/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Simplify the quantities in Probl... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the quantities in Problems \(16-19\) using \(m(z)=z^{2}\) $$m(z+h)-m(z-h)$$

Short Answer

Expert verified
The simplified expression is \(4zh\).

Step by step solution

01

Understanding the Function

The given function is \( m(z) = z^2 \). We need to find the difference \( m(z+h) - m(z-h) \). This means we need to substitute \( z+h \) and \( z-h \) into the function \( m(z) \), which is \( z^2 \).
02

Substituting and Expanding

Substitute \( z+h \) into the function: \( m(z+h) = (z+h)^2 = z^2 + 2zh + h^2 \). Now, substitute \( z-h \) into the function: \( m(z-h) = (z-h)^2 = z^2 - 2zh + h^2 \).
03

Finding the Difference

Now compute the difference: \( m(z+h) - m(z-h) = (z^2 + 2zh + h^2) - (z^2 - 2zh + h^2) \). Simplify this expression by combining like terms.
04

Simplifying the Expression

In the difference \((z^2 + 2zh + h^2) - (z^2 - 2zh + h^2)\), the \(z^2\) terms and \(h^2\) terms cancel each other out. This leaves: \( 2zh + 2zh = 4zh \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Expansion
When dealing with function expansion, we explore how functions change when their inputs are varied. This process involves substituting the input variables with expressions that include additional terms. For the given function, \( m(z) = z^2 \), we expand by substituting inputs. For instance:
  • Substitute \( z+h \): \( m(z+h) = (z+h)^2 \)
  • Substitute \( z-h \): \( m(z-h) = (z-h)^2 \)
This substitution leads to the expansion of the function into their algebraic expressions. The aim is to find out how changes in input, like differences \( h \), influence the output. Understanding this concept helps in exploring function behaviors, crucial in fields like calculus where derivatives, which measure such changes, play a vital role.
Function expansion allows us to analyze the underlying algebraic properties of a function when subjected to different input alterations.
Algebraic Expression Simplification
Simplifying algebraic expressions involves condensing complex expressions into simpler forms without changing their values. This process often includes combining like terms or reducing fractions. To understand the simplification process:
Consider the expression \((z^2 + 2zh + h^2) - (z^2 - 2zh + h^2)\) from the solution. By subtracting the second expression from the first, we encounter terms that naturally cancel out:
  • \(z^2\) terms cancel with \(z^2\)
  • Positive \(h^2\) cancels with negative \(h^2\)
This results in the simplification to \(4zh\).
The art of simplifying revolves around recognizing and eliminating terms that offset each other. Such simplifications help make calculations more manageable and reveal the essential parts of an expression.
Quadratic Functions
Quadratic functions are polynomial functions of degree two, which take the general form \(m(z) = az^2 + bz + c\). In our exercise, we specifically deal with the simplest form \(m(z) = z^2\), where \(a=1\), and both \(b\) and \(c\) are zero.These functions graph as parabolas, symmetrical around their vertex, and are fundamental in algebra. Quadratic functions are crucial for many applications:
  • In physics, they describe trajectories
  • In finance, they model certain economic behaviors
When we examine function expansions as seen by inputting \(m(z+h)\) and \(m(z-h)\), these inputs allow us to determine the function's behavior around a specific point. Understanding quadratics and their properties lays a foundation for exploring more advanced mathematics, including calculus and real-world problem solving.

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Most popular questions from this chapter

The Bay of Fundy in Canada has the largest tides in the world. The difference between low and high water levels is 15 meters (nearly 50 feet). At a particular point the depth of the water, \(y\) meters, is given as a function of time, \(t,\) in hours since midnight by $$y=D+A \cos (B(t-C))$$ (a) What is the physical meaning of \(D ?\) (b) What is the value of \(A ?\) (c) What is the value of \(B ?\) Assume the time between successive high tides is 12.4 hours. (d) What is the physical meaning of \(C ?\)

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The demand curve for a product is given by \(q=\) \(120,000-500 p\) and the supply curve is given by \(q=\) \(1000 p\) for \(0 \leq q \leq 120,000,\) where price is in dollars. (a) At a price of \(\$ 100,\) what quantity are consumers willing to buy and what quantity are producers willing to supply? Will the market push prices up or down? (b) Find the equilibrium price and quantity. Does your answer to part (a) support the observation that market forces tend to push prices closer to the equilibrium price?

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