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The number of people living with HIV infections increased worldwide approximately exponentially from 2.5 million in 1985 to 34 million in \(2010 .^{75}\) (HIV is the virus that causes AIDS.) (a) Give a formula for the number of HIV infections, \(H\) (in millions) as a function of years, \(t,\) since 1985 Use the form \(H=H_{0} e^{k t} .\) Graph this function. (b) What was the yearly continuous percent change in the number of HIV infections between 1985 and \(2010 ?\)

Short Answer

Expert verified
\( H(t) = 2.5 e^{\frac{\ln(13.6)}{25}t} \); annual growth rate is \( \frac{\ln(13.6)}{0.25} \%\

Step by step solution

01

Identify Initial and Final Population

The number of people infected with HIV in 1985 was 2.5 million, and in 2010 it was 34 million. Convert these into values for the function, where initial population \( H_0 = 2.5 \) million and final population \( H(t) = 34 \) million.
02

Determine Time Elapsed

Calculate the time elapsed from 1985 to 2010, which is \( t = 2010 - 1985 = 25 \) years.
03

Use Exponential Growth Formula

The formula for exponential growth is \( H(t) = H_0 e^{kt} \) where \( H(t) = 34 \), \( H_0 = 2.5 \), and \( t = 25 \). Substitute these values into the equation to find \( k \).
04

Solve for Growth Constant \( k \)

Substitute the values into the equation: \( 34 = 2.5 e^{25k} \). Divide both sides by 2.5: \( e^{25k} = \frac{34}{2.5} \). Take the natural logarithm of both sides: \( 25k = \ln(13.6) \). Solve for \( k \): \( k = \frac{\ln(13.6)}{25} \).
05

Exponential Growth Function

Substitute \( H_0 \) and \( k \) back into the function: \( H(t) = 2.5 e^{kt} \). With \( k \) calculated, rewrite the function as \( H(t) = 2.5 e^{\frac{\ln(13.6)}{25}t} \).
06

Interpret \( k \) as Yearly Percent Change

The continuous growth rate \( k \) represents the exponential growth rate. To express this as a yearly percent change, calculate \( 100k \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

HIV Infections Modeling
Modeling the growth of HIV infections over time is a valuable tool in understanding the spread of the disease. In the context of HIV, the model helps researchers and public health officials predict future cases and evaluate the effectiveness of interventions. Here, we look at the period from 1985 to 2010, where the number of infections grew from 2.5 million to 34 million, following an exponential growth pattern.

In exponential growth, the population grows by a constant percentage rate over equal time intervals, not a constant amount. This is characteristic of many biological phenomena, such as the spread of viruses like HIV. The general formula for exponential growth is given by:

\[ H(t) = H_0 e^{kt} \]

where:
  • \( H(t) \) is the number of HIV infections at time \( t \).
  • \( H_0 \) is the initial number of infections.
  • \( e \) is the base of natural logarithms, approximately equal to 2.71828.
  • \( k \) is the continuous growth rate of the infections.


This formula simulates how the infection spreads over time, accounting for the natural acceleration of contagion.
Continuous Growth Rate
The concept of continuous growth rate, denoted by \( k \), is crucial in understanding how populations, like those living with HIV, expand exponentially over time. It represents the rate at which the population grows continuously, instead of in discrete intervals. In our exercise, determining \( k \) aids in calculating and predicting the increase in infections.

To find \( k \), we utilize the natural logarithm, which helps transform the exponential equation into a linear one, making it easier to solve. From the exponential growth formula:

\[ 34 = 2.5 e^{25k} \]

First, divide both sides by 2.5 to isolate the exponential term:
  • \( e^{25k} = \frac{34}{2.5} \)


Next, take the natural logarithm of both sides to solve for the exponent:
  • \( 25k = \ln(13.6) \)


Finally, solve for \( k \) by dividing by 25:
  • \( k = \frac{\ln(13.6)}{25} \)


This \( k \) value is then interpreted as the yearly continuous percent change, offering insight into the rate of spread of the infection. Multiplying \( k \) by 100 will give the percentage growth rate per year.
Natural Logarithm
The natural logarithm, denoted by \( \ln \), is a powerful tool in mathematics and is particularly useful for solving problems involving exponential growth. In this context, it helps transform complex exponential equations into manageable linear forms. The natural logarithm has a base of \( e \), where \( e \approx 2.71828 \), often called Euler's number.

In the process of modeling HIV infection growth, the natural logarithm is essential for determining the continuous growth rate \( k \). By rewriting the equation:

\[ 25k = \ln(13.6) \]

we utilize the \( \ln \) function to solve for \( k \). What makes the natural logarithm particularly useful is how it converts multiplicative relationships into additive ones. This transformation simplifies computations and is a common method in calculus and exponential growth modeling.

Using the natural logarithm also means that we can backtrack this transformation to return to an exponent-based equation. It’s this property that makes \( \ln \) indispensable in breaking down and solving exponential growth problems, like forecasting the spread of HIV.

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