivatives are analyzed: \( f'(t) \), \( g'(t) \), and \( h'(t) \). Each derivative provides insight into whether the respective function—hours worked, hourly earnings, and weekly earnings—is increasing, decreasing, or remaining constant over time.

  • If the derivative is positive, it indicates that the function is increasing, meaning the quantity it measures is growing over time.
  • If the derivative is negative, it signals a decrease, showing that the particular quantity is reducing over the years.
  • A zero derivative suggests no change from one measured point in time to the next.
In the context of this exercise, we found:
\( f'(t) \) is negative overall (indicating a decrease in weekly hours worked), \( g'(t) \) is positive (demonstrating an increase in hourly earnings), and \( h'(t) \) is also positive (highlighting a rise in weekly earnings). The interpretation of these derivatives tells us how the working dynamics in terms of hours and earnings have evolved over time.
Estimating Derivatives
Estimating the derivative at specific years, like 1970 and 1995, helps us understand the changes that occur during those years more precisely. We do this by calculating the average rate of change over a defined interval using the formula:\[ f'(a) \approx \frac{f(b) - f(a)}{b - a}\]For example, estimating \( f'(1970) \), which represents the change in hours worked, involves taking the difference in function values at two years and dividing by the time period. The calculation for \( f'(1970) \) was approximately -0.2, showing a decrease in work hours at that time, whereas \( f'(1995) \) was 0, indicating no change.
Similarly, estimating derivatives for \( g(t) \) and \( h(t) \) at the same points highlighted:
  • \( g'(1970) = 0.266 \) and \( g'(1995) = 0.472 \), showing hourly earnings increased at both times, but at a faster rate by 1995.
  • \( h'(1970) = 8.896 \) and \( h'(1995) = 16.176 \), meaning weekly earnings grew, particularly at a higher rate in 1995.
These estimates are particularly useful in identifying periods of economic growth or stagnation and indicate how quickly these changes are occurring.
Function Analysis
To thoroughly analyze how these functions behave over time, it's important to consider the trend indicated by their derivatives. Observing the functions \( f(t) \), \( g(t) \), and \( h(t) \):
  • \( f(t) \): Highlights a downward trend where the hours worked decline from 37 to 34.3 over three decades, primarily driven by the needs of efficiency and possibly technological advancements reducing workload.
  • \( g(t) \): This showcases significant growth from \(3.40 to \)14.00, an increase in hourly earnings likely influenced by inflationary pressures and enhancements in productivity.
  • \( h(t) \): Displays a steady increase in weekly earnings from \(125.80 to \)480.41, which can be seen as a result of increasing hourly rates and possibly the addition of economic bonuses over time.
Breaking down these functions into intervals and examining changes in their derivatives provides a layered understanding of economic and labor trends, making it clearer how and why these variables interact as they do. Understanding these patterns helps in making informed predictions about future labor statistics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the Leibniz notation for the derivative of the given function and include units. The distance to the ground, \(D\), in feet, of a skydiver is a function of the time \(t\) in minutes since the skydiver jumped out of the airplane.

The number of active Facebook users hit 175 million at the end of February 2009 and 200 million \(^{17}\) at the end of April \(2009 .\) With \(t\) in months since the start of 2009 , let \(f(t)\) be the number of active users in millions. Estimate \(f(4)\) and \(f^{\prime}(4)\) and the relative rate of change of \(f\) at \(t=4 .\) Interpret your answers in terms of Facebook users.

When you breathe, a muscle (called the diaphragm) reduces the pressure around your lungs and they expand to fill with air. The table shows the volume of a lung as a function of the reduction in pressure from the diaphragm. Pulmonologists (lung doctors) define the compliance of the lung as the derivative of this function. 10 (a) What are the units of compliance? (b) Estimate the maximum compliance of the lung. (c) Explain why the compliance gets small when the lung is nearly full (around 1 liter). $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Pressure reduction } \\ \text { (cm of water) } \end{array} & \begin{array}{c} \text { Volume } \\ \text { (iters) } \end{array} \\ \hline 0 & 0.20 \\ \hline 5 & 0.29 \\ \hline 10 & 0.49 \\ \hline 15 & 0.70 \\ \hline 20 & 0.86 \\ \hline 25 & 0.95 \\ \hline 30 & 1.00 \\ \hline \end{array}$$

Using slopes to left and right of \(0,\) estimate \(R^{\prime}(0)\) if \(R(x)=100(1.1)^{x}\)

A yam has just been taken out of the oven and is cooling off before being eaten. The temperature, \(T,\) of the yam (measured in degrees Fahrenheit) is a function of how long it has been out of the oven, \(t\) (measured in minutes). Thus, we have \(T=f(t)\) (a) Is \(f^{\prime}(t)\) positive or negative? Why? (b) What are the units for \(f^{\prime}(t) ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.