/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Sketch a graph of a continuous f... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch a graph of a continuous function \(f\) with the following properties: \(\cdot f^{\prime}(x)>0\) for all \(x\) \(\cdot f^{\prime \prime}(x)<0\) for \(x<2\) and \(f^{\prime \prime}(x)>0\) for \(x>2\).

Short Answer

Expert verified
The graph is always increasing, with a concave down curve for \( x < 2 \) and a concave up curve for \( x > 2 \).

Step by step solution

01

- Understanding Derivative Conditions

We are given that \( f'(x) > 0 \) for all \( x \), which means that the function \( f(x) \) is always increasing. This implies that the slope of the function is never negative, and there are no decreases in the graph.
02

- Analyzing Second Derivative for Concavity (Left of x = 2)

For \( x < 2 \), \( f''(x) < 0 \) suggests that the function is concave down in this region. This means the graph is curving downward, resembling an upside-down cup shape. The function is increasing but at a decreasing rate before \( x = 2 \).
03

- Analyzing Second Derivative for Concavity (Right of x = 2)

For \( x > 2 \), \( f''(x) > 0 \) suggests that the function is concave up in this region. This indicates that the graph is curving upward, resembling a regular cup shape. Here, the function is increasing at an increasing rate beyond \( x = 2 \).
04

- Sketch the Graph Based on Conditions

Start sketching the graph by assuming it is increasing throughout. Before \( x = 2 \), draw a curve that slopes up but bends down slightly, showing concavity downward. At \( x = 2 \), there should be a transition to a curve that slopes up and bends upward, highlighting the concavity upward. The transition at \( x = 2 \) is smooth, but the curvature changes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
Understanding derivatives is crucial when analyzing how a function behaves. A derivative, denoted as \( f'(x) \), represents the rate at which the function \( f(x) \) changes with respect to \( x \). When the derivative is positive, \( f'(x) > 0 \), this indicates that the function is increasing. This means that as you move from left to right on the graph, the value of the function rises.
  • Positive derivative: The function is going upwards, like climbing a hill.
  • Negative derivative: The function goes downwards, like descending a hill (not applicable here as \( f'(x) > 0 \)).
  • Zero derivative: The function might be flat, indicating a possible local minimum or maximum.
In our exercise, because \( f'(x) > 0 \) for all \( x \), the graph of \( f(x) \) is always increasing, consistently climbing upwards. There's no portion of the graph where the function decreases, which is an essential feature when sketching it.
Concavity
Concavity helps us understand the direction the graph is curving. To determine concavity, we look at the second derivative \( f''(x) \). If \( f''(x) < 0 \), the graph is concave down, resembling an upside-down cup shape. Conversely, if \( f''(x) > 0 \), the graph is concave up, shaped like a right-side-up cup.
In our problem:
  • For \( x < 2 \), \( f''(x) < 0 \): The graph is concave down. The function is rising, but it does so with an ever-decreasing slope—like the rate at which you're climbing a hill is slowing down.
  • For \( x > 2 \), \( f''(x) > 0 \): The graph is concave up. Here, the function still rises but now with an increasing slope, similar to accelerating up a steep hill.
At the point \( x = 2 \), the concavity changes, making this a point of inflection where the curvature of the graph transitions from concave down to concave up.
Increasing Functions
Increasing functions are those where the function's value rises as the input value increases. For a function \( f(x) \) to be increasing, its derivative \( f'(x) \) needs to be greater than zero. In our exercise, we know that the entire graph is increasing since \( f'(x) > 0 \) for all \( x \).
Characteristics of Increasing Functions:
  • The slope of the tangent line is positive at every point on the graph.
  • There are no downward trends; the function consistently moves in an upward direction.
  • Every new value of \( x \) results in a higher \( f(x) \) than the previous value of \( x \).
In sketching graphs of increasing functions, understand that the steepness can change. It can rise quickly or slowly, affected by the concavity, but it will always rise without descending.
Graph Sketching
Sketching a graph involves combining the insights gained from the derivative and concavity. To sketch based on the given conditions, follow this structured approach:
1. Begin by drawing an upward sloping line, as \( f'(x) > 0 \) signals that \( f(x) \) is increasing for all \( x \).
2. For \( x < 2 \): Smoothly draw the graph concave down. This means the line should not be perfectly straight but curved downward, forming an upside-down cup shape.
3. At \( x = 2 \): Identify the point of inflection. Here, seamlessly transition the curve from concave down to concave up without sharp angles. The curve should flatten slightly at this transition.
4. For \( x > 2 \): Continue the graph upwards but now with concavity upwards, making the curve resemble a regular cup shape.
This sketching method visually represents that \( f(x) \) is not just increasing but also changing the way it increases, as determined by its concavity.

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Most popular questions from this chapter

The number of barrels of oil produced from North Dakota oil wells is estimated to be \(B=21.88 e^{0.059 t}\) million barrels, where \(t\) is in months since Sept \(2012 .^{20}\) Estimate the relative rate of change of oil production in December 2012 using (a) \(\quad \Delta t=1\) (b) \(\Delta t=0.1\) (c) \(\Delta t=0.01\)

Sketch the graph of a function whose first derivative is everywhere negative and whose second derivative is positive for some \(x\) -values and negative for other \(x\) -values.

A yam has just been taken out of the oven and is cooling off before being eaten. The temperature, \(T,\) of the yam (measured in degrees Fahrenheit) is a function of how long it has been out of the oven, \(t\) (measured in minutes). Thus, we have \(T=f(t)\) (a) Is \(f^{\prime}(t)\) positive or negative? Why? (b) What are the units for \(f^{\prime}(t) ?\)

Annual net sales, in billion of dollars, for the Hershey Company, the largest US producer of chocolate, is a function \(S=f(t)\) of time, \(t,\) in years since 2000 (a) Interpret the statements \(f(8)=5.1\) and \(f^{\prime}(8)=\) 0.22 in terms of Hershey sales. \(^{13}\) (b) Estimate \(f(12)\) and interpret it in terms of Hershey sales.

Graph the functions described in parts (a)-(d). (a) First and second derivatives everywhere positive. (b) Second derivative everywhere negative; first derivative everywhere positive. (c) Second derivative everywhere positive; first derivative everywhere negative. (d) First and second derivatives everywhere negative.

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